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The circumference of the base of a cylindrical vessel is 132 cm and its height is 25 cm. How many litres of water can it hold? (1000 = 1l)
Let the radius of the cylindrical vessel be r.
Height (h) of vessel = 25 cm
Circumference of vessel = 132 cm
2πr = 132 cm
Volume of cylindrical vessel = πr2h
= 34650 cm3
= 34.65 litres
Therefore, such vessel can hold 34.65 litres of water.
A patient in a hospital is given soup daily in a cylindrical bowl of diameter 7 cm. If the bowl is filled with soup to a height of 4 cm, how much soup the hospital has to prepare daily to serve 250 patients?
Radius (r) of cylindrical bowl =
Height (h) of bowl, up to which bowl is filled with soup = 4 cm
Volume of soup in 1 bowl = πr2h
= (11 × 3.5 × 4) cm3
= 154 cm3
Volume of soup given to 250 patients = (250 × 154) cm3
= 38500 cm3
= 38.5 litres.
The inner diameter of a cylindrical wooden pipe is 24 cm and its outer diameter is 28 cm. The length of the pipe is 35 cm. Find the mass of the pipe, if 1 of wood has a mass of 0.6 g.
Inner radius (r1) of cylindrical pipe =
Outer radius (r2) of cylindrical pipe =
Height (h) of pipe = Length of pipe = 35 cm
Volume of pipe =
Mass of 1 cm3 wood = 0.6 g
Mass of 5720 cm3 wood = (5720 × 0.6) g
= 3432 g
= 3.432 kg
A soft drink is available in two packs – (i) a tin can with a rectangular base of length 5 cm and width 4 cm, having a height of 15 cm and (ii) a plastic cylinder with circular base of diameter 7 cm and height 10 cm. Which container has greater capacity and by how much?
The tin can will be cuboidal in shape while the plastic cylinder will be cylindrical in shape.
Length (l) of tin can = 5 cm
Breadth (b) of tin can = 4 cm
Height (h) of tin can = 15 cm
Capacity of tin can = l × b × h
= (5 × 4 × 15) cm3
= 300 cm3
Radius (r) of circular end of plastic cylinder =
Height (H) of plastic cylinder = 10 cm
Capacity of plastic cylinder = πr2H
Therefore, plastic cylinder has the greater capacity.
Difference in capacity = (385 − 300) cm3 = 85 cm3
If the lateral surface of a cylinder is 94.2 and its height is 5 cm, then find the
(i) radius of its base
(ii) its volume. (Use = 3.14)
(i) Height (h) of cylinder = 5 cm
Let radius of cylinder be r.
CSA of cylinder = 94.2 cm2
2πrh = 94.2 cm2
(2 × 3.14 × r × 5) cm = 94.2 cm2
r = 3 cm
(ii) Volume of cylinder = πr2h
= (3.14 × (3)2 × 5) cm3
= 141.3 cm3
It costs Rs. 2200 to paint the inner curved surface of a cylindrical vessel 10 m deep. If
the cost of painting is at the rate of Rs. 20 per , find
(i) inner curved surface area of the vessel,
(ii) radius of the base,
(iii) capacity of the vessel.
(i) Rs 20 is the cost of painting 1 m2 area.
Rs 2200 is the cost of painting =
= 110 m2 area
Therefore, the inner surface area of the vessel is 110 m2.
(ii) Let the radius of the base of the vessel be r.
Height (h) of vessel = 10 m
Surface area = 2πrh = 110 m2
(iii) Volume of vessel = πr2h
= 96.25 m3
Therefore, the capacity of the vessel is 96.25 m3 or 96250 litres.
The capacity of a closed cylindrical vessel of height 1 m is 15.4 litres. How many
square metres of metal sheet would be needed to make it?
Let the radius of the circular end be r.
Height (h) of cylindrical vessel = 1 m
Volume of cylindrical vessel = 15.4 litres = 0.0154 m3
⇒ r = 0.07 m
Therefore, 0.4708 m2 of the metal sheet would be required to make the cylindrical vessel.
A lead pencil consists of a cylinder of wood with a solid cylinder of graphite filled in the interior. The diameter of the pencil is 7 mm and the diameter of the graphite is 1 mm. If the length of the pencil is 14 cm, find the volume of the wood and that of the graphite.
Radius (r1) of pencil =
= 0.35 cm
Radius (r2) of graphite =
= 0.05 cm
Height (h) of pencil = 14 cm
Volume of wood in pencil =
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