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Manthan Rathod Class 6 Tuition trainer in Mumbai

Manthan Rathod

locationImg Bhayandar East, Mumbai
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I am pursuing my second year electronics at Sardar Patel Institute of Technology.
Passed with 87% pcm aggregate in 12th STD. Appeared for JEE mains and MHTCET and scored 162/200
A fresher but i am very much confident that I can improve the marks as well the most important factor "Thought Process" of the student and can make him/her develop a better approach towards success if given a chance to induce my skills into them.

Languages Spoken

Marathi

English

Hindi

Address

Bhayandar East, Mumbai, India - 401105

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Teaches

Class 6 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Board

CBSE, State

Subjects taught

Science, Mathematics

Taught in School or College

No

Class 7 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Board

CBSE, State

Subjects taught

Mathematics, Science

Taught in School or College

No

Class 8 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Board

CBSE, State

Subjects taught

Mathematics, Science

Taught in School or College

No

Class 9 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Board

State

Subjects taught

Mathematics, Science

Taught in School or College

No

Class 10 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Board

State

Subjects taught

Mathematics, Science

Taught in School or College

No

Class 11 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Board

State

Subjects taught

Physics, Mathematics, Chemistry

Taught in School or College

No

Class 12 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Board

State

Subjects taught

Chemistry, Mathematics, Physics

Taught in School or College

No

Reviews

No Reviews yet!

Answers by Manthan Rathod

Answered on 24/04/2018

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5k pm. With flexible lectures.
Answers 1475 Comments
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Answered on 03/06/2017 Learn Tuition/Class XI-XII Tuition (PUC)

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Post a Lesson

Tan(360)= tan(2?-360) Hence. Tan(360)=tan(0)=0
Answers 145 Comments
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Answered on 03/06/2017

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Post a Lesson

It's a formula for finding force over a body in motion. Where a is acceleration of the body and m is mass of it. It corresponds to Newton's? second law of motion.
Answers 183 Comments
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Teaches

Class 6 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Board

CBSE, State

Subjects taught

Science, Mathematics

Taught in School or College

No

Class 7 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Board

CBSE, State

Subjects taught

Mathematics, Science

Taught in School or College

No

Class 8 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Board

CBSE, State

Subjects taught

Mathematics, Science

Taught in School or College

No

Class 9 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Board

State

Subjects taught

Mathematics, Science

Taught in School or College

No

Class 10 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Board

State

Subjects taught

Mathematics, Science

Taught in School or College

No

Class 11 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Board

State

Subjects taught

Physics, Mathematics, Chemistry

Taught in School or College

No

Class 12 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Board

State

Subjects taught

Chemistry, Mathematics, Physics

Taught in School or College

No

No Reviews yet!

Answers by Manthan Rathod

Answered on 24/04/2018

Ask a Question

Post a Lesson

5k pm. With flexible lectures.
Answers 1475 Comments
Dislike Bookmark

Answered on 03/06/2017 Learn Tuition/Class XI-XII Tuition (PUC)

Ask a Question

Post a Lesson

Tan(360)= tan(2?-360) Hence. Tan(360)=tan(0)=0
Answers 145 Comments
Dislike Bookmark

Answered on 03/06/2017

Ask a Question

Post a Lesson

It's a formula for finding force over a body in motion. Where a is acceleration of the body and m is mass of it. It corresponds to Newton's? second law of motion.
Answers 183 Comments
Dislike Bookmark
x

Ask a Question

Please enter your Question

Please select a Tag

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