Madhav Kishore photo

Madhav Kishore

Tutor

Sama, Vadodara, India- 390008.

UrbanPro students 2 Students (2 from UrbanPro)

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Details verified of Madhav Kishore

Identity

Education

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Identity is verified based on matching the details uploaded by the Tutor with government databases.

Overview

I am a Mechanical engineer and take classes for Physics, Chemistry & Mathematics.

Physics up to IIT JEE (Main and Advance) Level and Mathematics and Chemistry up to IIT JEE MAIN, PUC (10+2).

Having an experience of more than 7 years in one on one class. I take class for students of XI, XII (CBSE AND STATE BOARD) and Engineering aspirants (IIT JEE-Main and Advance).
I take class of Mathematics for CAT or Other MBA Entrance Examinations.

I have Qualified GATE (Conducted by IIT for M.Tech programs) in 2014.

I had qualified AIEEE (All India Engineering Entrance Examination) and joined Mechanical Engineering in 2005.

Demo Class

Yes, not charged

Class Availability

ScheduleDays

Before 9am
Monday Tuesday Wednesday Thursday Friday Saturday Sunday
9am-Noon
Monday Tuesday Wednesday Thursday Friday Saturday Sunday
Noon-3pm
Monday Tuesday Wednesday Thursday Friday Saturday Sunday
3pm-6pm
Monday Tuesday Wednesday Thursday Friday Saturday Sunday
After 6pm
Monday Tuesday Wednesday Thursday Friday Saturday Sunday
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Languages Spoken

English, Hindi

Education

Bachelor of Technology (B.Tech.) from Dr. MGR University in 2009.

Address

Sama, Vadodara, India- 390008.

Gallery (2)

Physics

THERMODYNAMICS

Documents (1)

WHY TO JOIN ???????

Reviews (2)

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5.0 from 2 reviews

5.0/52
R

- by Ravinder Singh

attended Engineering Entrance Coaching

in Jan,2004

posted on 20 Jul, 2013

"Sh. Madhav Kishore Sir has provided coaching to me in physics & mathematics during my preparation for Engineering Entrance Examinations for various colleges. His guidance has played most vital role in my selection to Delhi College of Engineering. I pay my regards to Sh. Madhav Kishore Sir for his direction & contribution to me education."

A

- by Amit

attended Engineering Entrance Coaching

in Jan,2004

posted on 18 Jul, 2013

"Madhav sir is the main cause for my selection in DELHI COLLEGE OF ENGINEERING because he taught me mathematics and physics required for the engineering entrance exam .it is because of his efforts that i was able to take admission in one of the prestigious engineering college of India. Thanks sir "

Have you attended the class of Madhav? Write a Review

Answers by Madhav (1)

"Hi friends, please post the solution for following problem. If, (root X) + Y = 11 X + (root Y) =7 Then X , Y = ? " in   Tuition/Class XI-XII Tuition (PUC)

ANSWER- X=4, Y=9 SOLUTION, Let us assume that, X=a2 & Y=b2 Then eqn will be, a+b2 = 11, a=11-b2 & a2+b=7, put a=11-b2 in this equation Now the equation will be, b4-22b2+b+114=0 After solving this, (b-3)(b3+3b2-13b-38)=0 hence answer will be (b-3)=0, b=3 putting this in above equation, a=2 HenX=4 & Y=9, ANSWER

1
|
0

Madhav address

x
Classes are not available!

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5.0 from 2 reviews

R

- by Ravinder Singh

attended Engineering Entrance Coaching

in Jan,2004

posted on 20 Jul, 2013

"Sh. Madhav Kishore Sir has provided coaching to me in physics & mathematics during my preparation for Engineering Entrance Examinations for various colleges. His guidance has played most vital role in my selection to Delhi College of Engineering. I pay my regards to Sh. Madhav Kishore Sir for his direction & contribution to me education."

A

- by Amit

attended Engineering Entrance Coaching

in Jan,2004

posted on 18 Jul, 2013

"Madhav sir is the main cause for my selection in DELHI COLLEGE OF ENGINEERING because he taught me mathematics and physics required for the engineering entrance exam .it is because of his efforts that i was able to take admission in one of the prestigious engineering college of India. Thanks sir "

Have you attended the class of Madhav? Write a Review

"Hi friends, please post the solution for following problem. If, (root X) + Y = 11 X + (root Y) =7 Then X , Y = ? " in   Tuition/Class XI-XII Tuition (PUC)

ANSWER- X=4, Y=9 SOLUTION, Let us assume that, X=a2 & Y=b2 Then eqn will be, a+b2 = 11, a=11-b2 & a2+b=7, put a=11-b2 in this equation Now the equation will be, b4-22b2+b+114=0 After solving this, (b-3)(b3+3b2-13b-38)=0 hence answer will be (b-3)=0, b=3 putting this in above equation, a=2 HenX=4 & Y=9, ANSWER

1
|
0

Madhav Kishore describes himself as Tutor. Madhav is located in Sama, Vadodara. Madhav takes at students Home, Regular Classes- at his Home and Online Classes- via online medium. He has 5 years of teaching experience . Madhav has completed Bachelor of Technology (B.Tech.) from Dr. MGR University in 2009. HeĀ is well versed in English and Hindi. Madhav has got 2 reviews till now with 100% positive feedback.

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