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Q3(viii):
Verify whether the following are zeroes of the polynomial, indicated against them.
(viii) $p(x) = 2x + 1, x = \frac{1}{2}$
Solution :
Initial Setup & Theoretical Foundation
We are tasked with verifying whether the given value of $x$ is a zero (or root) of the provided linear polynomial. The given parameters are:
- Polynomial: $p(x) = 2x + 1$
- Value to verify: $x = \frac{1}{2}$
[Theoretical Justification: By the fundamental definition of polynomials, a real number $c$ is considered a "zero" of a polynomial $p(x)$ if and only if evaluating the polynomial at $x = c$ yields a result of zero. Mathematically, this is expressed as $p(c) = 0$.]
Step 1: Substitution of the Given Value
To test the condition $p(c) = 0$, we substitute $x = \frac{1}{2}$ into the polynomial $p(x)$.
$p\left(\frac{1}{2}\right) = 2\left(\frac{1}{2}\right) + 1$
Step 2: Algebraic Evaluation
Next, we perform the arithmetic operations following the standard order of operations (PEMDAS/BODMAS).
First, multiply the terms:
$2 \times \frac{1}{2} = 1$
Now, substitute this product back into the expression:
$p\left(\frac{1}{2}\right) = 1 + 1$
$p\left(\frac{1}{2}\right) = 2$
Step 3: Logical Verification
We must now compare our evaluated result with the required condition for a zero.
$p\left(\frac{1}{2}\right) = 2 \neq 0$
[Since the polynomial evaluates to $2$ rather than $0$, the value $x = \frac{1}{2}$ fails the condition $p(c) = 0$.]
Graphical Representation & Geometric Proof
Geometrically, the zeroes of a polynomial $p(x)$ correspond to the $x$-intercepts of its graph $y = p(x)$. The graph below plots the linear function $y = 2x + 1$. Notice that the true zero occurs where the line crosses the x-axis at $x = -\frac{1}{2}$, whereas evaluating at $x = \frac{1}{2}$ yields a y-coordinate of $2$.
Final Conclusion
Because the evaluation of the polynomial at the given value does not result in zero, the value is not a root of the equation.
Final Solution: No, $x = \frac{1}{2}$ is not a zero of the polynomial $p(x) = 2x + 1$, because $p\left(\frac{1}{2}\right) = 2 \neq 0$.
More Questions from Class 9 Mathematics Polynomials EXERCISE 2.2
- Q1(i): Find the value of the polynomial $5x – 4x^2 + 3$ at (i) $x = 0$
- Q1(ii): Find the value of the polynomial $5x – 4x^2 + 3$ at (ii) $x = –1$
- Q1(iii): Find the value of the polynomial $5x – 4x^2 + 3$ at (iii) $x = 2$
- Q2(i): Find $p(0)$, $p(1)$ and $p(2)$ for each of the following polynomials: (i) $p(y) = y^2 – y + 1$
- Q2(ii): Find $p(0)$, $p(1)$ and $p(2)$ for each of the following polynomials: (ii) $p(t) = 2 + t + 2t^2 – t^3$
- Q2(iii): Find $p(0)$, $p(1)$ and $p(2)$ for each of the following polynomials: (iii) $p(x) = x^3$
- Q2(iv): Find $p(0)$, $p(1)$ and $p(2)$ for each of the following polynomials: (iv) $p(x) = (x – 1) (x + 1)$
- Q3(i): Verify whether the following are zeroes of the polynomial, indicated against them. (i) $p(x) = 3x + 1, x = –\frac{1}{3}$
- Q3(ii): Verify whether the following are zeroes of the polynomial, indicated against them. (ii) $p(x) = 5x – \pi, x = \frac{4}{5}$
- Q3(iii): Verify whether the following are zeroes of the polynomial, indicated against them. (iii) $p(x) = x^2 – 1, x = 1, –1$
- Q3(iv): Verify whether the following are zeroes of the polynomial, indicated against them. (iv) $p(x) = (x + 1) (x – 2), x = – 1, 2$
- Q3(v): Verify whether the following are zeroes of the polynomial, indicated against them. (v) $p(x) = x^2, x = 0$
- Q3(vi): Verify whether the following are zeroes of the polynomial, indicated against them. (vi) $p(x) = lx + m, x = –\frac{m}{l}$
- Q3(vii): Verify whether the following are zeroes of the polynomial, indicated against them. (vii) $p(x) = 3x^2 – 1, x = –\frac{1}{\sqrt{3}}, \frac{2}{\sqrt{3}}$
- Q4(i): Find the zero of the polynomial in each of the following cases: (i) $p(x) = x + 5$
- Q4(ii): Find the zero of the polynomial in each of the following cases: (ii) $p(x) = x – 5$
- Q4(iii): Find the zero of the polynomial in each of the following cases: (iii) $p(x) = 2x + 5$
- Q4(iv): Find the zero of the polynomial in each of the following cases: (iv) $p(x) = 3x – 2$
- Q4(v): Find the zero of the polynomial in each of the following cases: (v) $p(x) = 3x$
- Q4(vi): Find the zero of the polynomial in each of the following cases: (vi) $p(x) = ax, a \neq 0$
- Q4(vii): Find the zero of the polynomial in each of the following cases: (vii) $p(x) = cx + d, c \neq 0, c, d$ are real numbers.
CBSE Solutions for Class 9 Mathematics Polynomials
Chapters in CBSE - Class 9 Mathematics
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