Azimabad, Balasore, India - 756001.
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Hindi Proficient
English Proficient
National Institute of Technology Rourkela 2018
Bachelor of Technology (B.Tech.)
SWARNA NIWAS,ISAN NAGAR
CENTRAL SCHOOL SQUARE
Azimabad, Balasore, India - 756001
Landmark: Gautam Medical Store
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1 Student Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
2
Board
ICSE, State, CBSE
CBSE Subjects taught
Mathematics, Science
ICSE Subjects taught
Physics, Mathematics, Chemistry
Taught in School or College
No
State Syllabus Subjects taught
Mathematics, Science
1 Student Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
2
Board
CBSE, ISC/ICSE, State
ISC/ICSE Subjects taught
Physics, Mathematics, Chemistry
CBSE Subjects taught
Physics, Chemistry, Mathematics
Taught in School or College
No
State Syllabus Subjects taught
Physics, Mathematics, Chemistry, Electronics
Teaching Experience in detail in Class 11 Tuition
I have done single tuition to class 11 student in subjects of Mathematics , Physics and Chemistry. I have also done group tuition and taught in coaching centers. I have good experience in teaching class 11 students
1 Student Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
2
Board
CBSE, ISC/ICSE, State
ISC/ICSE Subjects taught
Physics, Mathematics, Chemistry
CBSE Subjects taught
Physics, Chemistry, Mathematics
Taught in School or College
No
State Syllabus Subjects taught
Physics, Mathematics, Chemistry, Electronics
Teaching Experience in detail in Class 12 Tuition
I have given single tuition to class 12 students in subjects of mathematics, physics and chemistry. I have also taught in coaching centers as well.
1. Which school boards of Class 10 do you teach for?
ICSE, State and CBSE
2. Do you have any prior teaching experience?
No
3. Which classes do you teach?
I teach Class 10 Tuition, Class 11 Tuition and Class 12 Tuition Classes.
4. Do you provide a demo class?
Yes, I provide a free demo class.
5. How many years of experience do you have?
I have been teaching for 2 years.
Answered on 22/06/2019 Learn Tuition
We know the identity x³+y³+z³-3xyz=(x+y+z)(x²+y²+z²-xy-yz-zx).
So if x²+y²+z²=xy+yz+zx
=>x²+y²+z²-xy-yz-zx=0
=>(x+y+z)(x²+y²+z²-xy-yz-zx)=0
=>x³+y³+z³-3xyz=0
=>x³+y³+z³=3xyz
1 Student Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
2
Board
ICSE, State, CBSE
CBSE Subjects taught
Mathematics, Science
ICSE Subjects taught
Physics, Mathematics, Chemistry
Taught in School or College
No
State Syllabus Subjects taught
Mathematics, Science
1 Student Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
2
Board
CBSE, ISC/ICSE, State
ISC/ICSE Subjects taught
Physics, Mathematics, Chemistry
CBSE Subjects taught
Physics, Chemistry, Mathematics
Taught in School or College
No
State Syllabus Subjects taught
Physics, Mathematics, Chemistry, Electronics
Teaching Experience in detail in Class 11 Tuition
I have done single tuition to class 11 student in subjects of Mathematics , Physics and Chemistry. I have also done group tuition and taught in coaching centers. I have good experience in teaching class 11 students
1 Student Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
2
Board
CBSE, ISC/ICSE, State
ISC/ICSE Subjects taught
Physics, Mathematics, Chemistry
CBSE Subjects taught
Physics, Chemistry, Mathematics
Taught in School or College
No
State Syllabus Subjects taught
Physics, Mathematics, Chemistry, Electronics
Teaching Experience in detail in Class 12 Tuition
I have given single tuition to class 12 students in subjects of mathematics, physics and chemistry. I have also taught in coaching centers as well.
Answered on 22/06/2019 Learn Tuition
We know the identity x³+y³+z³-3xyz=(x+y+z)(x²+y²+z²-xy-yz-zx).
So if x²+y²+z²=xy+yz+zx
=>x²+y²+z²-xy-yz-zx=0
=>(x+y+z)(x²+y²+z²-xy-yz-zx)=0
=>x³+y³+z³-3xyz=0
=>x³+y³+z³=3xyz
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