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Motion in a Straight Line

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Answered on 14/09/2018 Learn Motion in a Straight Line +1 CBSE - Class 11/Physics

Abhishek Aman

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Both are in opposite direction,so consider one velocity in negative direction. Velocity of jet w.r.t. ground Vjg= 500 km/h …...(Upward) Velocity of products relative to jet VPJ = 1500 km/h ... read more

Both are in opposite direction,so consider one velocity in negative direction.

    Velocity of jet w.r.t. ground Vjg= 500 km/h                                                                …...(Upward)

        Velocity of products relative to jet VPJ = 1500 km/h                                                …(downward)

Hence, velocity of  products relative to ground = -1500+500

                                                                                    =  -1000 km/h

Here – ve sign means downward .

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Answered on 15/09/2018 Learn Motion in a Straight Line +1 CBSE - Class 11/Physics

Vijay Giri

Tutor

Distance Vs time graph is parabolic graph in case of n sec but it's straight line if we draw graph for distance Vs nth second time graph passing through origin as u=0 and acceleration constant
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