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Class 12 Tuition > Class 12 Tuition in Noida > Anubhav Sinha

Anubhav Sinha Class 12 Tuition trainer in Noida

Anubhav Sinha

locationImg Sector 61 Block E, Noida
8 yrs of Exp
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Details verified of Anubhav Sinha✕

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Want to Love Maths ? ( for students upto Class XII )

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I have been a sharp student all my life with deep interest in Mathematics and Science. Have secured 99%ile in IITJEE and AIEEE 2011 . In CAT, I achieved 98%ile in 2009.
I completed my engineering in Electronics and Communications and did my MBA from Symbiosis Institute of Business Management, Pune.
After that I have spent close to 8 years in corporate sector in various functions viz. Strategy / Marketing & Operations.
Now, I want to help remove the fear of mathematics from students.
For any teaching requirements for Mathematics in Noida, please reach out to me.

Languages Spoken

Hindi Mother Tongue (Native)

English Proficient

Education

Symbiosis Institute of Business Management, Pune 2011

Master of Business Administration (M.B.A.)

Address

Sector 61 Block E, Noida, India - 201301

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Teaches

Class 12 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

8

Board

CBSE, State, ISC/ICSE, International Baccalaureate, IGCSE

Experience in School or College

Teaching is a very satisfying profession through which I help students achieve their goals.

Subjects taught

Mathematics

Taught in School or College

Yes

Class 11 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

8

Board

CBSE, State, ISC/ICSE, International Baccalaureate, IGCSE

Subjects taught

Mathematics

Taught in School or College

No

Class 10 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

8

Board

International Baccalaureate, CBSE, IGCSE, ICSE, State

Subjects taught

Mathematics

Taught in School or College

No

Class 9 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

8

Board

International Baccalaureate, CBSE, IGCSE, ICSE, State

Subjects taught

Mathematics

Taught in School or College

No

Class 8 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 8 Tuition

8

Board

Cambridge Assessment International Education (CAIE), CBSE, ICSE, International Baccalaureate, State

Subjects taught

Mathematics

Taught in School or College

No

Reviews

No Reviews yet!

Answers by Anubhav Sinha

Answered on 23/10/2019

Ask a Question

Post a Lesson

Hi,I have requirement to write macro in excel to calulate pricing based on input and filters for different... ...more
Hi,I have requirement to write macro in excel to calulate pricing based on input and filters for different...

Sure... To start with we need to define the variable relationships.
Answers 77 Comments
Dislike Bookmark

Answered on 29/06/2019

Ask a Question

Post a Lesson

<p>if x^2+y^2+z^2=xy+yz+zx then find the value of x^3+y^3+z^3</p>

If x^2+y^2+z^2=xy+yz+zx then, 2x^2+2y^2+2z^2=2xy+2yz+2zx ie (x^2+y^2) + (y^2+z^2) + (z^2+x^2) = 2xy+2yz+2zx ie (x^2+y^2 -2xy) + (y^2+z^2 -2yz) + (z^2+x^2 - 2zx) = 0 ie (x-y)^2 + (y-z)^2 + (z-x)^2 = 0 , which will happen only when x = y = z = k (let) Now, consider (x+y+z)^3 = x^3 + (y+z)^3 + 3x(y+z) (x+... ...more

If x^2+y^2+z^2=xy+yz+zx then,

2x^2+2y^2+2z^2=2xy+2yz+2zx ie

(x^2+y^2) + (y^2+z^2) + (z^2+x^2) = 2xy+2yz+2zx ie

(x^2+y^2 -2xy) + (y^2+z^2 -2yz) + (z^2+x^2 - 2zx) = 0 ie

(x-y)^2 + (y-z)^2 + (z-x)^2 = 0 ,

which will happen only when

x = y = z = k (let)

Now, consider

(x+y+z)^3 = x^3 + (y+z)^3 + 3x(y+z) (x+ y +z )

                 =x^3 + (y^3 + z^3 + 3y^2z + 3yz^2 ) +3x (xy + y^2 + yz + xz + yz + z^2)

            = x^3 + y^3 + z^3 + 3y^2z + 3yz^2  +3x^2y + 3xy^2 + 3xyz + 3x^2z + 3xyz +3xz^2

            = x^3 + y^3 + z^3 + 3y^2z + 3yz^2  +3x^2y + 3xy^2 + 3xyz + 3x^2z + 3xyz +3xz^2

so,

x^3 + y^3 + z^3 = (x+y+z)^3 - (3y^2z +3yz^2  +3x^2y +3xy^2 +3xyz +3x^2z +3xyz +3xz^2)

                          = (3k)^3 - k^3 (3+3+3+3+3+3+3+3)

                          = k^3 (27-24)

                          = 3k^3 = 3x^3 = 3y^3 = 3z^3 = 3x^2y= 3x^2z = 3y^2x = 3y^2z = 3z^2x = 3z^2y = 3xyz

Answers 278 Comments
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Teaches

Class 12 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

8

Board

CBSE, State, ISC/ICSE, International Baccalaureate, IGCSE

Experience in School or College

Teaching is a very satisfying profession through which I help students achieve their goals.

Subjects taught

Mathematics

Taught in School or College

Yes

Class 11 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

8

Board

CBSE, State, ISC/ICSE, International Baccalaureate, IGCSE

Subjects taught

Mathematics

Taught in School or College

No

Class 10 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

8

Board

International Baccalaureate, CBSE, IGCSE, ICSE, State

Subjects taught

Mathematics

Taught in School or College

No

Class 9 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

8

Board

International Baccalaureate, CBSE, IGCSE, ICSE, State

Subjects taught

Mathematics

Taught in School or College

No

Class 8 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 8 Tuition

8

Board

Cambridge Assessment International Education (CAIE), CBSE, ICSE, International Baccalaureate, State

Subjects taught

Mathematics

Taught in School or College

No

No Reviews yet!

Answers by Anubhav Sinha

Answered on 23/10/2019

Ask a Question

Post a Lesson

Hi,I have requirement to write macro in excel to calulate pricing based on input and filters for different... ...more
Hi,I have requirement to write macro in excel to calulate pricing based on input and filters for different...

Sure... To start with we need to define the variable relationships.
Answers 77 Comments
Dislike Bookmark

Answered on 29/06/2019

Ask a Question

Post a Lesson

<p>if x^2+y^2+z^2=xy+yz+zx then find the value of x^3+y^3+z^3</p>

If x^2+y^2+z^2=xy+yz+zx then, 2x^2+2y^2+2z^2=2xy+2yz+2zx ie (x^2+y^2) + (y^2+z^2) + (z^2+x^2) = 2xy+2yz+2zx ie (x^2+y^2 -2xy) + (y^2+z^2 -2yz) + (z^2+x^2 - 2zx) = 0 ie (x-y)^2 + (y-z)^2 + (z-x)^2 = 0 , which will happen only when x = y = z = k (let) Now, consider (x+y+z)^3 = x^3 + (y+z)^3 + 3x(y+z) (x+... ...more

If x^2+y^2+z^2=xy+yz+zx then,

2x^2+2y^2+2z^2=2xy+2yz+2zx ie

(x^2+y^2) + (y^2+z^2) + (z^2+x^2) = 2xy+2yz+2zx ie

(x^2+y^2 -2xy) + (y^2+z^2 -2yz) + (z^2+x^2 - 2zx) = 0 ie

(x-y)^2 + (y-z)^2 + (z-x)^2 = 0 ,

which will happen only when

x = y = z = k (let)

Now, consider

(x+y+z)^3 = x^3 + (y+z)^3 + 3x(y+z) (x+ y +z )

                 =x^3 + (y^3 + z^3 + 3y^2z + 3yz^2 ) +3x (xy + y^2 + yz + xz + yz + z^2)

            = x^3 + y^3 + z^3 + 3y^2z + 3yz^2  +3x^2y + 3xy^2 + 3xyz + 3x^2z + 3xyz +3xz^2

            = x^3 + y^3 + z^3 + 3y^2z + 3yz^2  +3x^2y + 3xy^2 + 3xyz + 3x^2z + 3xyz +3xz^2

so,

x^3 + y^3 + z^3 = (x+y+z)^3 - (3y^2z +3yz^2  +3x^2y +3xy^2 +3xyz +3x^2z +3xyz +3xz^2)

                          = (3k)^3 - k^3 (3+3+3+3+3+3+3+3)

                          = k^3 (27-24)

                          = 3k^3 = 3x^3 = 3y^3 = 3z^3 = 3x^2y= 3x^2z = 3y^2x = 3y^2z = 3z^2x = 3z^2y = 3xyz

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