As a tutor you can connect with more than a million students and grow your network.

Ask a Question

Feed

Answered on 19/11/2016 Tuition/Class XI-XII Tuition (PUC) Tuition/Class XI-XII Tuition (PUC)/Mathematics Permutation and Combinations

Solve: 5! ?

Eti G.

Math Magician

120

Like 0

Answers 3 Comments Answered on 28/11/2016 Tuition/Class XI-XII Tuition (PUC) Tuition/Class XI-XII Tuition (PUC)/Mathematics Permutation and Combinations

How many words can be formed by using all letters of the word ?BIHAR??

Tapas Bhattacharya

Tutor

Here, all the letters are different and there are 5 letters. So, the number of words = 5! = 120.

Like 1

Answers 1 Comments Answered on 04/12/2016 Tuition/Class XI-XII Tuition (PUC) Tuition/Class XI-XII Tuition (PUC)/Mathematics Permutation and Combinations

How many 3-digit numbers can be formed from the digits 2, 3, 5, 6, 7, 9 which are divisible by 5 and... read more

How many 3-digit numbers can be formed from the digits 2, 3, 5, 6, 7, 9 which are divisible by 5 and none of the digits is repeated? read less

Tapas Bhattacharya

Tutor

For all the numbers the last digit must be 5. So, the 1st, and the 2nd places are occupied by 2, 3, 6, 7, and 9 without any repetition. So, this can be done by taking 2 digits at a time from the above 6 digits. The number of ways this can be done is 6P2 = !6/!(6-2) = !6/!4 = (6x5x4x3x2x1)/(4x3x2x1) =... read more

For all the numbers the last digit must be 5. So, the 1st, and the 2nd places are occupied by 2, 3, 6, 7, and 9 without any repetition. So, this can be done by taking 2 digits at a time from the above 6 digits. The number of ways this can be done is 6P2 = !6/!(6-2) = !6/!4 = (6x5x4x3x2x1)/(4x3x2x1) = 6x5 = 30. (Answer) read less

Like 0

Answers 1 Comments Answered on 01/12/2016 Tuition/Class XI-XII Tuition (PUC) Tuition/Class XI-XII Tuition (PUC)/Mathematics Permutation and Combinations

What is value of (100) P (2)?

Sreedevi A.

Teacher

(100)! / 98!

Like 0

Answers 1 Comments Answered on 01/12/2016 Tuition/Class XI-XII Tuition (PUC) Tuition/Class XI-XII Tuition (PUC)/Mathematics Permutation and Combinations

Find out the number of ways in which 6 rings of different types can be worn in 3 fingers?

Anil Kumar

CAT Coaching Classes

Each ring has a choice of 3 fingers, so no of ways =3^6. There are no restrictions.

Like 0

Answers 2 Comments Answered on 02/12/2016 Tuition/Class XI-XII Tuition (PUC) Tuition/Class XI-XII Tuition (PUC)/Mathematics Permutation and Combinations

What is the difference between permutation and combination?

Sreedevi A.

Teacher

Permutation involves selection and arrangement where as Combination involves only selection.

Like 0

Answers 1 Comments Answered on 03/12/2016 Tuition/Class XI-XII Tuition (PUC) Tuition/Class XI-XII Tuition (PUC)/Mathematics Permutation and Combinations

Solve: (9) P (3)?

Sarvajeet Kumar

An Experienced Trainer

504.

Like 0

Answers 1 Comments Asked on 05/11/2016 Tuition/Class XI-XII Tuition (PUC) Tuition/Class XI-XII Tuition (PUC)/Mathematics Permutation and Combinations

Out of 7 consonants and 4 vowels, how many words of 3 consonants and 2 vowels can be formed?

Answer

Asked on 05/11/2016 Tuition/Class XI-XII Tuition (PUC) Tuition/Class XI-XII Tuition (PUC)/Mathematics Permutation and Combinations

In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they... read more

In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be there? read less

Answer

Asked on 05/11/2016 Tuition/Class XI-XII Tuition (PUC) Tuition/Class XI-XII Tuition (PUC)/Mathematics Permutation and Combinations

From a group of 7 men and 6 women, five persons are to be selected to form a committee so that at least... read more

From a group of 7 men and 6 women, five persons are to be selected to form a committee so that at least 3 men are there in the committee. In how many ways can it be done? read less

Answer

UrbanPro.com helps you to connect with the best in India. Post Your Requirement today and get connected.

x

Ask a Question