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Permutation and Combinations

Top Tutors who teach Permutation and Combinations

1
Presbytery Madeykunnu - Kuravilangad Rd, Vaikom
Classes: Tuition

I am a dedicated postgraduate student with a strong background in education, having provided home tuition since my plus two classes. With a Bachelor's...

2
Debojit Sarkar Tuition trainer in Jamshedpur Featured
Parsudih, Jamshedpur
Super Tutor
3 yrs of Exp
500per hour
Classes: Tuition, Engineering Diploma Tuition and more.

I am a B.E(Civil) from Jadavpur University. I am teaching since 2021. I am very proficient in Maths and Science. My main goal is to make students...

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Sundara Rao ganti Tuition trainer in Hisar Featured
Prem Nagar, Hisar
Super Tutor
20+ yrs of Exp
600per hour
Classes: Tuition, Class 12 Tuition

I recently retired from my job after serving in a very reputed school. I have good experience in teaching accountancy and business studies. I know...

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Bindu Davi Tuition trainer in Enamavu Featured
Enamakkal, Enamavu
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15 yrs of Exp
350per hour
Classes: Tuition, Class 8 Tuition and more.

I am a school teacher from Kerala , India. I have 15 years teaching experience in CBSE school. I have a degree in statistics. I am a certified trained...

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Deepashree Tuition trainer in Bangalore Featured
Basaveshwara Nagar, Bangalore
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12 yrs of Exp
500per hour
Classes: Tuition, Class 9 Tuition and more.

With over 15 years of dedicated teaching experience, I am an accomplished and qualified educator specializing in Spoken English, Math, Science, Social...

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Knowledge Park II, Noida
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8 yrs of Exp
400per hour
Classes: Tuition, Class 11 Tuition and more.

I have been teaching past 9 years and have gained a-lot experience after teaching in premium institutes. Having mentored more than a thousand students...

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Dr. srilatha N. Tuition trainer in Hyderabad Featured
Begumpet, Hyderabad
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20+ yrs of Exp
500per hour
Classes: Tuition, Class 12 Tuition

I teach Class 12 and B.Com students, specializing in core Accounting subjects such as Financial Accounting, Corporate Accounting, Advanced Accounting,...

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Neeraj Dwivedi Tuition trainer in Delhi Featured
Mukherjee Nagar, Delhi
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5 yrs of Exp
500per hour
Classes: Tuition, Class 11 Tuition and more.

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Hari kishore S. Tuition trainer in Delhi Featured
Patpar Ganj, Delhi
Super Tutor
20+ yrs of Exp
600per hour
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I am taking home tuition for Accounts, Costing & Financial management for classes XI, XII, B.COM(H/P), BBA & MBA since 1997.

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Amit Tuition trainer in Gurgaon Featured
Sector 92, Gurgaon
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20+ yrs of Exp
800per hour
Classes: Tuition, Vedic Maths Training and more.

With an unwavering passion for mathematics, I have dedicated 21 years of my life to the art of teaching. Armed with an M.Sc. in Mathematics, what...

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Permutation and Combinations Lessons

Notes on Permutation,Combination
A permutation is merely meaning the arrangement of things in how many ways the elements can be arranged permutation word comes from a Latin word which means to change thoroughly or exchange the things If...

Permutation and Combinations Questions

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Answered on 19/11/2016 Learn Permutation and Combinations +2 Tuition/Class XI-XII Tuition (PUC) CBSE - Class 12/Mathematics

Sadiya Ghori

Accountancy Tutor

120
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Answered on 28/11/2016 Learn Permutation and Combinations +2 Tuition/Class XI-XII Tuition (PUC) CBSE - Class 12/Mathematics

Tapas Bhattacharya

Tutor

Here, all the letters are different and there are 5 letters. So, the number of words = 5! = 120.
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Answered on 04/12/2016 Learn Permutation and Combinations +2 Tuition/Class XI-XII Tuition (PUC) CBSE - Class 12/Mathematics

Tapas Bhattacharya

Tutor

For all the numbers the last digit must be 5. So, the 1st, and the 2nd places are occupied by 2, 3, 6, 7, and 9 without any repetition. So, this can be done by taking 2 digits at a time from the above 6 digits. The number of ways this can be done is 6P2 = !6/!(6-2) = !6/!4 = (6x5x4x3x2x1)/(4x3x2x1) =... read more
For all the numbers the last digit must be 5. So, the 1st, and the 2nd places are occupied by 2, 3, 6, 7, and 9 without any repetition. So, this can be done by taking 2 digits at a time from the above 6 digits. The number of ways this can be done is 6P2 = !6/!(6-2) = !6/!4 = (6x5x4x3x2x1)/(4x3x2x1) = 6x5 = 30. (Answer) read less
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Answered on 01/12/2016 Learn Permutation and Combinations +2 Tuition/Class XI-XII Tuition (PUC) CBSE - Class 12/Mathematics

Sreedevi Addepalli

Teacher

(100)! / 98!
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Answered on 01/12/2016 Learn Permutation and Combinations +2 Tuition/Class XI-XII Tuition (PUC) CBSE - Class 12/Mathematics

Anil Kumar

CAT Coaching Classes

Each ring has a choice of 3 fingers, so no of ways =3^6. There are no restrictions.
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