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Apeksha Kawari trainer in Bangalore

Apeksha Kawari

locationImg Jayanagar 5th Block, Bangalore
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Tutor

* Experience of working as mathematics teacher for high school in an e-techno school.
* Experience in mathematics content development and delivering online/offline classes.
* Worked as mathematics faculty in BASE educational services.

Languages Spoken

Kannada Mother Tongue (Native)

Hindi Proficient

English Proficient

Education

Mangalore university 2015

Master of Science (M.Sc.)

Address

Jayanagar 5th Block, Bangalore, India - 560041

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Answers by Apeksha Kawari

Answered on 07/08/2019

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2(1) -3(-2) =2+6=8 So, (1, -2) is a solution of 2x-3y=8.
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Answered on 23/06/2019 Learn CBSE - Class 10/Mathematics/UNIT IV: Geometry/Triangles/NCERT Solutions/Exercise 6.6

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AC²=AD²+DC² =AD²+(BC-BD) ² =AD²+BD²+BC²-2BD.BC =AB²+BC²-2BD.BC
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Answered on 23/06/2019 Learn CBSE - Class 10/Mathematics/UNIT IV: Geometry/Triangles/NCERT Solutions/Exercise 6.6

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AC²=AD²+DC² =AD²+(DB+BC) ² =AD²+DB²+BC²+2DB.BC =AB²+BC²+2DB.BC
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Answered on 22/06/2019

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X³+y³+z³=(x²+y²+z²-xy-yz-zx) (x+y+z) Since x²+y²+z²=xy+yz+zx, X³+y³+z³=0
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Answers by Apeksha Kawari

Answered on 07/08/2019

Ask a Question

Post a Lesson

2(1) -3(-2) =2+6=8 So, (1, -2) is a solution of 2x-3y=8.
Answers 294 Comments
Dislike Bookmark

Answered on 23/06/2019 Learn CBSE - Class 10/Mathematics/UNIT IV: Geometry/Triangles/NCERT Solutions/Exercise 6.6

Ask a Question

Post a Lesson

AC²=AD²+DC² =AD²+(BC-BD) ² =AD²+BD²+BC²-2BD.BC =AB²+BC²-2BD.BC
Answers 4 Comments
Dislike Bookmark

Answered on 23/06/2019 Learn CBSE - Class 10/Mathematics/UNIT IV: Geometry/Triangles/NCERT Solutions/Exercise 6.6

Ask a Question

Post a Lesson

AC²=AD²+DC² =AD²+(DB+BC) ² =AD²+DB²+BC²+2DB.BC =AB²+BC²+2DB.BC
Answers 3 Comments
Dislike Bookmark

Answered on 22/06/2019

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X³+y³+z³=(x²+y²+z²-xy-yz-zx) (x+y+z) Since x²+y²+z²=xy+yz+zx, X³+y³+z³=0
Answers 278 Comments
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