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Post a LessonAnswered on 06/04/2024 Learn CBSE - Class 12/Mathematics/Unit III: Calculus
Sadika
Inverse trigonometric functions are functions that "undo" the effects of trigonometric functions. They provide a way to find the angle (or value) associated with a given trigonometric ratio. Inverse trigonometric functions are denoted by \(\sin^{-1}(x)\), \(\cos^{-1}(x)\), \(\tan^{-1}(x)\), \(\cot^{-1}(x)\), \(\sec^{-1}(x)\), and \(\csc^{-1}(x)\), representing arcsine, arccosine, arctangent, arccotangent, arcsecant, and arccosecant, respectively.
Here's a brief explanation of each inverse trigonometric function:
1. **arcsin (or \(\sin^{-1}(x)\))**: Gives the angle whose sine is \(x\), where \(x\) is between -1 and 1.
2. **arccos (or \(\cos^{-1}(x)\))**: Gives the angle whose cosine is \(x\), where \(x\) is between -1 and 1.
3. **arctan (or \(\tan^{-1}(x)\))**: Gives the angle whose tangent is \(x\).
4. **arccot (or \(\cot^{-1}(x)\))**: Gives the angle whose cotangent is \(x\).
5. **arcsec (or \(\sec^{-1}(x)\))**: Gives the angle whose secant is \(x\), where \(x \geq 1\) or \(x \leq -1\).
6. **arccsc (or \(\csc^{-1}(x)\))**: Gives the angle whose cosecant is \(x\), where \(x \geq 1\) or \(x \leq -1\).
It's important to note that the range of inverse trigonometric functions is restricted to ensure that they are single-valued and have unique inverses. The specific range depends on the convention used, but commonly accepted ranges are as follows:
- For arcsin and arccos: \(-\frac{\pi}{2} \leq \theta \leq \frac{\pi}{2}\) (or \(-90^\circ \leq \theta \leq 90^\circ\)).
- For arctan: \(-\frac{\pi}{2} < \theta < \frac{\pi}{2}\) (or \(-90^\circ < \theta < 90^\circ\)).
- For arccot: \(0 < \theta < \pi\) (or \(0^\circ < \theta < 180^\circ\)).
- For arcsec and arccsc: \(0 \leq \theta < \frac{\pi}{2}\) and \(\frac{\pi}{2} < \theta \leq \pi\) (or \(0^\circ \leq \theta < 90^\circ\) and \(90^\circ < \theta \leq 180^\circ\)).
These functions are essential in solving trigonometric equations, modeling periodic phenomena, and various applications in science, engineering, and mathematics.
read lessAnswered on 06/04/2024 Learn CBSE - Class 12/Mathematics/Unit III: Calculus
Sadika
read less
Answered on 06/04/2024 Learn CBSE - Class 12/Mathematics/Unit III: Calculus
Sadika
To determine the principal value of
Answered on 01/03/2024 Learn CBSE - Class 12/Mathematics/Unit III: Calculus
Kalaiselvi
Online Mathematics tutor with 8 years experience(Online Classes for 10th to 12th)
Let sin-1(3/5) = x and sin-1(8/17) = y
Therefore sinx = 3/5 and siny = 8/17
Now, cosx = √(1 - sin2x) = √(1 - (3/5)2) = √(1 - 9/25) = 4/5 and cosy = √(1 - sin2y) = √(1 - (8/17)2) = √(1 - 64/289) = 15/17
We have cos(x - y) = cosx cosy + sinx siny = 4/5 x 15/17 + 3/5 x 8/17 = 60/85 + 24/85 = 84/85 ⇒ x - y = cos-1(84/85) ⇒ sin-1(3/5) - sin-1(8/17) = cos-1(84/85)
read lessAnswered on 01/03/2024 Learn CBSE - Class 12/Mathematics/Unit III: Calculus
Kalaiselvi
Online Mathematics tutor with 8 years experience(Online Classes for 10th to 12th)
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