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Learn NCERT Exercise 6 with Free Lessons & Tips

Describe a method for refining nickel?

Nickel is refined by Mond’s process. In this process, nickel is heated in the presence of carbon monoxide to form nickel tetracarbonyl, which is a volatile complex.

Then, the obtained nickel tetracarbonyl is decomposed by subjecting it to a higher temperature (450 − 470 K) to obtain pure nickel metal.

Comments

Which method of refining will you suggest for an element in which impurities present have chemical properties close to the properties of that elements?

Zone refining is one of the methods of the refining of the ores. It is based on the principle that the impurities are more soluble in the melt of the metal than they are in the solid state of the metal. There is a circular mobile heater which is fixed at one end of the rod. The rod is made up of the impure metal. As the heater is moved forward, the impure metal melts in the part where the heater is temporarily placed. Thus, as the heater moves forward, the melt of the metal also moves forward, along with the heater, as the previous part of the metal condenses or solidifies as the heater moves away from it. Now, the impurities are not soluble in the solid part of the metal but instead, are soluble in the molten part of the metal. Thus the impurities keep on getting dissolved into the molten part of the metal and thus, as this melt keeps on moving forward as the adjacent part of the metal melts, the impurities also keep on moving forward. This process is repeated several times and thus eventually, the impurities get concentrated at one end of the rod. However, the process is repeated in the same direction so that the impurities get collected or concentrated in the same one end of the rod. Later, this part of the rod is cut off.

This method of refining is very useful for the removal of impurities from semi - conductors like Ge, Ga, Si, As, B, In, etc.. Also, it is useful for the refining of the metals of high purity.

Comments

Copper can be extracted by hydrometallurgy but not zinc. Explain?

The reduction potentials of zinc and iron are lower than that of copper. In hydrometallurgy, zinc and iron can be used to displace copper from their solution.

But to displace zinc, more reactive metals i.e., metals having lower reduction potentials than zinc such as Mg, Ca, K, etc. are required. But all these metals react with water with the evolution of H2 gas.

As a result, these metals cannot be used in hydrometallurgy to extract zinc.

Hence, copper can be extracted by hydrometallurgy but not zinc.

Comments

What is the role of depressant in froth floatation process?

In the froth floatation process, the role of the depressants is to separate two sulphide ores by selectively preventing one ore from forming froth. For example, to separate two sulphide ores (ZnS and Pbs), NaCN is used as a depressant which selectively allows PbS to come with froth, but prevents ZnS from coming to froth. This happens because NaCN reacts with ZnS to form Na2[Zn(CN)4].

Comments

Why is the extraction of copper from pyrites more difficult than that from its oxide ore through reduction?

The Gibbs free energy of formation (ΔfG) of Cu2S is less than that of and. Therefore, H2 and C cannot reduce Cu2S to Cu.

On the other hand, the Gibbs free energy of formation of is greater than that of. Hence, C can reduce Cu2O to Cu.

Hence, the extraction of copper from its pyrite ore is difficult than from its oxide ore through reduction.

Comments

Explain: (i) Zone refining (ii) Column chromatography.

(i) Zone refining:

This method is based on the principle that impurities are more soluble in the molten state of metal (the melt) than in the solid state. In the process of zone refining, a circular mobile heater is fixed at one end of a rod of impure metal. As the heater moves, the molten zone of the rod also moves with it. As a result, pure metal crystallizes out of the melt and the impurities pass onto the adjacent molten zone. This process is repeated several times, which leads to the segregation of impurities at one end of the rod. Then, the end with the impurities is cut off. Silicon, boron, gallium, indium etc. can be purified by this process.

(ii) Column chromatography:

Column chromatography is a technique used to separate different components of a mixture. It is a very useful technique used for the purification of elements available in minute quantities. It is also used to remove the impurities that are not very different in chemical properties from the element to be purified. Chromatography is based on the principle that different components of a mixture are differently adsorbed on an adsorbent. In chromatography, there are two phases: mobile phase and stationary phase. The stationary phase is immobile and immiscible. Al2O3column is usually used as the stationary phase in column chromatography. The mobile phase may be a gas, liquid, or supercritical fluid in which the sample extract is dissolved. Then, the mobile phase is forced to move through the stationary phase. The component that is more strongly adsorbed on the column takes a longer time to travel through it than the component that is weakly adsorbed. The adsorbed components are then removed (eluted) using a suitable solvent (eluant).

Comments

Out of C and CO, which is a better reducing agent at 673 K?

At 673 K, the value of is less than that of. Therefore, CO can be oxidised more easily to CO2 than C to CO. Hence, CO is a better reducing agent than C at 673 K.

Comments

Name the common elements present in the anode mud in electrolytic refining of copper. Why are they so present ?

In electrolytic refining of copper, the common elements present in anode mud are selenium, tellurium, silver, gold, platinum, and antimony.

These elements are very less reactive and are not affected during the purification process. Hence, they settle down below the anode as anode mud.

Comments

Write chemical reactions taking place in the extraction of zinc from zinc blende?

The different steps involved in the extraction of zinc from zinc blende (ZnS) are given below:

(i) Concentration of ore

First, the gangue from zinc blende is removed by the froth floatation method.

(ii) Conversion to oxide (Roasting)

Sulphide ore is converted into oxide by the process of roasting. In this process, ZnS is heated in a regular supply of air in a furnace at a temperature, which is below the melting point of Zn.

(iii) Extraction of zinc from zinc oxide (Reduction)

Zinc is extracted from zinc oxide by the process of reduction. The reduction of zinc oxide is carried out by mixing it with powdered coke and then, heating it at 673 K.

(iv) Electrolytic Refining

Zinc can be refined by the process of electrolytic refining. In this process, impure zinc is made the anode while a pure copper strip is made the cathode. The electrolyte used is an acidified solution of zinc sulphate (ZnSO4). Electrolysis results in the transfer of zinc in pure from the anode to the cathode.

Comments

State the role of silica in the metallurgy of copper?

During the roasting of pyrite ore, a mixture of FeO and Cu2O is obtained.

The role of silica in the metallurgy of copper is to remove the iron oxide obtained during the process of roasting as ‘slag’. If the sulphide ore of copper contains iron, then silica (SiO2) is added as flux before roasting. Then, FeO combines with silica to form iron silicate, FeSiO3 (slag).

Comments

How can you separate alumina from silica in bauxite ore associated with silica? Give equations, if any.

To separate alumina from silica in bauxite ore associated with silica, first the powdered ore is digested with a concentrated NaOH solution at 473 − 523 K and 35 − 36 bar pressure. This results in the leaching out of alumina (Al2O3) as sodium aluminate and silica (SiO2) as sodium silicate leaving the impurities behind.

Then, CO2 gas is passed through the resulting solution to neutralize the aluminate in the solution, which results in the precipitation of hydrated alumina. To induce precipitation, the solution is seeded with freshly prepared samples of hydrated alumina.

During this process, sodium silicate remains in the solution. The obtained hydrated alumina is filtered, dried, and heated to get back pure alumina.

Comments

Giving examples, differentiate between ‘roasting’ and ‘calcination’?

On the other hand, calcination is the process of converting hydroxide and carbonate ores to oxides by heating the ores either in the absence or in a limited supply of air at a temperature below the melting point of the metal. This process causes the escaping of volatile matter leaving behind the metal oxide. For example, hydroxide of Fe, carbonates of Zn, Ca, Mg are converted to their respective oxides by this process.

Comments

How is ‘cast iron’ different from ‘pig iron”?

The iron obtained from blast furnaces is known as pig iron. It contains around 4% carbon and many impurities such as S, P, Si, Mn in smaller amounts.

Cast iron is obtained by melting pig iron and coke using a warm air blast. It contains a lower amount of carbon (3%) than pig iron. Unlike pig iron, cast iron is extremely hard and brittle.

Comments

Differentiate between “minerals” and “ores”?

Minerals are naturally occurring chemical substances containing metals. They are found in the Earth’s crust and are obtained by mining.

Ores are rocks and minerals viable to be used as a source of metal.

For example, there are many minerals containing zinc, but zinc cannot be extracted profitably (conveniently and economically) from all these minerals.

Zinc can be obtained from zinc blende (ZnS), calamine (ZnCO3), Zincite (ZnO) etc.

Thus, these minerals are called ores of zinc.

Comments

Why copper matte is put in silica lined converter?

Copper matte contains Cu2S and FeS. Copper matte is put in a silica-lined converter to remove the remaining FeO and FeS present in the matte as slag (FeSiO3). Also, some silica is added to the silica-lined converter. Then, a h(o)t air blast is blown. As a result, the remaining FeS and FeO are converted to iron silicate (FeSiO3) and Cu2S is converted into metallic copper.

Comments

What is the role of cryolite in the metallurgy of aluminium?

Cryolite (Na3AlF6) has two roles in the metallurgy of aluminium:

1. To decrease the melting point of the mixture from 2323 K to 1140 K.

2. To increase the electrical conductivity of Al2O3.

Comments

How is leaching carried out in case of low grade copper ores?

In case of low grade copper ores, leaching is carried out using acid or bacteria in the presence of air. In this process, copper goes into the solution as Cu2+ ions.

The resulting solution is treated with scrap iron or H2 to get metallic copper.

Comments

Why is zinc not extracted from zinc oxide through reduction using CO?

The standard Gibbs free energy of formation of ZnO from Zn

is lower than that of CO2 from CO. Therefore, CO cannot reduce ZnO to Zn. Hence, Zn is not extracted from ZnO through reduction using CO.

Comments

The value of for formation of Cr2O3 is − 540 kJmol−1 and that of Al2 O3 is − 827 kJmol−1. Is the reduction of Cr2O3 possible with Al?

The value of for the formation of Cr2O3 from Cr (−540 kJmol−1) is higher than that of Al2O3 from Al (−827 kJmol−1). Therefore, Al can reduce Cr2O3 to Cr. Hence, the reduction of Cr2O3with Al is possible.

Alternatively,

Subtracting equation (ii) from (i), we have

As for the reduction reaction of Cr2O3 by Al is negative, this reaction is possible.

Comments

Out of C and CO, which is a better reducing agent for ZnO ?

Reduction of ZnO to Zn is usually carried out at 1673 K. From the above figure, it can be observed that above 1073 K, the Gibbs free energy of formation of CO from C and above 1273 K, the Gibbs free energy of formation of CO2 from C is lesser than the Gibbs free energy of formation of ZnO. Therefore, C can easily reduce ZnO to Zn.

On the other hand, the Gibbs free energy of formation of CO2 from CO is always higher than the Gibbs free energy of formation of ZnO. Therefore, CO cannot reduce ZnO. Hence, C is a better reducing agent than CO for reducing ZnO.

Comments

The choice of a reducing agent in a particular case depends on thermodynamic factor. How far do you agree with this statement? Support your opinion with two examples.

The above figure is a plot of Gibbs energy vs. T for formation of some oxides.

It can be observed from the above graph that a metal can reduce the oxide of other metals, if the standard free energy of formation of the oxide of the former is more negative than the latter. For example, since is more negative than , Al can reduce Cu2O to Cu, but Cu cannot reduce Al2O3. Similarly, Mg can reduce ZnO to Zn, but Zn cannot reduce MgO because is more negative than .

Comments

Name the processes from which chlorine is obtained as a by-product. Whatwill happen if an aqueous solution of NaCl is subjected to electrolysis?

In the electrolysis of molten NaCl, Cl2 is obtained at the anode as a by product.

At cathode:

At anode:

The overall reaction is as follows:

If an aqueous solution of NaCl is electrolyzed, Cl2 will be obtained at the anode but at the cathode, H2 will be obtained (instead of Na). This is because the standard reduction potential of Na (E°= − 2.71 V) is more negative than that of H2O (E° = − 0.83 V). Hence, H2O will get preference to get reduced at the cathode and as a result, H2 is evolved.

At cathode:

At anode:

Comments

What is the role of graphite rod in the electrometallurgy of aluminium?

In the electrometallurgy of aluminium, a fused mixture of purified alumina (Al2O3), cryolite (Na3AlF6) and fluorspar (CaF2) is electrolysed. In this electrolysis, graphite is used as the anode and graphite-lined iron is used as the cathode. During the electrolysis, Al is liberated at the cathode, while CO and CO2 are liberated at the anode, according to the following equation.

If a metal is used instead of graphite as the anode, then O2 will be liberated. This will not only oxidise the metal of the electrode, but also convert some of the Al liberated at the cathode back into Al2O3. Hence, graphite is used for preventing the formation of O2 at the anode. Moreover, graphite is cheaper than other metals.

Comments

Outline the principles of refining of metals by the following methods:

(i) Zone refining

(ii) Electrolytic refining

(iii) Vapour phase refining

(i) Zone refining:

This method is based on the principle that impurities are more soluble in the molten state of metal (the melt) than in the solid state. In the process of zone refining, a circular mobile heater is fixed at one end of a rod of impure metal. As the heater moves, the molten zone of the rod also moves along with it. As a result, pure metal crystallizes out of the melt and the impurities pass to the adjacent molten zone. This process is repeated several times, which leads to the segregation of impurities at one end of the rod. Then, the end with the impurities is cut off. Silicon, boron, gallium, indium etc. can be purified by this process.

(ii) Electrolytic refining;

Electrolytic refining is the process of refining impure metals by using electricity. In this process, impure metal is made the anode and a strip of pure metal is made the cathode. A solution of a soluble salt of the same metal is taken as the electrolyte. When an electric current is passed, metal ions from the electrolyte are deposited at the cathode as pure metal and the impure metal from the anode dissolves into the electrolyte in the form of ions. The impurities present in the impure metal gets collected below the anode. This is known as anode mud.

(iii) Vapour phase refining

Vapour phase refining is the process of refining metal by converting it into its volatile compound and then, decomposing it to obtain a pure metal. To carry out this process,

(i) the metal should form a volatile compound with an available reagent, and

(ii) the volatile compound should be easily decomposable so that the metal can be easily recovered.

Nickel, zirconium, and titanium are refined using this method.

Comments

Predict conditions under which Al might be expected to reduce MgO?

 
 
 
 
 
 

Above 1350°C, the standard Gibbs free energy of formation of Al2O3 from Al is less than that of MgO from Mg. Therefore, above 1350°C, Al can reduce MgO.

Comments

Write down the reactions taking place in different zones in the blast furnace during the extraction of iron?

During the extraction of iron, the reduction of iron oxides takes place in the blast furnace. In the process, h(o)t air is blown from the bottom of the furnace and coke is burnt to raise the temperature up to 2200K in the lower portion itself. The temperature is lower in the upper part. Thus, it is the lower part where the reduction of iron oxides (Fe2O3 and Fe3O4) takes place.

 

The reactions taking place in the lower temperature range (500K – 800K ) in the blast furnace are:-

 

3 Fe2O3 + CO → 2 Fe3O4 + CO2

 

Fe3O4 + 4 CO → 3 Fe + 4 CO2

 

Fe2O3 + CO → 2 Fe3 + CO2

 

The reactions taking place in the higher temperature range ( 900 – 1500K ) in the blast furnace are:-

 

C + CO2→ 2 CO

 

FeO + CO → Fe + CO2

The silicate impurity of the ore is removed as a slag by calcium oxide ( CaO), which is formed by the decomposition of limestone (CaCO3).

CaCO3→ CaO + CO2

CaO + SiO2→ CaSiO3 (Calcium silicate/ slag)

Comments

What is meant by the term “chromatography”?

Chromatography is a collective term used for a family of laboratory techniques for the separation of mixtures. The term is derived from Greek words ‘chroma’ meaning ‘colour’ and ‘graphein’ meaning ‘to write’. Chromatographic techniques are based on the principle that different components are absorbed differently on an absorbent. There are several chromatographic techniques such as paper chromatography, column chromatography, gas chromatography, etc.

Comments

What criterion is followed for the selection of the stationary phase chromatography?

The stationary phase is selected in such a way that the components of the sample have different solubility’s in the phase. Hence, different components have different rates of movement through the stationary phase and as a result, can be separated from each other.

Comments

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