Lesson Posted on 20 Aug Permutation and Combinations

Notes on Permutation,Combination

Raj Kumar

I am Six Sigma Black belt trained from American Society of Quality I am 2011 pass out in B.tech from...

A permutation is merely meaning the arrangement of things in how many ways the elements can be arranged permutation word comes from a Latin word which means to change thoroughly or exchange the things If we care about the Order arrangement, then it is a permutation. Picking a 1st,2nd and 3rd place... read more

A permutation is merely meaning the arrangement of things in how many ways the elements can be arranged

permutation word comes from a Latin word which means to change thoroughly or exchange the things

If we care about the Order arrangement, then it is a permutation.

Picking a 1st,2nd and 3rd place in the race is an example of permutation .because the order matters

The combination is merely meaning the selection of group

Combination word comes from a Latin word which means joins two by two

If we do not care about the order, so it is called the combination

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Comments Answered on 19/11/2016 CBSE/Class 12/Science/Mathematics Tuition/Class XI-XII Tuition (PUC) Permutation and Combinations

Eti G.

Math Magician

120

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Answers 3 Comments Answered on 28/11/2016 CBSE/Class 12/Science/Mathematics Tuition/Class XI-XII Tuition (PUC) Permutation and Combinations

How many words can be formed by using all letters of the word ‘BIHAR’?

Tapas Bhattacharya

Tutor

Here, all the letters are different and there are 5 letters. So, the number of words = 5! = 120.

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Answers 1 Comments Answered on 04/12/2016 CBSE/Class 12/Science/Mathematics Tuition/Class XI-XII Tuition (PUC) Permutation and Combinations

How many 3-digit numbers can be formed from the digits 2, 3, 5, 6, 7, 9 which are divisible by 5 and... read more

How many 3-digit numbers can be formed from the digits 2, 3, 5, 6, 7, 9 which are divisible by 5 and none of the digits is repeated? read less

Tapas Bhattacharya

Tutor

For all the numbers the last digit must be 5. So, the 1st, and the 2nd places are occupied by 2, 3, 6, 7, and 9 without any repetition. So, this can be done by taking 2 digits at a time from the above 6 digits. The number of ways this can be done is 6P2 = !6/!(6-2) = !6/!4 = (6x5x4x3x2x1)/(4x3x2x1) =... read more

For all the numbers the last digit must be 5. So, the 1st, and the 2nd places are occupied by 2, 3, 6, 7, and 9 without any repetition. So, this can be done by taking 2 digits at a time from the above 6 digits. The number of ways this can be done is 6P2 = !6/!(6-2) = !6/!4 = (6x5x4x3x2x1)/(4x3x2x1) = 6x5 = 30. (Answer) read less

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Answers 1 Comments Answered on 01/12/2016 CBSE/Class 12/Science/Mathematics Tuition/Class XI-XII Tuition (PUC) Permutation and Combinations

What is value of (100) P (2)?

Sreedevi A.

Teacher

(100)! / 98!

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Answers 1 Comments Answered on 01/12/2016 CBSE/Class 12/Science/Mathematics Tuition/Class XI-XII Tuition (PUC) Permutation and Combinations

Find out the number of ways in which 6 rings of different types can be worn in 3 fingers?

Anil Kumar

CAT Coaching Classes

Each ring has a choice of 3 fingers, so no of ways =3^6. There are no restrictions.

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Answers 2 Comments Answered on 02/12/2016 CBSE/Class 12/Science/Mathematics Tuition/Class XI-XII Tuition (PUC) Permutation and Combinations

What is the difference between permutation and combination?

Sreedevi A.

Teacher

Permutation involves selection and arrangement where as Combination involves only selection.

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Answers 1 Comments Answered on 03/12/2016 CBSE/Class 12/Science/Mathematics Tuition/Class XI-XII Tuition (PUC) Permutation and Combinations

Solve: (9) P (3)?

Sarvajeet Kumar

An Experienced Trainer

504.

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Answers 1 Comments Asked on 05/11/2016 CBSE/Class 12/Science/Mathematics Tuition/Class XI-XII Tuition (PUC) Permutation and Combinations

Out of 7 consonants and 4 vowels, how many words of 3 consonants and 2 vowels can be formed?

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Asked on 05/11/2016 CBSE/Class 12/Science/Mathematics Tuition/Class XI-XII Tuition (PUC) Permutation and Combinations

In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they... read more

In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be there? read less

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