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Answered on 30 Jun Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching/IIT JEE Advanced Coaching Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching/IIT JEE Crash Course +5 Tuition/BSc Tuition Tuition/BTech Tuition CBSE/Class 11/Commerce/Economics CBSE/Class 11/Science/Chemistry CBSE/Class 11/Commerce less

NIO Schools

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we live in a world where digital technology has outweighed conventional way of teaching.One can easily score good marks in class 11 and 12 without coaching. Some of the best online learning portals are Khan Academy, Youtube, ask iitians, Quora etccc
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Answered on 27 Jun Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching/IIT JEE Advanced Coaching Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching/IIT JEE Crash Course +5 Tuition/BSc Tuition Tuition/BTech Tuition CBSE/Class 11/Commerce/Economics CBSE/Class 11/Science/Chemistry CBSE/Class 11/Commerce less

Arun Pathrose

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If you are capable of understanding and covering 95% of the syllabuss by yourself no need of joining a coaching class else you have select a good coaching centre.
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Lesson Posted on 09 Jun CBSE/Class 11/Science/Chemistry Tuition

Meena

Do you know why water boils at higher temperature when solute is mixed into it Why your Red blood cells lose nuclei but not that of camel
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Answered on 16 Mar CBSE/Class 11/Science/Chemistry Tuition/Class XI-XII Tuition (PUC)

Debraj Paul Study Champion

Excellence Award Winner

??H = 90.0 x 540 =48600 calVolume of liquid is negligible as compared to volume of vapour. ??H = ??U + ${ pV }_{ vap }$ ??H = ??U + nRT= 48600 - 90/18 x 2 x 373(n = 90/18)= 48600 - 3730 = 44870 cal read more

 ??H = 90.0 x 540 =48600 cal

Volume of liquid is negligible as compared to volume of vapour.
??H = ??U + ${ pV }_{ vap }$
??H = ??U + nRT
= 48600 - 90/18 x 2 x 373(n = 90/18)
= 48600 - 3730 = 44870 cal 

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Asked on 15 Mar CBSE/Class 11/Science/Chemistry Tuition/Class XI-XII Tuition (PUC)

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Lesson Posted on 04 Mar CBSE/Class 11/Science/Chemistry

convert (i) nitromethane into dimethylamine? (ii) propanoic acid into ethanoic acid?

Sujoy D.

1. Strong concept building classes. 2. Weekly tests in weak areas for students to improve their confidence. 3....

QUESTION convert (i) nitromethane into dimethylamine? (ii) propanoic acid into ethanoic acid? ANSWER Nitromethane into dimethylamine read more

QUESTION

convert
(i) nitromethane into dimethylamine?
(ii) propanoic acid into ethanoic acid?

 

ANSWER

Nitromethane into dimethylamine

 

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Lesson Posted on 04 Mar CBSE/Class 11/Science/Chemistry

Two examples of disproportionation reaction in aqueous solution

Sujoy D.

1. Strong concept building classes. 2. Weekly tests in weak areas for students to improve their confidence. 3....

QUESTION What is meant by disproportionation? Give two examples of disproportionation reaction in aqueous solution ANSWER In a disproportionation reaction, same substance undergoes oxidation (increase in oxidation number) as well as reduction (decrease in oxidation number) resulting in the... read more

QUESTION

What is meant by disproportionation? Give two examples of disproportionation reaction in aqueous solution

 

ANSWER

In a disproportionation reaction, same substance undergoes oxidation (increase in oxidation number) as well as reduction (decrease in oxidation number) resulting in the formation of two different products.e.g.
(i) Mn (VI) becomes unstable relative to Mn (VII) and Mn
(IV) in acidic solution.

(ii) Many Cu (I) compounds are unstable in aqueous solution and undergo disproportionation as follows:

 

QUESTION

Do the vital functions of the body such as digestion get affected during fever? Explain your answer.

 

ANSWER

The optimum temperature range for enzymatic activity is 298-310 K, i.e. enzymes are inactive beyond this temperature range (high or low).
Thus, during fever (temperature >310 K), the activity of enzymes get affected.

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Lesson Posted on 04 Mar CBSE/Class 11/Science/Chemistry

convert the following compounds to benzene? (i)Ethyne. (ii)Ethene. (iii)Hexane.

Sujoy D.

1. Strong concept building classes. 2. Weekly tests in weak areas for students to improve their confidence. 3....

QUESTION How would you convert the following compounds to benzene? (i)Ethyne. (ii)Ethene. (iii)Hexane. ANSWER read more

QUESTION

How would you convert the following compounds to benzene?
(i)Ethyne.
(ii)Ethene.
(iii)Hexane.

ANSWER

 

 
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Answered on 20 Feb CBSE/Class 11/Science/Chemistry

Jacinta

Tutor

Hell-Volhard-Zelinsky Reaction Treatment with bromine and a catalytic amount of phosphorus leads to the selective α-bromination of carboxylic acids. Mechanism of the Hell-Volhard-Zelinsky Reaction Phosphorus reacts with bromine to give phosphorus tribromide, and in the first step this converts... read more

Hell-Volhard-Zelinsky Reaction

Treatment with bromine and a catalytic amount of phosphorus leads to the selective α-bromination of carboxylic acids.


Mechanism of the Hell-Volhard-Zelinsky Reaction

Phosphorus reacts with bromine to give phosphorus tribromide, and in the first step this converts the carboxylic acid into an acyl bromide.

An acyl bromide can readily exist in the enol form, and this tautomer is rapidly brominated at the α-carbon. The monobrominated compound is much less nucleophilic, so the reaction stops at this stage. This acyl intermediate compound can undergo bromide exchange with unreacted carboxylic acid via the anhydride, which allows the catalytic cycle to continue until the conversion is complete.

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