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Q2(ii):
Write the coefficients of $x^2$ in each of the following: (ii) $2 – x^2 + x^3$

Solution :

Given Polynomial & Initial Setup

We are given the algebraic expression:

$P(x) = 2 - x^2 + x^3$

Our objective is to determine the numerical coefficient of the $x^2$ term within this polynomial.

Step 1: Understanding Polynomial Terms and Standard Form

[Per the algebraic definition of a polynomial], an expression is composed of distinct terms separated by addition ($+$) or subtraction ($-$) operators. To analyze the polynomial systematically, it is best practice to rewrite it in standard form, where the terms are ordered by descending powers of the variable $x$.

Rearranging $P(x)$ yields:

$P(x) = x^3 - x^2 + 2$

Step 2: Isolating the Target Term

We must identify the specific term that contains the variable $x^2$. By dissecting the polynomial into its constituent terms, we get:

  • Cubic term: $+x^3$
  • Quadratic term: $-x^2$
  • Constant term: $+2$

The target term containing $x^2$ is explicitly $-x^2$.

Step 3: Extracting the Numerical Coefficient

[By the fundamental axioms of algebra], the coefficient is the constant multiplicative factor attached to a variable in a specific term. When a variable appears without an explicit numerical multiplier but carries a negative sign, the multiplicative identity property dictates that the hidden multiplier is $-1$.

We can expand the target term algebraically to reveal its coefficient:

$-x^2 = (-1) \cdot x^2$

Thus, the numerical factor multiplying $x^2$ is $-1$.

Visual Breakdown of the Polynomial Terms

2 Constant -x² Target Term +x³ Cubic Term (-1) · x² Coefficient = -1

Final Solution: The coefficient of $x^2$ in the polynomial $2 - x^2 + x^3$ is $-1$.


More Questions from Class 9 Mathematics Polynomials EXERCISE 2.1


CBSE Solutions for Class 9 Mathematics Polynomials


Chapters in CBSE - Class 9 Mathematics


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