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Hello Kasireddy,

The electronic confugaration of Copper (Cu) is [Ar]  but not .

This is because of

stability of completely filled d sub-shell.

The completely filled & hlaf-filled sub-shells are stable.

The causes of stability of completely filled & half filled sub-shells are due to following reasons

1) symmetrical distribution of electrons

2) exchange energy

due to above reasons Copper has [Ar]  electronic confuguratiion.

Thank you

 

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Hello Geeta,

The term degenerated indicates containing nearly same enegry. In d-subshell, the 5 orbitals are degeneted.

among the the above options   , are degenerated.

*Hint- d-obritals which are in same shell are degenerated (until they are under the influence of any other ligands)

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Answer is A

Orbital angular momentum depends on the value of azimuthal quantum number.

 

Azimuthal Quantum Number describes the shape of the orbital.

It is represented as 'l'.

The value of l ranges from 0 to (n-1). For l = 0,1,2,3... the orbitals are s, p, d, f...

The orbital angular momentum of an electron is given by

l = azimuthal quantum number

h = plank's constant

Thus Orbital angular momentum depends on the value of azimuthal quantum number i.e the value of l.

Thank you.

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Which of the following conclusions could not be derived from Rutherford’s α-particle scattering experiment?(a) Most of the space in the atom is empty. (b) The radius of the atom is about 10 -10 m while that of nucleus is 10 -15 (c) Electrons move in a circular path of fixed energy called orbits. (d) Electrons and the nucleus are held together by electrostatic forces of attraction." read less

According to de Broglie, matter should exhibit dual behaviour, that is both particle and wave like properties. However, a cricket ball of mass 100 g does not move like a wave when it is thrown by a bowler at a speed of 100 km/h. Calculate the wavelength of the ball and explain why it does not show wave nature. read less

The Balmer series in the hydrogen spectrum corresponds to the transition from n1 = 2 to n2 = 3, 4,……… This series lies in the visible region. Calculate the wave number of line associated with the transition in Balmer series when the electron moves to n = 4 orbit. (RH = 109677 cm-1). read less

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