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algebra relates to CBSE - Class 6/Maths

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S. hemaa Class 6 Tuition trainer in Bangalore Featured
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Diptee Mishra Class 6 Tuition trainer in Nagpur Featured
Manewada, Nagpur
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I have 6 years of experience teaching middle school students, including Class VI, with a strong focus on concept clarity in Mathematics, Science,...

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Villivakkam, Chennai
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I started teaching 20 yrs back when the parents of my students insisted me to teach for higher classes also. I love teaching because my students...

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Debdeep B. Class 6 Tuition trainer in Bangalore Featured
J P Nagar, Bangalore
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Saurabh Kr hari Class 6 Tuition trainer in Patna Featured
Rukanpura, Patna
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I am a passionate Science and Maths teacher with 3--4 years of experience. I focus on making learning clear, engaging, and practical, while creating...

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RK Puram Sector 9, Delhi
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I am a tutor, teaches till tenth 10th classes and economics to class 11 and 12th. My teaching experience is of 4 years. I started teaching in a institute...

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Indira B. Class 6 Tuition trainer in Vadodara Featured
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My experience in teaching Class 6th students following CBSE curriculum has been superb. I taught them all subjects offline with regular tests and...

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Pankaj Saw Class 6 Tuition trainer in Pune Featured
Mundhwa, Pune
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500per hour
Classes: Class 6 Tuition, SAT Coaching and more.

I am an experienced tutor with extensive experience in teaching Class 6 students, particularly in mathematics and science. My teaching approach is...

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Answered on 23/02/2024 Learn CBSE - Class 6/Maths/algebra/Introduction to formation of Variables

Sadika

To find Rahul's total score in English and Hindi, you simply add his scores in both subjects. Given: English score = 80 Hindi score = x Total score = English score + Hindi score Total score = 80 + x So, Rahul's total score in the two subjects is 80 + x. read more

To find Rahul's total score in English and Hindi, you simply add his scores in both subjects.

Given: English score = 80 Hindi score = x

Total score = English score + Hindi score Total score = 80 + x

So, Rahul's total score in the two subjects is 80 + x.

 
 
 
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Answered on 23/02/2024 Learn CBSE - Class 6/Maths/algebra/Introduction to formation of Variables

Sadika

To find out how much distance Rohit covers in yy steps, you simply multiply the distance covered in one step (xx centimeters) by the number of steps (yy). Given: Distance covered in one step (xx) = xx centimeters Number of steps (yy) = yy Distance covered = Distance covered in one step * Number of... read more

To find out how much distance Rohit covers in yy steps, you simply multiply the distance covered in one step (xx centimeters) by the number of steps (yy).

Given: Distance covered in one step (xx) = xx centimeters Number of steps (yy) = yy

Distance covered = Distance covered in one step * Number of steps Distance covered = xx * yy

So, Rohit covers x×yx×y centimeters in yy steps.

 
 
 
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Answered on 23/02/2024 Learn CBSE - Class 6/Maths/algebra/Introduction to formation of Variables

Sadika

To determine the total weight of xx apples and yy oranges, you'll need to multiply the weight of each type of fruit by the respective quantity and then sum the results. Given: Weight of one apple (aa) = 75 grams Weight of one orange (oo) = 40 grams Quantity of apples (xx) Quantity of oranges (yy) Total... read more

To determine the total weight of xx apples and yy oranges, you'll need to multiply the weight of each type of fruit by the respective quantity and then sum the results.

Given: Weight of one apple (aa) = 75 grams Weight of one orange (oo) = 40 grams Quantity of apples (xx) Quantity of oranges (yy)

Total weight = (Weight of one apple * Quantity of apples) + (Weight of one orange * Quantity of oranges) Total weight = (75×x)+(40×y)(75×x)+(40×y)

So, the total weight of xx apples and yy oranges is 75x+40y75x+40y grams.

 
 
 
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Answered on 23/02/2024 Learn CBSE - Class 6/Maths/algebra/Introduction to formation of Variables

Sadika

To determine the total cost of xx pencils and yy fountain pens, you'll multiply the cost of each item by the respective quantity and then sum the results. Given: Cost of one pencil (pp) = Rs 2 Cost of one fountain pen (ff) = Rs 15 Quantity of pencils (xx) Quantity of fountain pens (yy) Total... read more

To determine the total cost of xx pencils and yy fountain pens, you'll multiply the cost of each item by the respective quantity and then sum the results.

Given: Cost of one pencil (pp) = Rs 2 Cost of one fountain pen (ff) = Rs 15 Quantity of pencils (xx) Quantity of fountain pens (yy)

Total cost = (Cost of one pencil * Quantity of pencils) + (Cost of one fountain pen * Quantity of fountain pens) Total cost = (2×x)+(15×y)(2×x)+(15×y)

So, the total cost of xx pencils and yy fountain pens is 2x+15y2x+15y rupees.

 
 

 
 
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Answered on 23/02/2024 Learn CBSE - Class 6/Maths/algebra/Introduction to formation of Variables

Sadika

Let's denote: Length of the rectangle = 2332 of its breadth Breadth of the rectangle = xx cm Then, we can express the length of the rectangle in terms of its breadth: Length=23×BreadthLength=32×Breadth Length=23×xLength=32×x Length=2x3Length=32x Now, we can calculate the area... read more

Let's denote: Length of the rectangle = 2332 of its breadth Breadth of the rectangle = xx cm

Then, we can express the length of the rectangle in terms of its breadth: Length=23×BreadthLength=32×Breadth Length=23×xLength=32×x Length=2x3Length=32x

Now, we can calculate the area of the rectangle: Area=Length×BreadthArea=Length×Breadth Area=(2x3)×xArea=(32x)×x Area=2x23Area=32x2

So, the area of the rectangle is 2x2332x2 square centimeters.

 
 
 
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