UrbanPro
true

CBSE Updates

Ask a Question

Post a Lesson

All

All

Lessons

Discussion

Answered 6 days ago IIT JEE/IIT - JEE Mains/Chemistry/Organic Chemistry/Chemistry in Everyday Life CBSE/Class 11/Science/Chemistry CBSE/Class 11/Science/Chemistry/Organic Chemistry – Some Basic Principles and Techniques

Kavitha Nagalapur

Chemistry teacher with 6 years of competitive exams training for class 11, 12th and M.Sc.(NET)

Cations are positively charged ions formed due to the loss of electrons from an atom. Kernels are not charged atoms. They are simply atoms with inner shell electrons and a nucleus.
Answers 10 Comments
Dislike Bookmark

Answered on 13 Jul CBSE/Class 11/English/English - Hornbill - Reading Skills

What is the difference between a composition and a paragraph?

P V Rao

I am P V Rao, an experienced educator and teacher with more than 30 years of teaching experience

Several words make up a sentence; a group of sentences make up a paragraph. Several paragraphs make up a composition.
Answers 1 Comments
Dislike Bookmark

Lesson Posted on 06 Jul IT Courses/Programming Languages/Python/Python 3.7 IT Courses/Programming Languages/Python/Python 3.8 CBSE/Class 12

Steps of Execution of a Python Program

Manoj Singh

I am a experienced, passionate, dedicated teacher and tutor with over 12 years of experience in teaching,...

When we compile a Python program, the python compiler converts the Python source code into another code called byte code. Byte code is a fixed set of instructions that represent different types of operations. This code can run on any Operating System and hardware. So mainly, byte code instructions are... read more

When we compile a Python program, the python compiler converts the Python source code into another code called byte code. Byte code is a fixed set of instructions that represent different types of operations. This code can run on any Operating System and hardware. So mainly, byte code instructions are platform-independent.

The size of each byte code instruction is one byte, and thats why they are called the name byte code.

Now we need to convert the byte code to machine understandable code, which comprises 0s and 1s. This machine understandable code is called machine code.

So Python uses an interpreter called PVM (Python Virtual Machine), which understands the byte code and converts it into machine code.

After that, these machine code instructions are executed by the processor and results are displayed.

(pic: Google)

                               See the source image

We can view the python byte code files (.pyc).

First, write a program in any text editor and save it with .py

now, compile the program using python compiler.

for example, if your file name is test.py, then use the following syntax

c:\> python test.py

To see the byte code instructions created by the python compiler before they are executed by the PVM, execute the following command.

c:\>python -m dis test.py

Here -m represents the module named dis. This module is also known as 'disassembler' that displays the byte code in the human-understandable format.

The above command will display the byte code of the test.pyc file creates during the compilation of the test.py file.

That is the way to view the byte code.

Thanks!

read less
Comments
Dislike Bookmark

Answered on 24 May CBSE/Class 12/Science/Physics/Unit 10-Communication Systems/COMMUNICATION SYSTEMS Language/Spoken English

Dr. Sandeep Kumar Sharma

Associate Professor with 20 years of teaching experience.

Read newspaper daily. Watch youtube videos on news clippings. Download a short 1-minute video. Write the text and try to speak in that manner. Record your voice and listen. Compare it with the newsreader and try to improve. Do a lot of reading. Make a friend with whom you talk in English. Read... read more
  • Read newspaper daily. 
  • Watch youtube videos on news clippings. 
  • Download a short 1-minute video. 
  • Write the text and try to speak in that manner. 
  • Record your voice and listen. 
  • Compare it with the newsreader and try to improve. Do a lot of reading. 
  • Make a friend with whom you talk in English. 
  • Read one article daily for 10 to 15 minutes. 
  • Watch youtube for programmes like Toastmasters, Ted Talks.
  • Stand in front of the mirror and give a two-minute speech every day.

Follow these tips, and you will observe a significant improvement.

read less
Answers 139 Comments
Dislike Bookmark

Answered on 01 Jun CBSE/Class 10/Science

Asok Kumar P

20 years experience teaching Class 8 to 12 Physics,Chemistry and Mathematics and NEET/JEE/KEAM Coac

Hydrogen gas is obtained Fe+H2SO4-FeSO4+ H2
Answers 50 Comments
Dislike Bookmark

Answered on 03 May CBSE/Class 10/Science

Edukendra Classes

For the syllabus, please visit the Jagranjosh education column. The chapter I recommend to start with is SI units, introduction to scalar and vector quantities, periodic table concerning metals and non-metals, cell and life cycle, etc. These are some fundamental topics to make a conceptual base.
Answers 40 Comments
Dislike Bookmark

Lesson Posted on 09/04/2020 Tuition/BBA Tuition Tuition/BCom Tuition CBSE/Class 11/Commerce/Accountancy +2 Tuition/Class XI-XII Tuition (PUC)/Accounts CBSE/Class 11/Commerce/Accountancy/Unit 1-Financial Accounting(Part A)Theoretical Framework less

How to Prepare Final Accounts (Step by step procedure) for BBA/ Bcom/ BBM students

Madhura G.

With over more than ten years of experience as a tutor for accountancy, finance, Taxation, Costing and...

Dear Students, Final Accounts question is a very scoring question in the accountancy Paper and is also a compulsory question for most of the boards. So here is the list of simple steps to be follwed while solving a final Accounts sum: 1. Read the list of Trial Balance items and adjustments carefully 2.... read more

Dear Students,

Final Accounts question is a very scoring question in the accountancy Paper and is also a compulsory question for most of the boards.

So here is the list of simple steps  to be follwed while solving a final Accounts sum:

1. Read the list of Trial Balance items and adjustments carefully

2. Record all the debit items given in the Trial Balance on either expenses side of Trading-P&L Account or Asset Side of Balancesheet

3. Record all the credit items given in the Trial Balance on either Income side of Trading-P&L Account or Liabilities Side of Balancesheet

4. Remember to post all the trial balance items only once, but all the adjustments items twice (one debit effect and one credit effect)

5. Balance your trading-P&L a/c first and determine profit/loss

6. Add this profit obtained with the Capital, on the liabilities side of the balance sheet

7. Take the total of the balance sheet.

Remember every debit has a corresponding credit.

read less
Comments 1
Dislike Bookmark

Lesson Posted on 18/06/2017 CBSE/Class 10/Science Tuition/Class VI-VIII Tuition Tuition/Class IX-X Tuition +1 Tuition/Class VI-VIII Tuition/Science less

Numerical problems on force and pressure

Soumi Roy

I am an experienced, qualified tutor with over 8 years of experience in teaching maths and Science across...

Example 1: A force of 1200 N acts on the surface of area 10 cm2 normally. What would be the thrust and pressure on the surface?Given: Force F = 1200 N, Area A = 10 cm2 = 10 ×10-4 m2 = 10-3 m2Thrust = Normal pressure = F = 1200 NPressure P = F/A 1200N10−3m21200N10−3m2 ... read more

Example 1:

A force of 1200 N acts on the surface of area 10 cm2 normally. What would be the thrust and pressure on the surface?

Given:


Force F = 1200 N, Area A = 10 cm2 = 10 ×10-4 m2 = 10-3 m2

Thrust = Normal pressure = F = 1200 N

Pressure P = F/A 1200N103m21200N10−3m2
              
                      = 1.2 ×× 106 N/m2

Example 2:

The elephant weighs 20,000 N stands on one foot of area 1000 cm2. How much pressure would it exert on the ground?

Given:


Force applied by elephant F = 20,000 N, area A = 1000 cm2 = 1000/100×100m2 = 0.1 m2

The pressure is given by

Pressure P = F/A

      = 20,000N/0.1m2


        = 2,00,000 N/m2.

Example 3:

Calculate the pressure produced by a force of 800 N acting on an area of 2.0 m2.

Solution:

Pressure is defined as force per unit area or P = F / A
P = (800 N) / (2.0 m2
)
P = 400 N / m2
= 400 Pa

Example 4:

The pressure of a gas contained in a cylinder with a movable piston is 300 Pa. The area of the piston is 0.5 m2. Calculate the force that is exerted on the piston.

Solution

Pressure is defined as force per unit area or P = F / A
We multiply both sides of the equation by the area to solve for the force as
F = P A
F = (300 Pa) (0.5 m2
)
F = 150 (Pa) m2
= 150 (N / m2
) m2
F = 150 N

Example 5:

A swimming pool of width 9.0 m and length 24.0 m is filled with water to a depth of 3.0 m. Calculate pressure on the bottom of the pool due to the water.

Solution:

The pressure due to a column of fluid is calculated as the product of the height of the fluid times
the density of the fluid times the acceleration due to gravity. For water the density is d = 1000 kg /
m3
.
? P = d h g
? P = (1000 kg / m3
) (3.0 m) (9.8 m / s2
)
? P = 29400 kg m2 / m3
s2
To simplify the units we cancel one m term in the m2
term in the numerator and one m term in
the m3
term in the denominator to get
? P = 29400 kg m / s2
m2

We know that 1N = 1 kg m / s2
so we can write
? P = 29400 N / m2
= 29400 Pa

read less
Comments 62
Dislike Bookmark

About UrbanPro

UrbanPro.com helps you to connect with the best in India. Post Your Requirement today and get connected.

Overview

Questions 9.5 k

Lessons 1369

Total Shares  

+ Follow 344 Followers

Related Topics

Top Contributors

Connect with Expert Tutors & Institutes for CBSE

x

Ask a Question

Please enter your Question

Please select a Tag

X

Find Tutors, Trainers & Institutes near you

Post requirement and connect with the tutors in your locality

  • Post a learning requirement
  • Get customized responses
  • Compare and select the best

Want to learn something New?

Find best tutors, trainers & institutes near you on UrbanPro

Post your learning requirement

UrbanPro.com is India's largest network of most trusted tutors and institutes. Over 55 lakh students rely on UrbanPro.com, to fulfill their learning requirements across 1,000+ categories. Using UrbanPro.com, parents, and students can compare multiple Tutors and Institutes and choose the one that best suits their requirements. More than 7.5 lakh verified Tutors and Institutes are helping millions of students every day and growing their tutoring business on UrbanPro.com. Whether you are looking for a tutor to learn mathematics, a German language trainer to brush up your German language skills or an institute to upgrade your IT skills, we have got the best selection of Tutors and Training Institutes for you. Read more