Find the best tutors and institutes for Class 10 Tuition
Q2(ii):
Write four solutions for each of the following equations:
(ii) $\pi x + y = 9$
Solution :
Initial Setup & Algebraic Formulation
We are tasked with finding four distinct solutions for the following linear equation in two variables:
$\pi x + y = 9$
A linear equation in two variables has infinitely many solutions. A solution is defined as an ordered pair $(x, y)$ that satisfies the equation. To systematically generate these solutions, we will express one variable in terms of the other.
Step 1: Isolating the Dependent Variable
To make the calculation of ordered pairs straightforward, we isolate the dependent variable ($y$) in terms of the independent variable ($x$). [Per the Subtraction Property of Equality, subtracting $\pi x$ from both sides of the equation yields:]
$y = 9 - \pi x$
We can now substitute arbitrary real numbers for $x$ to compute the corresponding exact values of $y$.
Step 2: Deriving the First Solution
Let us assign $x = 0$. Substituting this value into our isolated equation:
$y = 9 - \pi(0)$
$y = 9 - 0$
$y = 9$
Thus, the first solution is the ordered pair $(0, 9)$. [This point also represents the y-intercept of the linear graph].
Step 3: Deriving the Second Solution
Let us assign $x = 1$. Substituting this value into the equation:
$y = 9 - \pi(1)$
$y = 9 - \pi$
Thus, the second solution is the ordered pair $(1, 9 - \pi)$.
Step 4: Deriving the Third Solution
Let us assign $x = 2$. Substituting this value into the equation:
$y = 9 - \pi(2)$
$y = 9 - 2\pi$
Thus, the third solution is the ordered pair $(2, 9 - 2\pi)$.
Step 5: Deriving the Fourth Solution
Let us assign $x = -1$. Substituting this value into the equation:
$y = 9 - \pi(-1)$
$y = 9 + \pi$
Thus, the fourth solution is the ordered pair $(-1, 9 + \pi)$.
Step 6: Tabular Summary of Solutions
We can organize the derived solutions into a Cartesian coordinate table. This demonstrates the linear relationship and prepares the data for graphical representation.
| Independent Variable ($x$) | Dependent Variable ($y$) | Ordered Pair $(x, y)$ |
|---|---|---|
| $0$ | $9$ | $(0, 9)$ |
| $1$ | $9 - \pi$ | $(1, 9 - \pi)$ |
| $2$ | $9 - 2\pi$ | $(2, 9 - 2\pi)$ |
| $-1$ | $9 + \pi$ | $(-1, 9 + \pi)$ |
Step 7: Graphical Representation of the Linear Equation
Below is the geometric interpretation of the equation $\pi x + y = 9$ plotted on a Cartesian plane. The line represents the locus of all infinite solutions, with our four specific calculated points highlighted. (Note: For spatial plotting purposes, $\pi$ is approximated as $3.14$).
Final Solution: Four valid solutions for the equation $\pi x + y = 9$ are $(0, 9)$, $(1, 9 - \pi)$, $(2, 9 - 2\pi)$, and $(-1, 9 + \pi)$.
More Questions from Class 9 Mathematics Linear Equations in Two Variables EXERCISE 4.2
- Q1: Which one of the following options is true, and why? $y = 3x + 5$ has
- Q2(i): Write four solutions for each of the following equations: (i) $2x + y = 7$
- Q2(iii): Write four solutions for each of the following equations: (iii) $x = 4y$
- Q3(i): Check which of the following are solutions of the equation $x - 2y = 4$ and which are not: (i) $(0, 2)$
- Q3(ii): Check which of the following are solutions of the equation $x - 2y = 4$ and which are not: (ii) $(2, 0)$
- Q3(iii): Check which of the following are solutions of the equation $x - 2y = 4$ and which are not: (iii) $(4, 0)$
- Q3(iv): Check which of the following are solutions of the equation $x - 2y = 4$ and which are not: (iv) $(\sqrt{2}, 4\sqrt{2})$
- Q3(v): Check which of the following are solutions of the equation $x - 2y = 4$ and which are not: (v) $(1, 1)$
- Q4: Find the value of $k$, if $x = 2$, $y = 1$ is a solution of the equation $2x + 3y = k$.
CBSE Solutions for Class 9 Mathematics Linear Equations in Two Variables
Chapters in CBSE - Class 9 Mathematics
Top Tutors who teach Linear Equations in Two Variables
I specialize in Class 10 Mathematics tuition with an exam-oriented and concept-based teaching approach. I simplify complex mathematical concepts using step-by-step explanations, making them easy for students to understand and apply confidently. I assess each student's learning level, identify weak areas, and provide personalized guidance to improve both accuracy and speed. My classes include regular practice, chapter-wise tests, previous years' board exam questions, doubt-clearing sessions, and effective exam strategies. I maintain a friendly and motivating learning environment where students feel comfortable asking questions. My objective is to help every student strengthen their mathematical foundation, gain confidence, and achieve excellent results in the Class 10 board examinations.
Experienced Mathematics tutor with a strong focus on concept-based learning. I help students improve their understanding, problem-solving skills, and academic performance through personalized guidance.
Dear Parents and students, I am Amit, We provide home-based tuition for subjects and we also do professional coaching for NEET/IIT-JEE and other competitive exams. We have experienced tutors in all the fields and subjects. We also provide demo class free of cost. We do online as well as offline mode of teaching...
I have taught Grade 10 students mathematics
Dedicated and passionate educator with over 10 years of experience teaching Mathematics and Science to students of Classes 8th to 12th across multiple boards — CBSE, ICSE, IGCSE, IB MYP, and IBDP. Founder of Ishaan Tuitions, Pune, specializing in personalized one-to-one coaching and small group sessions designed to strengthen conceptual understanding and academic performance. Expertise also includes preparing students for competitive examinations such as SAT and IIT-JEE Mains, with a strong record of improving analytical thinking and problem-solving abilities.
My experience is very good with sachin sir his way of teaching I love and my thanks to Urbanpro also to help me to take me to such a good teacher
I have worked as PGT teacher in one of the best CBSE schools and all of my students gained more than 90 percent marks. I have full concept of subjects and can assist students in gaining more than 90 percent marks.
She’s a excellent teacher , her behaviour her talking style is very sweet and if you didn’t understand any topic she’ll repeat it for you as many times you want!! Satisfied and loved her teaching
Find more Tutor for Linear Equations in Two Variables in your City
- Bangalore Mathematics Tutors
- Delhi Mathematics Tutors
- Chennai Mathematics Tutors
- Gurgaon Mathematics Tutors
- Noida Mathematics Tutors
- Hyderabad Mathematics Tutors
- Mumbai Mathematics Tutors
- Chandigarh Mathematics Tutors
- Pune Mathematics Tutors
- Ghaziabad Mathematics Tutors
- Jaipur Mathematics Tutors
- Surat Mathematics Tutors
Download free CBSE - Class 9 Mathematics Linear Equations in Two Variables EXERCISE 4.2 worksheets
Download Now