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Anand Joshi

Basaveshwara Nagar, Bangalore, India - 560079

Anand Joshi Engineering Diploma Tuition trainer in Bangalore

Anand Joshi

Civil Engineering and Languages Subject tutor

Basaveshwara Nagar, Bangalore, India - 560079.

1 Student taught

Referral Discount: Get ₹ 500 off when you make a payment to start classes. Get started by Booking a Demo.

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Overview

In depth experience in Civil engineering Subjects. Friendly approach so that you can learn and understand easily without any problems
Help in solving Previous exam papers so that you can gain confidence and use time precociously.

Languages Spoken

Kannada

Hindi

Marathi

English

Education

VTU 2005

Bachelor of Engineering (B.E.)

Address

Basaveshwara Nagar, Bangalore, India - 560079

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Engineering Diploma Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Engineering Diploma Tuition

5

Engineering Diploma Branch

Civil Engineering Diploma

Taught in School or College

No

Reviews

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No Reviews yet! Be the first one to Review

FAQs

1. Which Engineering Diploma branches do you tutor for?

Civil Engineering Diploma

2. Do you have any prior teaching experience?

No

3. Which classes do you teach?

I teach BTech Tuition, Class 10 Tuition, Class 9 Tuition, Class VI-VIII Tuition, Engineering Diploma Tuition, Kannada Language and Spoken English Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 5 years.

Answers by Anand Joshi (52)

Answered on 12/01/2015 Tuition/Class VI-VIII Tuition

The ratio of the density of a substance to the density of a standard, usually water for a liquid or solid, and air for a gas. (chemistry)
Answers 21 Comments
Dislike Bookmark

Answered on 12/01/2015 Tuition/Class VI-VIII Tuition

You are right, that because of centripetal acceleration you will weigh a tiny amount less at the equator than at the poles. Try not to think of centripetal acceleration as a force though; what's really going on is that objects which are in motion like to go in a straight line and so it takes some force... ...more
You are right, that because of centripetal acceleration you will weigh a tiny amount less at the equator than at the poles. Try not to think of centripetal acceleration as a force though; what's really going on is that objects which are in motion like to go in a straight line and so it takes some force to make them go round in a circle. So some of the force of gravity is being used to make you go round in a circle at the equator (instead of flying off into space) while at the pole this is not needed. This means that the centripetal acceletation at the equator is about 0.03 m/s2 (metres per seconds squared). Compare this to the acceleration due to gravity which is about 10 m/s2 and you can see how tiny an effect this is - you would weigh about 0.3% less at the equator than at the poles!
Answers 53 Comments
Dislike Bookmark

Answered on 12/01/2015 Tuition/Class VI-VIII Tuition

As water is cooled down, however, the molecules have less energy and hydrogen bonding takes over. The molecules form a ordered crystal through hydrogen bonding that spaces the molecules farther apart than when they were in a liquid. This makes ice less dense than water allowing it to float.
Answers 19 Comments
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Engineering Diploma Tuition 3.5

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Engineering Diploma Tuition

5

Engineering Diploma Branch

Civil Engineering Diploma

Taught in School or College

No

BTech Tuition 3.5

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in BTech Tuition

5

BTech Branch

BTech Civil Engineering

Taught in School or College

No

Kannada Language classes 3.5

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Kannada Language classes

4

Demo Class Provided

Yes

Profession

Working Professional

I cater to following requirements

Wanting to learn it as a language, School Curriculum

Awards and Recognition

No

Mother Tongue

Yes

Class 9 Tuition 3.4

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

5

Board

CBSE, State

CBSE Subjects taught

Science, Marathi, English, Hindi, Kannada

Taught in School or College

No

State Syllabus Subjects taught

English, Kannada, Science, Hindi

Class 10 Tuition 3.4

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

5

Board

CBSE, State

CBSE Subjects taught

Science, Marathi, English, Hindi, Kannada

Taught in School or College

No

State Syllabus Subjects taught

English, Kannada, Science, Hindi

Spoken English classes 3.5

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Spoken English classes

4

Demo Class Provided

No

Profession

Working Professional

Lived or Worked in English Speaking Country

No

Awards and Recognition

No

Curriculum Expertise

State

Citizen of English Speaking Country

No

Certification

None

Teaching at

Home

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Answers by Anand Joshi (52)

Answered on 12/01/2015 Tuition/Class VI-VIII Tuition

The ratio of the density of a substance to the density of a standard, usually water for a liquid or solid, and air for a gas. (chemistry)
Answers 21 Comments
Dislike Bookmark

Answered on 12/01/2015 Tuition/Class VI-VIII Tuition

You are right, that because of centripetal acceleration you will weigh a tiny amount less at the equator than at the poles. Try not to think of centripetal acceleration as a force though; what's really going on is that objects which are in motion like to go in a straight line and so it takes some force... ...more
You are right, that because of centripetal acceleration you will weigh a tiny amount less at the equator than at the poles. Try not to think of centripetal acceleration as a force though; what's really going on is that objects which are in motion like to go in a straight line and so it takes some force to make them go round in a circle. So some of the force of gravity is being used to make you go round in a circle at the equator (instead of flying off into space) while at the pole this is not needed. This means that the centripetal acceletation at the equator is about 0.03 m/s2 (metres per seconds squared). Compare this to the acceleration due to gravity which is about 10 m/s2 and you can see how tiny an effect this is - you would weigh about 0.3% less at the equator than at the poles!
Answers 53 Comments
Dislike Bookmark

Answered on 12/01/2015 Tuition/Class VI-VIII Tuition

As water is cooled down, however, the molecules have less energy and hydrogen bonding takes over. The molecules form a ordered crystal through hydrogen bonding that spaces the molecules farther apart than when they were in a liquid. This makes ice less dense than water allowing it to float.
Answers 19 Comments
Dislike Bookmark

Contact

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Anand Joshi describes himself as Civil Engineering and Languages Subject tutor. He conducts classes in BTech Tuition, Class 10 Tuition and Class 9 Tuition. Anand is located in Basaveshwara Nagar, Bangalore. Anand takes Regular Classes- at his Home. He has 5 years of teaching experience . Anand has completed Bachelor of Engineering (B.E.) from VTU in 2005. HeĀ is well versed in Kannada, Hindi, Marathi and English.

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