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A number is such that when it is divided by 15, the remainder is 14. When divided by 16, the remainder is 15. What is the lowest value of the number?

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Btech grad with 7 yrs of C++ coding experience and multiple websites running on 1st page of google

Let's say the no is X X÷15= Y+14 X÷16= Z+15 If Y=X+1 And Z= X+1 We will get the no which is directly divisible by 15 and 16. So we calculate the Lowest common multiple of 15 and 16. We get 240. Now we need to subtract 1 from it to get the exact no. Therefore the answer is 239
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Let's say the no is X

X÷15= Y+14

X÷16= Z+15

If Y=X+1

And Z= X+1

We will get the no which is directly divisible by 15 and 16.

So we calculate the Lowest common multiple of 15 and 16. We get 240.

Now we need to subtract 1 from it to get the exact no.

Therefore the answer is 239

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20 years of experience as Maths Tutor

Calculate HCF of 15, 16 = 240. Now 240 is divisible by 15 and 16 both. if we subtract 1 from 240 as 15-14 = 1 and 16-15 = 1. 239 is the required number.
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