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Find the best tutors and institutes for Class XI-XII Tuition (PUC)

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Asked on 29 Apr CBSE/Class 12/Science/Mathematics

Hi I am looking for a good maths academy in Chennai, most preferably triplicane area. Can you suggest... read more

Hi I am looking for a good maths academy in Chennai, most preferably triplicane area. Can you suggest me a good institution

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Asked on 15 Apr CBSE/Class 12/Science/Mathematics

Please send me in reply how to draw trigonometry table

Answer

Lesson Posted on 06 Apr CBSE/Class 12/Science/Mathematics

Rajan Mittal Classes

Mittal Classes started on 2010 , we have experience teachers. We provides IIT JEE Coaching classes , BTech Tuition .

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Comments Looking for Class XI-XII Tuition (PUC)

Find best Class XI-XII Tuition (PUC) in your locality on UrbanPro.

Lesson Posted on 08 Mar CBSE/Class 10/Mathematics CBSE/Class 12/Science/Mathematics

Honesty and Dedication helps in education and success in life.

Jagdish S.

Mathematics teaching for CBSE ICSE,PUC state CET,JEE IIT and Engineering maths ,CAT,MAT,International...

Honesty and Dedication helps in education and success in life. As per my 22 years of experience of teaching mathematics i would like to say to all student that we should be Honesty and Dedicated in study then we will be successful in life. If we earn money or marks by wrong way then we will not feel... read more

Honesty and Dedication helps in education and success in life.

As per my 22 years of experience of teaching mathematics i would like to say to all student that we should be Honesty and Dedicated in study then we will be successful in life. If we earn money or marks by wrong way then we will not feel happiness. Get less mark but with honesty that will make you feel happiness.

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Comments Answered on 24 Feb CBSE/Class 12/Science/Mathematics

Srinivas Rao

Math Guru

Super

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Answers 3 Comments Lesson Posted on 07 Feb CBSE/Class 12/Science/Mathematics

If A=(1+ 1/38)^38 And B=(1 + 1/37)^37 Then 1) A=B, 2) A>B, 3) A>4, 4) A** **

Sujoy D.

1. Strong concept building classes. 2. Weekly tests in weak areas for students to improve their confidence. 3....

Answer: Method 1: A = ^k B = ^(k - 1) Apply PMI now to get : A > B Method 2: Solution: (1+ 1/n)^n = e ~ 2.78xx.. as n tends to infinity. Now its an increasing function because just check for A = (1 +1/2)^2 and B= (1 +1)^1 ==> A= 9/4= 2.25 and B=2. So clearly A>B here. So, as the function... read more

Answer:

Method 1:

A = [(k + 1)/k ]^k

B = [(k/(k - 1)]^(k - 1)

Apply PMI now to get : A > B

Method 2:

Solution:

(1+ 1/n)^n = e ~ 2.78xx.. as n tends to infinity.

Now its an increasing function because just check for

A = (1 +1/2)^2 and B= (1 +1)^1 ==> A= 9/4= 2.25 and B=2. So clearly A>B here.

So, as the function is increasing so, it will also satisfy for our given A and B. i.e., A>B here.

f(x)= (1 + 1/x)^x is alwz an increasing function. and as it is increasing function so, if x> y then f(x) > f(y) alwz.

It also satisfies from here.

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Comments Lesson Posted on 07 Feb CBSE/Class 12/Science/Mathematics

What Is The Value Of f(1) + f(2) + f(3) + f(4) + f(5) + f(6)?

Sujoy D.

1. Strong concept building classes. 2. Weekly tests in weak areas for students to improve their confidence. 3....

Question: A function f(x) is defined as f(x) = f(x – 2) + x(x – 2) for all the integer values of ‘x’. Given that f(1) + f(6) = 0. What is the value of f(1) + f(2) + f(3) + f(4) + f(5) + f(6)? Answer: Method: f(x) = f(x – 2) + x(x – 2) f(1) + f(6) = 0 => f(6)... read more

Question:

A function f(x) is defined as f(x) = f(x – 2) + x(x – 2) for all the integer values of ‘x’. Given that f(1) + f(6) = 0. What is the value of f(1) + f(2) + f(3) + f(4) + f(5) + f(6)?

Answer:

Method:

f(x) = f(x – 2) + x(x – 2)

f(1) + f(6) = 0 => f(6) = -f(1)

f(2) = f(0)

f(3) = f(1) + 3

f(4) = f(2) + 8

f(5) = f(1) + 18

f(6) = f(4) + 24 = f(2) + 32

f(2) = -f1 - 32

f(4) = -f1 -24

f(1) + ... f(6) = -f1 -32 -f1 - 24 + f1 + 3 + f1 + 18

= -56 + 21 = -35.

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Comments Answered on 05/06/2017 CBSE/Class 12/Science/Mathematics Tuition/Class XI-XII Tuition (PUC)

Ca Prashanth Reddy

Tutor

S chand publications

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Answers 107 Comments Answered on 23/05/2017 CBSE/Class 12/Science/Mathematics Tuition/Class XI-XII Tuition (PUC)

Ca Prashanth Reddy

Tutor

You can start at 12th, but you must understand that this subject will require much more attention than the other subjects. Only understanding concept will not help, you will have to do lot of practice questions. You will need precise help and very good reference books. You also need to be ready to refer... read more

You can start at 12th, but you must understand that this subject will require much more attention than the other subjects. Only understanding concept will not help, you will have to do lot of practice questions. You will need precise help and very good reference books. You also need to be ready to refer back the earlier class maths book, if required. read less

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Answers 160 Comments Looking for Class XI-XII Tuition (PUC)

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Answered on 25 Feb CBSE/Class 12/Science/Mathematics Tuition/Class XI-XII Tuition (PUC)

Salman Ahmad Siddiqui

Tutor

7th term =40=a + 6d sum of 13 term =(13/2)(2a+12d)=13(a+6d)=13*40=520

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Answers 16 Comments UrbanPro.com helps you to connect with the best Class XI-XII Tuition (PUC) in India. Post Your Requirement today and get connected.

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