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Share this profile 243, Sadarpur Main Rd, Block B, Sector-45
Sector 43 Block B, Noida, India - 201303
Landmark: -Chetram Girls Inter College
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Class Location
Online class via Zoom
At the Institute
Board
State, CBSE
Subjects taught
EVS, English, Science, Mathematics, Social Science, Hindi
Class Location
Online class via Zoom
At the Institute
Board
State, CBSE
Subjects taught
Physical Education, Psychology, Mathematics, English, Chemistry, Urdu, Logic, Physics, History, Education, Biology, Statistics, Geology, Biotechnology, Sociology, Legal Studies, Philosophy, Political Science, Electronics, Geography, Home Science, Hindi
Class Location
Online class via Zoom
At the Institute
Board
State, CBSE
Subjects taught
Hindi, Sociology, Education, Physics, Philosophy, Mathematics, Physical Education, Chemistry, History, Political Science, English, Biology, Biotechnology, Home Science, Urdu, Electronics, Legal Studies, Psychology, Geography, Geology, Logic
Class Location
Online class via Zoom
At the Institute
Board
State, CBSE
Subjects taught
Hindi, EVS, Urdu, Science, English, Social Science, Mathematics
Class Location
Online class via Zoom
At the Institute
Board
CBSE, State
Subjects taught
English, Science, EVS, Mathematics, Urdu, Hindi, Social science
Class Location
Online class via Zoom
At the Institute
Board
CBSE, State
Subjects taught
Mathematics, Science, EVS, English, Urdu, Hindi, Social science
Class Location
Online class via Zoom
At the Institute
Board
CBSE, State
Subjects taught
Hindi, EVS, Science, Mathematics, Urdu, English, Social science
Answered on 26/11/2019 Learn CBSE - Class 12/Physics/Unit 1-Electrostatics/ELECTROSTATIC POTENTIAL AND CAPACITANCE/NCERT Solutions/Exercise 2
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Post a Lesson
(a) Dielectric constant of the mica sheet, k = 6
Initial capacitance, C = 1.771 × 10 -11 F
New Capacitance, C'= kC= 6x1.771x10-11 =106 pF
Supply voltage, V = 100 V
New Charge, q'=C'V=6x1.771x10-9 =1.06x 10-8 C
Potential across the plates remains 100 V
(b) Dielectric constant, k = 6
Initial capacitance, C = 1.771 × 10-11 F
New Capacitance, C'= kC= 6x1.771x10-11 =106 pF
If supply voltage is removed, then there will be no effect on the amount of charge in the plates.
Charge = 1.771 × 10- 9 C
Potential across the plates is given by,
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Answers 6 
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Class Location
Online class via Zoom
At the Institute
Board
State, CBSE
Subjects taught
EVS, English, Science, Mathematics, Social Science, Hindi
Class Location
Online class via Zoom
At the Institute
Board
State, CBSE
Subjects taught
Physical Education, Psychology, Mathematics, English, Chemistry, Urdu, Logic, Physics, History, Education, Biology, Statistics, Geology, Biotechnology, Sociology, Legal Studies, Philosophy, Political Science, Electronics, Geography, Home Science, Hindi
Class Location
Online class via Zoom
At the Institute
Board
State, CBSE
Subjects taught
Hindi, Sociology, Education, Physics, Philosophy, Mathematics, Physical Education, Chemistry, History, Political Science, English, Biology, Biotechnology, Home Science, Urdu, Electronics, Legal Studies, Psychology, Geography, Geology, Logic
Class Location
Online class via Zoom
At the Institute
Board
State, CBSE
Subjects taught
Hindi, EVS, Urdu, Science, English, Social Science, Mathematics
Class Location
Online class via Zoom
At the Institute
Board
CBSE, State
Subjects taught
English, Science, EVS, Mathematics, Urdu, Hindi, Social science
Class Location
Online class via Zoom
At the Institute
Board
CBSE, State
Subjects taught
Mathematics, Science, EVS, English, Urdu, Hindi, Social science
Class Location
Online class via Zoom
At the Institute
Board
CBSE, State
Subjects taught
Hindi, EVS, Science, Mathematics, Urdu, English, Social science
Answered on 26/11/2019 Learn CBSE - Class 12/Physics/Unit 1-Electrostatics/ELECTROSTATIC POTENTIAL AND CAPACITANCE/NCERT Solutions/Exercise 2
Ask a Question
Post a Lesson
(a) Dielectric constant of the mica sheet, k = 6
Initial capacitance, C = 1.771 × 10 -11 F
New Capacitance, C'= kC= 6x1.771x10-11 =106 pF
Supply voltage, V = 100 V
New Charge, q'=C'V=6x1.771x10-9 =1.06x 10-8 C
Potential across the plates remains 100 V
(b) Dielectric constant, k = 6
Initial capacitance, C = 1.771 × 10-11 F
New Capacitance, C'= kC= 6x1.771x10-11 =106 pF
If supply voltage is removed, then there will be no effect on the amount of charge in the plates.
Charge = 1.771 × 10- 9 C
Potential across the plates is given by,
Like 0 Answers 6 Comments Ask a Question
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