Bapdev Nagar, Pimpri-Chinchwad Details verified of Prashant Chand✕
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Online Classes Hindi Mother Tongue (Native)
English Proficient
Army institute of Technology, Pune Pursuing
Bachelor of Engineering (B.E.)
Bapdev Nagar, Pimpri-Chinchwad, India - 412101
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Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Board
CBSE, State, ICSE
Subjects taught
English, Mathematics, Science, Chemistry, English Literature
Taught in School or College
No
Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Board
State, CBSE
Subjects taught
Mathematics, English, Chemistry
Taught in School or College
No
Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Board
State, CBSE
Subjects taught
Chemistry, English, Mathematics
Taught in School or College
No
Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Board
CBSE, State, ICSE
Subjects taught
Mathematics, English Literature, Chemistry, English, Science
Taught in School or College
No
Answered on 23/06/2019 Learn CBSE - Class 10/English
Ask a Question
Post a Lesson
Like 0 
Answers 143 
Comments Answered on 23/06/2019
Ask a Question
Post a Lesson
x3 + y3 + z3 – 3xyz = (x + y + z) (x2 + y2 + z2 – xy – yz – zx)
Using this equation we can get to the solution.
lets take x3 + y3 + z3 as m
then m-3xyz=(x + y + z) (x2 + y2 + z2 – xy – yz – zx)
we have to find the value of m
we know this x2 + y2 + z2 = xy+yz+zx
then the RHS becomes 0
so m=3xyz
x3 + y3 + z3 =3xyz
Like 0 Answers 278 Comments Ask a Question
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Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Board
CBSE, State, ICSE
Subjects taught
English, Mathematics, Science, Chemistry, English Literature
Taught in School or College
No
Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Board
State, CBSE
Subjects taught
Mathematics, English, Chemistry
Taught in School or College
No
Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Board
State, CBSE
Subjects taught
Chemistry, English, Mathematics
Taught in School or College
No
Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Board
CBSE, State, ICSE
Subjects taught
Mathematics, English Literature, Chemistry, English, Science
Taught in School or College
No
Answered on 23/06/2019 Learn CBSE - Class 10/English
Ask a Question
Post a Lesson
Like 0 Answers 143 Comments Answered on 23/06/2019
Ask a Question
Post a Lesson
x3 + y3 + z3 – 3xyz = (x + y + z) (x2 + y2 + z2 – xy – yz – zx)
Using this equation we can get to the solution.
lets take x3 + y3 + z3 as m
then m-3xyz=(x + y + z) (x2 + y2 + z2 – xy – yz – zx)
we have to find the value of m
we know this x2 + y2 + z2 = xy+yz+zx
then the RHS becomes 0
so m=3xyz
x3 + y3 + z3 =3xyz
Like 0 Answers 278 Comments Ask a Question
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Pimpri-Chinchwad
