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Unit III: Calculus

Unit III: Calculus relates to CBSE/Class 12/Mathematics

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Unit III: Calculus Questions

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Answered on 06/04/2024 Learn CBSE/Class 12/Mathematics/Unit III: Calculus

Sadika

Inverse trigonometric functions are functions that "undo" the effects of trigonometric functions. They provide a way to find the angle (or value) associated with a given trigonometric ratio. Inverse trigonometric functions are denoted by \(\sin^{-1}(x)\), \(\cos^{-1}(x)\), \(\tan^{-1}(x)\), \(\cot^{-1}(x)\),... read more

Inverse trigonometric functions are functions that "undo" the effects of trigonometric functions. They provide a way to find the angle (or value) associated with a given trigonometric ratio. Inverse trigonometric functions are denoted by \(\sin^{-1}(x)\), \(\cos^{-1}(x)\), \(\tan^{-1}(x)\), \(\cot^{-1}(x)\), \(\sec^{-1}(x)\), and \(\csc^{-1}(x)\), representing arcsine, arccosine, arctangent, arccotangent, arcsecant, and arccosecant, respectively.

Here's a brief explanation of each inverse trigonometric function:

1. **arcsin (or \(\sin^{-1}(x)\))**: Gives the angle whose sine is \(x\), where \(x\) is between -1 and 1.

2. **arccos (or \(\cos^{-1}(x)\))**: Gives the angle whose cosine is \(x\), where \(x\) is between -1 and 1.

3. **arctan (or \(\tan^{-1}(x)\))**: Gives the angle whose tangent is \(x\).

4. **arccot (or \(\cot^{-1}(x)\))**: Gives the angle whose cotangent is \(x\).

5. **arcsec (or \(\sec^{-1}(x)\))**: Gives the angle whose secant is \(x\), where \(x \geq 1\) or \(x \leq -1\).

6. **arccsc (or \(\csc^{-1}(x)\))**: Gives the angle whose cosecant is \(x\), where \(x \geq 1\) or \(x \leq -1\).

It's important to note that the range of inverse trigonometric functions is restricted to ensure that they are single-valued and have unique inverses. The specific range depends on the convention used, but commonly accepted ranges are as follows:

- For arcsin and arccos: \(-\frac{\pi}{2} \leq \theta \leq \frac{\pi}{2}\) (or \(-90^\circ \leq \theta \leq 90^\circ\)).
- For arctan: \(-\frac{\pi}{2} < \theta < \frac{\pi}{2}\) (or \(-90^\circ < \theta < 90^\circ\)).
- For arccot: \(0 < \theta < \pi\) (or \(0^\circ < \theta < 180^\circ\)).
- For arcsec and arccsc: \(0 \leq \theta < \frac{\pi}{2}\) and \(\frac{\pi}{2} < \theta \leq \pi\) (or \(0^\circ \leq \theta < 90^\circ\) and \(90^\circ < \theta \leq 180^\circ\)).

These functions are essential in solving trigonometric equations, modeling periodic phenomena, and various applications in science, engineering, and mathematics.

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Answered on 06/04/2024 Learn CBSE/Class 12/Mathematics/Unit III: Calculus

Sadika

We know, tan−1a+cot−1a=π2 Therefore, cot(tan−1a+cot−1a)=cotπ2=0 read more

We know,

tan1a+cot1a=π2
 
Therefore,
cot(tan1a+cot1a)=cotπ2=0

 

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Answered on 06/04/2024 Learn CBSE/Class 12/Mathematics/Unit III: Calculus

Sadika

To determine the principal value of read more

To determine the principal value of

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Answered on 01/03/2024 Learn CBSE/Class 12/Mathematics/Unit III: Calculus

Kalaiselvi

Online Mathematics tutor with 6 years experience(Online Classes for 10th to 12th)

Let sin-1(3/5) = x and sin-1(8/17) = y Therefore sinx = 3/5 and siny = 8/17 Now, cosx = √(1 - sin2x) = √(1 - (3/5)2) = √(1 - 9/25) = 4/5 and cosy = √(1 - sin2y) = √(1 - (8/17)2) = √(1 - 64/289) = 15/17 We have cos(x - y) = cosx cosy + sinx siny = 4/5 x 15/17 + 3/5... read more

Let sin-1(3/5) = x and sin-1(8/17) = y

Therefore  sinx = 3/5 and siny = 8/17

Now, cosx = √(1 - sin2x) = √(1 - (3/5)2) = √(1 - 9/25) = 4/5 and cosy = √(1 - sin2y) = √(1 - (8/17)2) = √(1 - 64/289) = 15/17

We have cos(x - y) = cosx cosy + sinx siny  = 4/5 x 15/17 + 3/5 x 8/17 = 60/85 + 24/85 = 84/85 ⇒ x - y = cos-1(84/85) ⇒ sin-1(3/5) - sin-1(8/17) = cos-1(84/85)

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Answered on 01/03/2024 Learn CBSE/Class 12/Mathematics/Unit III: Calculus

Kalaiselvi

Online Mathematics tutor with 6 years experience(Online Classes for 10th to 12th)

2π/3 is the answer
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