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Post a LessonAnswered on 24/02/2024 Learn CBSE - Class 6/Maths/Practical Geometry
Sadika
To construct a line segment equal to AB+CDAB+CD, you would first draw a line segment ABAB with a length of 3.6 cm and then draw a line segment CDCD with a length of 1.6 cm.
Then, you would place the endpoint of CDCD at the endpoint of ABAB, so they connect end to end. The resulting line segment would be the sum of the lengths of ABAB and CDCD.
Now, to measure the total length of the constructed line segment:
Total length=AB+CD=3.6 cm+1.6 cm=5.2 cmTotal length=AB+CD=3.6 cm+1.6 cm=5.2 cm
So, the total length of the constructed line segment is 5.2 cm.
Answered on 24/02/2024 Learn CBSE - Class 6/Maths/Practical Geometry
Sadika
To construct a perpendicular to a given line segment at a point on it, you can follow these steps:
Now, you have constructed a perpendicular to the given line segment at the chosen point PP.
Answered on 24/02/2024 Learn CBSE - Class 6/Maths/Practical Geometry
Sadika
To construct an angle of 60 degrees and bisect it, you can follow these steps using a compass and straightedge:
Now, you have constructed an angle of 60 degrees and bisected it into two 30-degree angles.
Answered on 24/02/2024 Learn CBSE - Class 6/Maths/Practical Geometry
Sadika
To draw an angle of 120° and then construct an angle of 105°, follow these steps:
Draw an Angle of 120°:
Construct an Angle of 105°:
Now, you have both the 120° angle and the constructed 105° angle.
Answered on 24/02/2024 Learn CBSE - Class 6/Maths/Practical Geometry
Sadika
To draw triangle ABC and its perpendiculars from each vertex onto the opposite sides, follow these steps:
Draw triangle ABC:
Draw perpendiculars from each vertex onto the opposite sides:
Now, you have triangle ABC with perpendiculars AD, BE, and CF drawn from vertices A, B, and C respectively onto the opposite sides BC, AC, and AB.
To determine if these perpendiculars are concurrent (passing through the same point), you can construct the altitudes of the triangle, which are known to be concurrent at the orthocenter.
If the perpendiculars AD, BE, and CF intersect at a single point, then they are concurrent, and that point is the orthocenter of triangle ABC. If they do not intersect at a single point, then they are not concurrent.
Please note that the concurrency of perpendiculars in a triangle depends on the specific properties of the triangle. In some cases, the perpendiculars may be concurrent, while in others, they may not be. You would need to verify this for the specific triangle you've drawn.
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