Bapdev Nagar, Pimpri-Chinchwad, India - 412101.
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Hindi Mother Tongue (Native)
English Proficient
Army institute of Technology, Pune Pursuing
Bachelor of Engineering (B.E.)
Bapdev Nagar, Pimpri-Chinchwad, India - 412101
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Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
State, CBSE, ICSE
CBSE Subjects taught
Mathematics, English, Science
ICSE Subjects taught
English Literature, Mathematics, Chemistry, English
Taught in School or College
No
State Syllabus Subjects taught
English, Mathematics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
CBSE, State
CBSE Subjects taught
Mathematics, English, Chemistry
Taught in School or College
No
State Syllabus Subjects taught
Chemistry, English, Mathematics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
CBSE, State
CBSE Subjects taught
Mathematics, English, Chemistry
Taught in School or College
No
State Syllabus Subjects taught
Chemistry, English, Mathematics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
State, CBSE, ICSE
CBSE Subjects taught
Mathematics, English, Science
ICSE Subjects taught
English Literature, Mathematics, Chemistry, English
Taught in School or College
No
State Syllabus Subjects taught
English, Science, Mathematics
1. Which school boards of Class 10 do you teach for?
State, CBSE and ICSE
2. Do you have any prior teaching experience?
No
3. Which classes do you teach?
I teach Class 10 Tuition, Class 11 Tuition, Class 12 Tuition and Class 9 Tuition Classes.
4. Do you provide a demo class?
Yes, I provide a free demo class.
5. How many years of experience do you have?
I have been teaching for less than a year.
Answered on 23/06/2019 Learn CBSE/Class 10/English
Answered on 23/06/2019 Learn Tuition
x3 + y3 + z3 – 3xyz = (x + y + z) (x2 + y2 + z2 – xy – yz – zx)
Using this equation we can get to the solution.
lets take x3 + y3 + z3 as m
then m-3xyz=(x + y + z) (x2 + y2 + z2 – xy – yz – zx)
we have to find the value of m
we know this x2 + y2 + z2 = xy+yz+zx
then the RHS becomes 0
so m=3xyz
x3 + y3 + z3 =3xyz
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
State, CBSE, ICSE
CBSE Subjects taught
Mathematics, English, Science
ICSE Subjects taught
English Literature, Mathematics, Chemistry, English
Taught in School or College
No
State Syllabus Subjects taught
English, Mathematics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
CBSE, State
CBSE Subjects taught
Mathematics, English, Chemistry
Taught in School or College
No
State Syllabus Subjects taught
Chemistry, English, Mathematics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
CBSE, State
CBSE Subjects taught
Mathematics, English, Chemistry
Taught in School or College
No
State Syllabus Subjects taught
Chemistry, English, Mathematics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Board
State, CBSE, ICSE
CBSE Subjects taught
Mathematics, English, Science
ICSE Subjects taught
English Literature, Mathematics, Chemistry, English
Taught in School or College
No
State Syllabus Subjects taught
English, Science, Mathematics
Answered on 23/06/2019 Learn CBSE/Class 10/English
Answered on 23/06/2019 Learn Tuition
x3 + y3 + z3 – 3xyz = (x + y + z) (x2 + y2 + z2 – xy – yz – zx)
Using this equation we can get to the solution.
lets take x3 + y3 + z3 as m
then m-3xyz=(x + y + z) (x2 + y2 + z2 – xy – yz – zx)
we have to find the value of m
we know this x2 + y2 + z2 = xy+yz+zx
then the RHS becomes 0
so m=3xyz
x3 + y3 + z3 =3xyz
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Bhosari Gavhanevasti, Pimpri-Chinchwad 
