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Q2(i):
Check the injectivity and surjectivity of the following functions: (i) $f : N \to N$ given by $f(x) = x^2$
Solution :
Step 1: Formal Definition of the Function
The function is defined as $f: \mathbb{N} \to \mathbb{N}$, where $\mathbb{N} = \{1, 2, 3, \dots\}$. The rule governing the mapping is given by $f(x) = x^2$.
Step 2: Analysis of Injectivity (One-to-One)
A function is injective if $f(x_1) = f(x_2)$ implies $x_1 = x_2$ for all $x_1, x_2$ in the domain. [Per the definition of Injective Functions].
Consider $f(x_1) = f(x_2)$:
$x_1^2 = x_2^2$
Taking the square root of both sides: $\sqrt{x_1^2} = \sqrt{x_2^2} \implies |x_1| = |x_2|$.
Since the domain is $\mathbb{N}$ (natural numbers), both $x_1$ and $x_2$ must be positive. Therefore, $x_1 = x_2$.
Example check: Let $x_1 = 2, x_2 = 3$. $f(2) = 4, f(3) = 9$. Since $2 \neq 3 \implies 4 \neq 9$.
Conclusion: The function is injective.
Step 3: Analysis of Surjectivity (Onto)
A function is surjective if the Range of $f$ is equal to the Codomain of $f$. [Per the definition of Surjective Functions].
The codomain is $\mathbb{N} = \{1, 2, 3, 4, 5, \dots\}$.
The range of $f(x) = x^2$ for $x \in \mathbb{N}$ is $\{1^2, 2^2, 3^2, \dots\} = \{1, 4, 9, 16, \dots\}$.
We observe that there exist elements in the codomain that have no pre-image in the domain. For example, $2 \in \text{Codomain}$, but there is no $x \in \mathbb{N}$ such that $x^2 = 2$ (as $\sqrt{2} \notin \mathbb{N}$).
Since $\text{Range} \subset \text{Codomain}$ but $\text{Range} \neq \text{Codomain}$, the function is not surjective.
Step 4: Summary Table
| Property | Status | Reasoning |
|---|---|---|
| Injectivity | Injective | $f(x_1) = f(x_2) \implies x_1 = x_2$ for all $x \in \mathbb{N}$ |
| Surjectivity | Not Surjective | $2 \in \mathbb{N}$ has no pre-image in $\mathbb{N}$ |
Final Solution: The function $f: \mathbb{N} \to \mathbb{N}$ given by $f(x) = x^2$ is injective but not surjective.
More Questions from Class 12 Mathematics Relations and Functions EXERCISE 1.2
- Q1: Show that the function $f : R_{*} \to R_{*}$ defined by $f(x) = \frac{1}{x}$ is one-one and onto, where $R_{*}$ is the set of all non-zero real numbers. Is the result true, if the domain $R_{*}$ is replaced by $N$ with co-domain being same as $R_{*}$?
- Q2(ii): Check the injectivity and surjectivity of the following functions: (ii) $f : Z \to Z$ given by $f(x) = x^2$
- Q2(iii): Check the injectivity and surjectivity of the following functions: (iii) $f : R \to R$ given by $f(x) = x^2$
- Q2(iv): Check the injectivity and surjectivity of the following functions: (iv) $f : N \to N$ given by $f(x) = x^3$
- Q2(v): Check the injectivity and surjectivity of the following functions: (v) $f : Z \to Z$ given by $f(x) = x^3$
- Q3: Prove that the Greatest Integer Function $f : R \to R$, given by $f(x) = [x]$, is neither one-one nor onto, where $[x]$ denotes the greatest integer less than or equal to $x$.
- Q4: Show that the Modulus Function $f : R \to R$, given by $f(x) = |x|$, is neither one-one nor onto, where $|x|$ is $x$, if $x$ is positive or 0 and $|x|$ is $– x$, if $x$ is negative.
- Q5: Show that the Signum Function $f : R \to R$, given by $f(x) = \begin{cases} 1 & \text{if } x > 0 \\ 0 & \text{if } x = 0 \\ -1 & \text{if } x < 0 \end{cases}$ is neither one-one nor onto.
- Q6: Let $A = \{1, 2, 3\}$, $B = \{4, 5, 6, 7\}$ and let $f = \{(1, 4), (2, 5), (3, 6)\}$ be a function from $A$ to $B$. Show that $f$ is one-one.
- Q7(i): In each of the following cases, state whether the function is one-one, onto or bijective. Justify your answer. (i) $f : R \to R$ defined by $f(x) = 3 – 4x$
- Q7(ii): In each of the following cases, state whether the function is one-one, onto or bijective. Justify your answer. (ii) $f : R \to R$ defined by $f(x) = 1 + x^2$
- Q8: Let $A$ and $B$ be sets. Show that $f : A \times B \to B \times A$ such that $f(a, b) = (b, a)$ is bijective function.
- Q9: Let $f : N \to N$ be defined by $f(n) = \begin{cases} \frac{n+1}{2} & \text{if } n \text{ is odd} \\ \frac{n}{2} & \text{if } n \text{ is even} \end{cases}$ for all $n \in N$. State whether the function $f$ is bijective. Justify your answer.
- Q10: Let $A = R – \{3\}$ and $B = R – \{1\}$. Consider the function $f : A \to B$ defined by $f(x) = \frac{x-2}{x-3}$. Is $f$ one-one and onto? Justify your answer.
- Q11: Let $f : R \to R$ be defined as $f(x) = x^4$. Choose the correct answer.
- Q12: Let $f : R \to R$ be defined as $f(x) = 3x$. Choose the correct answer.
CBSE Solutions for Class 12 Mathematics Relations and Functions
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