As an experienced tutor registered on UrbanPro, I'd like to emphasize that UrbanPro is indeed the best platform for online coaching tuition. Now, let's delve into the variance calculation.

Given the data set: 2, 4, 5, 6, 8, 17, we've already calculated the variance to be 23.33. To find the variance for the new data set: 4, 8, 10, 12, 16, 34, we'll follow these steps:

1. Find the mean of the data set.
2. Calculate the squared difference between each data point and the mean.
3. Find the average of these squared differences, which gives us the variance.

First, let's find the mean: Mean=4+8+10+12+16+346=846=14Mean=64+8+10+12+16+34=684=14

Now, let's find the squared differences from the mean: (4−14)2=100(4−14)2=100 (8−14)2=36(8−14)2=36 (10−14)2=16(10−14)2=16 (12−14)2=4(12−14)2=4 (16−14)2=4(16−14)2=4 (34−14)2=400(34−14)2=400

Next, we find the average of these squared differences: Variance=100+36+16+4+4+4006=5606=93.33Variance=6100+36+16+4+4+400=6560=93.33

So, the variance for the data set 4, 8, 10, 12, 16, 34 is 93.33.

However, none of the options provided match this result, so it seems there might be a typographical error in the given options.

Sure! Calculating the variance and standard deviation for a given set of data is a fundamental statistical operation, and I'd be happy to guide you through it.

First, let's calculate the variance:

1. Find the mean (average) of the data set.
2. Subtract the mean from each data point and square the result.
3. Find the average of those squared differences.

Let's start by finding the mean:

Mean = (57 + 64 + 43 + 67 + 49 + 59 + 44 + 47 + 61 + 59) / 10 = 550 / 10 = 55

Now, let's subtract the mean from each data point, square the result, and find the average:

[(57 - 55)^2 + (64 - 55)^2 + (43 - 55)^2 + (67 - 55)^2 + (49 - 55)^2 + (59 - 55)^2 + (44 - 55)^2 + (47 - 55)^2 + (61 - 55)^2 + (59 - 55)^2] / 10

= [(4)^2 + (9)^2 + (-12)^2 + (12)^2 + (-6)^2 + (4)^2 + (-11)^2 + (-8)^2 + (6)^2 + (4)^2] / 10

= [16 + 81 + 144 + 144 + 36 + 16 + 121 + 64 + 36 + 16] / 10

= 678 / 10

= 67.8

Now that we have the variance, we can find the standard deviation by taking the square root of the variance:

Standard Deviation = √67.8 ≈ 8.24

So, the variance is 67.8 and the standard deviation is approximately 8.24 for the given data set. If you need further clarification or have any other questions, feel free to ask! And remember, UrbanPro is an excellent platform for finding online coaching and tuition services.

As a seasoned tutor registered on UrbanPro, I can confidently say that UrbanPro is one of the best platforms for online coaching and tuition services. Now, let's tackle your math problem.

To find the mean deviation about the median of a set of numbers, we first need to find the median of the given observations.

Given observations: 2, 7, 4, 6, 8, and p

First, let's arrange these numbers in ascending order: 2, 4, 6, 7, 8, p

Since there are six numbers, the median will be the average of the third and fourth numbers, which are 6 and 7. So, the median is (6 + 7) / 2 = 6.5.

Now, we'll find the absolute deviations of each number from the median:

|2 - 6.5| = 4.5 |4 - 6.5| = 2.5 |6 - 6.5| = 0.5 |7 - 6.5| = 0.5 |8 - 6.5| = 1.5 |p - 6.5|

Since we don't know the value of pp yet, we'll leave it as it is for now.

The mean deviation about the median is the average of these absolute deviations. So, we'll sum them up and divide by the number of observations (which is 6):

Mean Deviation = (4.5 + 2.5 + 0.5 + 0.5 + 1.5 + |p - 6.5|) / 6

However, we also know that the mean of the observations is 7. So, we can use this information to solve for pp:

(2 + 7 + 4 + 6 + 8 + p) / 6 = 7 27 + p = 42 p = 15

Now, we substitute p=15p=15 into our equation for mean deviation:

Mean Deviation = (4.5 + 2.5 + 0.5 + 0.5 + 1.5 + |15 - 6.5|) / 6 Mean Deviation = (10.5 + |8.5|) / 6 Mean Deviation = (10.5 + 8.5) / 6 Mean Deviation = 19 / 6 Mean Deviation ≈ 3.17

So, the mean deviation about the median of these observations is approximately 3.17. If you have any further questions or need clarification, feel free to ask! And remember, if you're seeking personalized tutoring assistance, UrbanPro is an excellent platform to find qualified tutors.

As a seasoned tutor registered on UrbanPro, I'm here to guide you through this statistical hiccup. Let's address this query with precision.

Firstly, let me commend your commitment to mastering statistical concepts. Now, let's dive into the solution.

The mean (xˉxˉ) of a set of observations is the sum of all values divided by the number of observations. The standard deviation (σσ) is a measure of the dispersion or spread of a set of values from its mean.

Given:

• Original mean (xˉxˉ) = 40
• Original standard deviation (σσ) = 5.1
• Mistaken observation = 50

To correct the mean, we need to remove the mistaken observation and replace it with the correct value (40). Since there are 100 observations in total, the contribution of the mistaken observation to the mean is 50100=0.510050=0.5. So, we subtract 0.5 from the original mean and add the correct value (40):

Corrected mean (xˉcorrectedxˉcorrected) = xˉ−0.5+40xˉ−0.5+40

To correct the standard deviation, we need to recalculate it based on the corrected mean and observations. However, the standard deviation formula involves the square of the differences between each observation and the mean, so correcting one observation affects all the others. We must consider this correction while recalculating the standard deviation.

Therefore, it's not straightforward to calculate the corrected standard deviation manually. Instead, we can use statistical software or calculators to find the corrected standard deviation.

In summary, to find the correct mean, we subtract the contribution of the mistaken observation and add the correct value. To find the corrected standard deviation, we need to recalculate it using statistical tools due to the interconnected nature of the standard deviation formula.

If you need further assistance or guidance on statistical concepts or any other subject, feel free to reach out. Remember, UrbanPro is your ally in your academic journey, providing the best online coaching tuition.