A circle is inscribed in a regular hexagon of side 2 root 3 cm. Find (1) the circumference of the inscribed circle (2) the area of the inscribed circle

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Manoj Kumar Vishwakarma

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A regular hexagon can be viewed as 6 equilateral triangles put together. From the perimeter, you know the side length of these triangles. Then you know the altitude of these triangles. The Altitude is the radius of the inscribed circle. So, you know the area of the circle.
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C = 18.84. A = 28.26.
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Accounts & Finance Teacher

Radius= 3 cm. Circumference =18.84 cm. Area = 28.26 sq. cm.
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A regular hexagon can be viewed as 6 equilateral triangles put together. From the perimeter, you know the side length of these triangles. Then you know the altitude of these triangles. The Altitude is the radius of the inscribed circle. So, you know the area of the circle. 1) the circumference of the...
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A regular hexagon can be viewed as 6 equilateral triangles put together. From the perimeter, you know the side length of these triangles. Then you know the altitude of these triangles. The Altitude is the radius of the inscribed circle. So, you know the area of the circle. 1) the circumference of the inscribed circle is 18.84 cm (2) the area of the inscribed circle is 18.84 cm read less
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Specialization in Cost and Management Accounting

The hexagon is made up of six equilateral triangles. Radius of the circle is height (altitude ) of the triangle. Height of the equilateral triangle is S x Root3 / 2 Radius = 2 x root 3 x Root 3 /2 = 3 cm Area = 3 x 3 x 3.14 = 28.26 Circumference = 3 x 2 x 3.14 = 18.84
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132/7.
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12.57 root 3 cm.
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Circumference =12.57 root 3 cm and area is 37.7 cm square approx.
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C = 18.84 cm. Area = 28.26 sq. cm.
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Mathematics Tutor

Circumference = 18.84 cm Area = 28.86 cm square
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