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A, B and C together can do a piece of work in 10 days, whereas B and C can do the same work in 20 days. In how many days can A do the work if working alone?

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In time and work , If A can do a piece of work in n days, then A's 1 day's work=1/n and If A's 1 day's work=1/n, then A can finish the work in n days . Therefore: 1/A+1/B+1/C=10 days(This is equation 1) , whereas 1/B+1/C=20 days(This is equation 2) substitute equation (2) in (1) and we can get the...
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In time and work , If A can do a piece of work in n days, then A's 1 day's work=1/n and If A's 1 day's work=1/n, then A can finish the work in n days . Therefore: 1/A+1/B+1/C=10 days(This is equation 1) , whereas 1/B+1/C=20 days(This is equation 2) substitute equation (2) in (1) and we can get the value of A if working alone. Hope this clears your doubt Regards Rakesh read less
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