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Math Olympiad classes Fees

Estimated Fees in India

₹ 1,500 to ₹ 3,000 per month

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Trending discussions on Math Olympiad classes

Lesson Posted on 04 Apr Language/Hindi Language/Hindi Speaking CBSE/Class 1/Maths Exam Coaching/Math Olympiad +3 CBSE/Class 10/Mathematics CBSE/Class 2/Maths/Mental Mathematics Tuition/BSc Tuition/General Chemistry For Maths & Physics less

Maths Online Tutor, Hindi Online Tutor

Nisha T.

Real time two-way audio and video interactive classes on white board using digital pen tablet. I am...

Real time two-way audio and video interactive classes on whiteboard using digital pen tablet.I am a highly qualified and experienced online tutor, teaching Maths and Hindi. I have taught more than 7000 sessions too and have more than 100 students worldwide. I teach home schooling students also. I teach... read more

Real time two-way audio and video interactive classes on whiteboard using digital pen tablet.
I am a highly qualified and experienced online tutor, teaching Maths and Hindi. I have taught more than 7000 sessions too and have more than 100 students worldwide. I teach home schooling students also. I teach students of all ages from 3 years to 99 years old.
I teach all topics in Maths including Basic maths, pre algebra, algebra, arithmetic, geometry, pre calculus, calculus, probability, statistics etc.
I also teach any curriculum including CBSE, ICSE, IGCSE, IB, KS1, KS2, KS3 etc.
I teach Hindi language (beginner, intermediate, advanced levels).
Teaching and learning on digital whiteboard gives you the benefit of real time interaction. You can write, draw, chat, audio, video etc. in real time. Scheduling of classes can be flexible.
All your sessions are recorded which enables you to review any time at any place.
So, to have a friendly, interactive and encouraging learning experience for Maths and Hindi, Please contact me.
Contacts

Name NISHA THAKUR
Mobile: +91-9821940507

Skype nishathakur4

Email nishathakur04@gmail.com

Fee Structure

Daily sessions------------------> $15/hour (20 session/month = $300)

4 sessions in a week----------> $17/hour (16 session/month = $272)
3 sessions in a week----------> $18/hour (12 session/month = $216)
2 sessions in a week----------> $19/hour ( 8 session/month = $152)
1 session in a week-----------> $20/hour ( 4 session/month = $80 )

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Lesson Posted on 05 Mar CBSE/Class 8/Maths Exam Coaching/Math Olympiad

Worksheet On Parallelogram

Soumi Roy

I am an experienced, qualified tutor with over 5 years of experience in teaching maths and physics across...

1. ABCD is a parallelogram in which ∠A = 110°. Find the measure of each of the angles ∠B, ∠C and ∠D. 2. Two adjacent angles of a parallelogram are equal. What is the measure of each of these angles? 3. Two adjacent angles of a parallelogram are in the ratio 4 : 5. Find the measure... read more

1. ABCD is a parallelogram in which ∠A = 110°. Find the measure of each of the angles ∠B, ∠C and ∠D. 

2. Two adjacent angles of a parallelogram are equal. What is the measure of each of these angles? 

3. Two adjacent angles of a parallelogram are in the ratio 4 : 5. Find the measure of each of its angles. 

4. Two adjacent angles of a parallelogram are (3x - 4)° and (3x + 16)°. Find the value of x and hence find the measure of each of its angles. 

5. The sum of two opposite angles of a parallelogram is 130°. Find the measure of each of its angles. 

6. Two sides of a parallelogram are in the ratio 5 : 3. If its perimeter is 64 cm, find the lengths of its sides.

7. The perimeter of a parallelogram is 140 cm. If one of the sides is longer than the other by 10 cm, find the length of each of its sides.

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Lesson Posted on 06 Feb Exam Coaching/NTSE exam Coaching Exam Coaching/Math Olympiad

Find The Ratio AE: EC (Important For NTSE Olympiad)

Sujoy D.

1. Strong concept building classes. 2. Weekly tests in weak areas for students to improve their confidence. 3....

Question given below: Solution 1: Solution 2: Solution 3: Solution 4: Draw a line from D... read more

Question given below:

                           

 

Solution 1:

 

                                                       

Solution 2:

 

                                                               

Solution 3:

 

                                     

Solution 4:

Draw a line from D parallel to BE cutting AC at P.

CDP and CBE are similar.

EP/EC = BD/BC = 3:5

Also, AFE and ADP are similar.

AE/EP = AD/FD = 2:1

Multiply both the equation from the top, so AE/EC = 6:5.

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