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Q3(iv):
Verify whether the following are zeroes of the polynomial, indicated against them. (iv) $p(x) = (x + 1) (x – 2), x = – 1, 2$

Solution :

Initial Setup & Theoretical Foundation

We are given the polynomial function:

$p(x) = (x + 1)(x - 2)$

We must verify whether the given values, $x = -1$ and $x = 2$, are zeroes of the polynomial.

[By the Fundamental Definition of a Zero of a Polynomial: A real number $a$ is a zero of a polynomial $p(x)$ if and only if evaluating the polynomial at $x = a$ yields zero, i.e., $p(a) = 0$.]

Step 1: Evaluating the Polynomial at $x = -1$

To determine if $x = -1$ is a zero, we substitute $-1$ for every instance of $x$ in the polynomial $p(x)$.

  • Substitute $x = -1$:
    $p(-1) = (-1 + 1)(-1 - 2)$
  • Simplify the terms within the parentheses:
    $p(-1) = (0)(-3)$
  • Apply the Zero Property of Multiplication [Any number multiplied by zero equals zero]:
    $p(-1) = 0$

Since $p(-1) = 0$, we mathematically confirm that $x = -1$ is a zero of the polynomial $p(x)$.

Step 2: Evaluating the Polynomial at $x = 2$

Next, we apply the same substitution methodology for $x = 2$.

  • Substitute $x = 2$:
    $p(2) = (2 + 1)(2 - 2)$
  • Simplify the terms within the parentheses:
    $p(2) = (3)(0)$
  • Apply the Zero Property of Multiplication:
    $p(2) = 0$

Since $p(2) = 0$, we mathematically confirm that $x = 2$ is also a zero of the polynomial $p(x)$.

Graphical Verification

The polynomial $p(x) = (x + 1)(x - 2)$ expands to the quadratic form $p(x) = x^2 - x - 2$. Geometrically, the zeroes of a polynomial correspond to the $x$-intercepts of its graph. The precise Cartesian plot below demonstrates the parabola intersecting the $x$-axis exactly at the coordinates $(-1, 0)$ and $(2, 0)$.

x p(x) 0 (-1, 0) (2, 0) Vertex (0.5, -2.25) p(x) = (x+1)(x-2)

Final Solution: Yes, both $x = -1$ and $x = 2$ are zeroes of the polynomial $p(x) = (x + 1)(x - 2)$, as evaluating the polynomial at both values yields exactly $0$.


More Questions from Class 9 Mathematics Polynomials EXERCISE 2.2


CBSE Solutions for Class 9 Mathematics Polynomials


Chapters in CBSE - Class 9 Mathematics


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