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Kumar Jaydeep BTech Tuition trainer in Bangalore

Kumar Jaydeep

students 1 student
locationImg Tavarekere Main Road, Bangalore
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I had successfully conducted classes for some classes. I had qualified GATE twice. I have strong analytical and communication skills. I have good concept of electrical and electronics engineering. I was volunteer in Crack the Campus for pre final year student in my college.

Languages Spoken

English

Hindi

Education

VTU 2016

Master of Engineering - Master of Technology (M.E./M.Tech.)

Address

Tavarekere Main Road, Bangalore, India - 560029

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Teaches

BTech Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

BTech Electrical & Electronics subjects

Renewable Energy, Switchgear And Protection, Neural Networks And Applications, Electrical Circuit Analysis, Power Electronics, Circuit Theory, Very Large Scale Integration (VLSI) Design, Control Systems

BTech Branch

BTech Electrical & Electronics

Type of class

Regular Classes

Class strength catered to

One on one/ Private Tutions, Group Classes

Taught in School or College

Yes

Quantitative Aptitude Coaching
1 Student

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Verbal Aptitude Coaching

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Class 11 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

1

Board

State, CBSE

Subjects taught

English, Chemistry, Mathematics, Physics

Taught in School or College

Yes

Class 12 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

1

Board

State, CBSE

Subjects taught

Physics, Mathematics, English, Chemistry

Taught in School or College

Yes

Class 6 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 6 Tuition

1

Board

State, CBSE

Subjects taught

English, Mathematics, Science

Taught in School or College

Yes

Class 7 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 7 Tuition

1

Board

State, CBSE

Subjects taught

English, Mathematics, Science

Taught in School or College

Yes

Class 8 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 8 Tuition

1

Board

State, CBSE

Subjects taught

Mathematics, Science, English

Taught in School or College

Yes

Class 9 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

1

Board

State, CBSE

Subjects taught

English, Science, Mathematics

Taught in School or College

Yes

Class 10 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

1

Board

State, CBSE

Subjects taught

English, Mathematics, Science

Taught in School or College

Yes

Reviews

No Reviews yet!

Answers by Kumar Jaydeep

Answered on 26/09/2018 Learn CBSE - Class 11/Physics

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F=ma 50= 20 x a a = 2.5m/s^2 v = u+at Here is a is -ve to stop 0 = 15 - 2.5xt 2.5t = 15 t = 6 So, it will take 6 seconds the body to stop
Answer Answers 3 Comments Comments
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Answered on 15/07/2018

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Btech CSE
Answer Answers 10 Comments Comments
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Answered on 15/07/2018

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Elitmus
Answer Answers 6 Comments Comments
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Answered on 19/09/2017

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1952
Answer Answers 2 Comments Comments
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Answered on 19/09/2017

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The series sum is 4590 and when divided by 1010 leaves remainder 550
Answer Answers 1 Comments Comments
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Teaches

BTech Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

BTech Electrical & Electronics subjects

Renewable Energy, Switchgear And Protection, Neural Networks And Applications, Electrical Circuit Analysis, Power Electronics, Circuit Theory, Very Large Scale Integration (VLSI) Design, Control Systems

BTech Branch

BTech Electrical & Electronics

Type of class

Regular Classes

Class strength catered to

One on one/ Private Tutions, Group Classes

Taught in School or College

Yes

Quantitative Aptitude Coaching
1 Student

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Verbal Aptitude Coaching

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Class 11 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

1

Board

State, CBSE

Subjects taught

English, Chemistry, Mathematics, Physics

Taught in School or College

Yes

Class 12 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

1

Board

State, CBSE

Subjects taught

Physics, Mathematics, English, Chemistry

Taught in School or College

Yes

Class 6 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 6 Tuition

1

Board

State, CBSE

Subjects taught

English, Mathematics, Science

Taught in School or College

Yes

Class 7 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 7 Tuition

1

Board

State, CBSE

Subjects taught

English, Mathematics, Science

Taught in School or College

Yes

Class 8 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 8 Tuition

1

Board

State, CBSE

Subjects taught

Mathematics, Science, English

Taught in School or College

Yes

Class 9 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

1

Board

State, CBSE

Subjects taught

English, Science, Mathematics

Taught in School or College

Yes

Class 10 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

1

Board

State, CBSE

Subjects taught

English, Mathematics, Science

Taught in School or College

Yes

No Reviews yet!

Answers by Kumar Jaydeep

Answered on 26/09/2018 Learn CBSE - Class 11/Physics

Ask a Question Ask a Question

Post a Lesson Post a Lesson

F=ma 50= 20 x a a = 2.5m/s^2 v = u+at Here is a is -ve to stop 0 = 15 - 2.5xt 2.5t = 15 t = 6 So, it will take 6 seconds the body to stop
Answer Answers 3 Comments Comments
Dislike Bookmark

Answered on 15/07/2018

Ask a Question Ask a Question

Post a Lesson Post a Lesson

Btech CSE
Answer Answers 10 Comments Comments
Dislike Bookmark

Answered on 15/07/2018

Ask a Question Ask a Question

Post a Lesson Post a Lesson

Elitmus
Answer Answers 6 Comments Comments
Dislike Bookmark

Answered on 19/09/2017

Ask a Question Ask a Question

Post a Lesson Post a Lesson

1952
Answer Answers 2 Comments Comments
Dislike Bookmark

Answered on 19/09/2017

Ask a Question Ask a Question

Post a Lesson Post a Lesson

The series sum is 4590 and when divided by 1010 leaves remainder 550
Answer Answers 1 Comments Comments
Dislike Bookmark
x

Ask a Question

Please enter your Question

Please select a Tag

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