Anubhav Sinha

Sector 61 Block E, Noida, India - 201301

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Sector 61 Block E, Noida, India - 201301.

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I have been a sharp student all my life with deep interest in Mathematics and Science. Have secured 99%ile in IITJEE and AIEEE 2011 . In CAT, I achieved 98%ile in 2009.

I completed my engineering in Electronics and Communications and did my MBA from Symbiosis Institute of Business Management, Pune.

After that I have spent close to 8 years in corporate sector in various functions viz. Strategy / Marketing & Operations.

Now, I want to help remove the fear of mathematics from students.

For any teaching requirements for Mathematics in Noida, please reach out to me.

I completed my engineering in Electronics and Communications and did my MBA from Symbiosis Institute of Business Management, Pune.

After that I have spent close to 8 years in corporate sector in various functions viz. Strategy / Marketing & Operations.

Now, I want to help remove the fear of mathematics from students.

For any teaching requirements for Mathematics in Noida, please reach out to me.

Hindi Mother Tongue (Native)

English Proficient

Symbiosis Institute of Business Management, Pune 2011

Master of Business Administration (M.B.A.)

Sector 61 Block E, Noida, India - 201301

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Class 12 Tuition

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 12 Tuition

8

Board

State, CBSE, International Baccalaureate, ISC/ICSE, IGCSE

IB Subjects taught

Mathematics

ISC/ICSE Subjects taught

Mathematics

CBSE Subjects taught

Mathematics

IGCSE Subjects taught

Mathematics

Experience in School or College

Teaching is a very satisfying profession through which I help students achieve their goals.

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics

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No Reviews yet! Be the first one to Review

Answered on 29 Jun Tuition

If x^2+y^2+z^2=xy+yz+zx then, 2x^2+2y^2+2z^2=2xy+2yz+2zx ie (x^2+y^2) + (y^2+z^2) + (z^2+x^2) = 2xy+2yz+2zx ie (x^2+y^2 -2xy) + (y^2+z^2 -2yz) + (z^2+x^2 - 2zx) = 0 ie (x-y)^2 + (y-z)^2 + (z-x)^2 = 0 , which will happen only when x = y = z = k (let) Now, consider (x+y+z)^3 = x^3 + (y+z)^3 + 3x(y+z) (x+... ...more

If x^2+y^2+z^2=xy+yz+zx then,

2x^2+2y^2+2z^2=2xy+2yz+2zx ie

(x^2+y^2) + (y^2+z^2) + (z^2+x^2) = 2xy+2yz+2zx ie

(x^2+y^2 -2xy) + (y^2+z^2 -2yz) + (z^2+x^2 - 2zx) = 0 ie

(x-y)^2 + (y-z)^2 + (z-x)^2 = 0 ,

**which will happen only when**

**x = y = z = k (let)**

Now, consider

(x+y+z)^3 = x^3 + (y+z)^3 + 3x(y+z) (x+ **y +z** )

=x^3 + (y^3 + z^3 + 3y^2z + 3yz^2 ) +3x (xy + y^2 + yz + xz + yz + z^2)

= x^3 + y^3 + z^3 + 3y^2z + 3yz^2 +3x^2y + 3xy^2 + 3xyz + 3x^2z + 3xyz +3xz^2

= x^3 + y^3 + z^3 + 3y^2z + 3yz^2 +3x^2y + 3xy^2 + 3xyz + 3x^2z + 3xyz +3xz^2

so,

x^3 + y^3 + z^3 = (x+y+z)^3 - (3y^2z +3yz^2 +3x^2y +3xy^2 +3xyz +3x^2z +3xyz +3xz^2)

= (3k)^3 - k^3 (3+3+3+3+3+3+3+3)

= k^3 (27-24)

= 3k^3 = 3x^3 = 3y^3 = 3z^3 = 3x^2y= 3x^2z = 3y^2x = 3y^2z = 3z^2x = 3z^2y = **3xyz**

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Answers 222 Comments Anubhav SinhaDirections

x Class 12 Tuition 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 12 Tuition

8

Board

State, CBSE, International Baccalaureate, ISC/ICSE, IGCSE

IB Subjects taught

Mathematics

ISC/ICSE Subjects taught

Mathematics

CBSE Subjects taught

Mathematics

IGCSE Subjects taught

Mathematics

Experience in School or College

Teaching is a very satisfying profession through which I help students achieve their goals.

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics

Class 11 Tuition 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 11 Tuition

8

Board

State, CBSE, International Baccalaureate, ISC/ICSE, IGCSE

IB Subjects taught

Mathematics

ISC/ICSE Subjects taught

Mathematics

CBSE Subjects taught

Mathematics

IGCSE Subjects taught

Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Class 10 Tuition 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 10 Tuition

8

Board

ICSE, International Baccalaureate, State, CBSE, IGCSE

IB Subjects taught

Mathematics

CBSE Subjects taught

Mathematics

ICSE Subjects taught

Mathematics

IGCSE Subjects taught

Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Class 9 Tuition 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 9 Tuition

8

Board

ICSE, International Baccalaureate, State, CBSE, IGCSE

IB Subjects taught

Mathematics

CBSE Subjects taught

Mathematics

ICSE Subjects taught

Mathematics

IGCSE Subjects taught

Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Class 8 Tuition 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 8 Tuition

8

Board

CBSE, IGCSE, International Baccalaureate, ICSE, State

IB Subjects taught

Mathematics

CBSE Subjects taught

Mathematics

ICSE Subjects taught

Mathematics

IGCSE Subjects taught

Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

this is test message this is test message this is test message this is test message this is test message this is test message this is test message

No Reviews yet! Be the first one to Review

Answered on 29 Jun Tuition

If x^2+y^2+z^2=xy+yz+zx then, 2x^2+2y^2+2z^2=2xy+2yz+2zx ie (x^2+y^2) + (y^2+z^2) + (z^2+x^2) = 2xy+2yz+2zx ie (x^2+y^2 -2xy) + (y^2+z^2 -2yz) + (z^2+x^2 - 2zx) = 0 ie (x-y)^2 + (y-z)^2 + (z-x)^2 = 0 , which will happen only when x = y = z = k (let) Now, consider (x+y+z)^3 = x^3 + (y+z)^3 + 3x(y+z) (x+... ...more

If x^2+y^2+z^2=xy+yz+zx then,

2x^2+2y^2+2z^2=2xy+2yz+2zx ie

(x^2+y^2) + (y^2+z^2) + (z^2+x^2) = 2xy+2yz+2zx ie

(x^2+y^2 -2xy) + (y^2+z^2 -2yz) + (z^2+x^2 - 2zx) = 0 ie

(x-y)^2 + (y-z)^2 + (z-x)^2 = 0 ,

**which will happen only when**

**x = y = z = k (let)**

Now, consider

(x+y+z)^3 = x^3 + (y+z)^3 + 3x(y+z) (x+ **y +z** )

=x^3 + (y^3 + z^3 + 3y^2z + 3yz^2 ) +3x (xy + y^2 + yz + xz + yz + z^2)

= x^3 + y^3 + z^3 + 3y^2z + 3yz^2 +3x^2y + 3xy^2 + 3xyz + 3x^2z + 3xyz +3xz^2

= x^3 + y^3 + z^3 + 3y^2z + 3yz^2 +3x^2y + 3xy^2 + 3xyz + 3x^2z + 3xyz +3xz^2

so,

x^3 + y^3 + z^3 = (x+y+z)^3 - (3y^2z +3yz^2 +3x^2y +3xy^2 +3xyz +3x^2z +3xyz +3xz^2)

= (3k)^3 - k^3 (3+3+3+3+3+3+3+3)

= k^3 (27-24)

= 3k^3 = 3x^3 = 3y^3 = 3z^3 = 3x^2y= 3x^2z = 3y^2x = 3y^2z = 3z^2x = 3z^2y = **3xyz**

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Answers 222 Comments Share this Profile

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