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Q2(iv):
Write the coefficients of $x^2$ in each of the following: (iv) $\sqrt{2}x - 1$

Solution :

Initial Setup & Theoretical Foundation

We are given the algebraic expression:

$P(x) = \sqrt{2}x - 1$

Our objective is to determine the coefficient of the $x^2$ term within this polynomial. [By definition, a coefficient is the numerical multiplier of a variable in a specific term of an algebraic expression].

Step 1: Analyzing the Degree and Terms of the Polynomial

The given polynomial, $P(x) = \sqrt{2}x - 1$, consists of two explicitly written terms:

  • The linear term: $\sqrt{2}x$, where the variable $x$ is raised to the power of $1$. The coefficient here is $\sqrt{2}$.
  • The constant term: $-1$, which can be mathematically expressed as $-1x^0$.

Because the highest power of the variable $x$ present in the expression is $1$, this is classified as a linear polynomial (degree $1$).

Step 2: Expressing the Polynomial in Standard Form

To rigorously identify the coefficient of a term that does not explicitly appear in the expression (in this case, the $x^2$ term), we must rewrite the polynomial in its complete standard descending form. [Per the axioms of polynomial representation, any missing term of degree $k$ can be introduced into the expression by multiplying it by zero ($0 \cdot x^k$), because adding the additive identity ($0$) does not alter the intrinsic value of the polynomial].

We expand $P(x)$ to explicitly include the quadratic ($x^2$) term:

$P(x) = 0 \cdot x^2 + \sqrt{2}x - 1$

Step 3: Visualizing the Polynomial Structure

The diagram below illustrates the structural breakdown of the polynomial when expanded to include the quadratic term, isolating the coefficient for each degree of $x$.

0x2 Coefficient = 0 (Missing Term) + √2 x Coefficient = √2 (Linear Term) - 1 Constant = -1 (Degree 0 Term)

Step 4: Extracting the Target Coefficient

By comparing our expanded polynomial $P(x) = 0x^2 + \sqrt{2}x - 1$ with the general quadratic form $ax^2 + bx + c$, we can map the coefficients directly:

  • $a$ (coefficient of $x^2$) = $0$
  • $b$ (coefficient of $x$) = $\sqrt{2}$
  • $c$ (constant term) = $-1$

Since the $x^2$ term is entirely absent from the original expression, its numerical multiplier must be zero.

Final Solution: The coefficient of $x^2$ in the polynomial $\sqrt{2}x - 1$ is $0$.


More Questions from Class 9 Mathematics Polynomials EXERCISE 2.1


CBSE Solutions for Class 9 Mathematics Polynomials


Chapters in CBSE - Class 9 Mathematics


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