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Q11:

Let $f : R \to R$ be defined as $f(x) = x^4$. Choose the correct answer.

Solution :

Step 1: Analyzing the Injectivity (One-to-One Property)

A function $f: A \to B$ is injective (one-to-one) if and only if $f(x_1) = f(x_2) \implies x_1 = x_2$ for all $x_1, x_2 \in A$. [Per the Definition of Injective Functions].

Given $f(x) = x^4$, let us test two distinct values from the domain $R$, such as $x_1 = 1$ and $x_2 = -1$.

  • $f(1) = (1)^4 = 1$
  • $f(-1) = (-1)^4 = 1$

Since $f(1) = f(-1)$ but $1 \neq -1$, the function fails the horizontal line test. [By the failure of the Injectivity Criterion].

Conclusion: The function $f(x) = x^4$ is not one-to-one.

Step 2: Analyzing the Surjectivity (Onto Property)

A function $f: R \to R$ is surjective (onto) if and only if for every $y \in R$ (codomain), there exists an $x \in R$ (domain) such that $f(x) = y$. [Per the Definition of Surjective Functions].

For $f(x) = x^4$, since $x$ is raised to an even power, the output $f(x)$ will always be non-negative for any real input $x$. That is, $f(x) \geq 0$ for all $x \in R$.

Consider a value $y = -2$ in the codomain $R$. There is no real number $x$ such that $x^4 = -2$, because the fourth power of any real number cannot be negative. [By the property of Real Numbers and Exponents].

Conclusion: The function $f(x) = x^4$ is not onto.

Step 3: Visual Representation of the Function

x f(x) 0 f(x) = x^4

Step 4: Comparative Summary

Property Status Reason
One-to-One No $f(1) = f(-1) = 1$
Onto No Range $\subset$ Codomain ($[0, \infty) \subset R$)

Final Solution: The function $f(x) = x^4$ is neither one-to-one nor onto.


More Questions from Class 12 Mathematics Relations and Functions EXERCISE 1.2


CBSE Solutions for Class 12 Mathematics Relations and Functions


Chapters in CBSE - Class 12 Mathematics


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