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Q1:
If A and B are symmetric matrices, prove that AB – BA is a skew symmetric matrix.
Solution :
Given Variables & Initial Setup
Let $A$ and $B$ be two symmetric matrices of the same order $n \times n$.
By the definition of symmetric matrices [Definition of Symmetric Matrices]:
- $A^T = A$
- $B^T = B$
We are required to prove that the matrix $X = AB - BA$ is a skew-symmetric matrix. A matrix $X$ is skew-symmetric if and only if $X^T = -X$ [Definition of Skew-Symmetric Matrices].
Step 1: Applying the Transpose Operation
To determine the nature of $X = AB - BA$, we take the transpose of the entire expression:
$X^T = (AB - BA)^T$
Using the linearity property of the transpose operation, i.e., $(A - B)^T = A^T - B^T$ [Property of Transpose]:
$X^T = (AB)^T - (BA)^T$
Step 2: Expanding via Reversal Law
Utilizing the reversal law of transpose, which states $(PQ)^T = Q^T P^T$ [Reversal Law of Matrix Transpose]:
$X^T = (B^T A^T) - (A^T B^T)$
Step 3: Substitution and Simplification
Substitute the given symmetric properties ($A^T = A$ and $B^T = B$) into the expression:
$X^T = (BA) - (AB)$
To factor out a negative sign and align with the original matrix $X = AB - BA$:
$X^T = -(AB - BA)$
$X^T = -X$
Analytical Conclusion
Since we have demonstrated that $(AB - BA)^T = -(AB - BA)$, the matrix satisfies the fundamental condition for skew-symmetry [Definition of Skew-Symmetric Matrices].
Final Solution: Since the transpose of the matrix (AB - BA) is equal to its negative, the matrix AB - BA is proved to be a skew-symmetric matrix.
More Questions from Class 12 Mathematics Matrices Miscellaneous Exercise on Chapter 3
- Q2: Show that the matrix B′AB is symmetric or skew symmetric according as A is symmetric or skew symmetric.
- Q3: Find the values of $x, y, z$ if the matrix $A = \begin{bmatrix} 0 & 2y & z \\ x & y & -z \\ x & -y & z \end{bmatrix}$ satisfy the equation $A′A = I$.
- Q4: For what values of $x$ : $\begin{bmatrix} 1 & 2 & 1 \end{bmatrix} \begin{bmatrix} 1 & 2 & 0 \\ 2 & 0 & 1 \\ 1 & 0 & 2 \end{bmatrix} \begin{bmatrix} 0 \\ 2 \\ x \end{bmatrix} = O$?
- Q5: If $A = \begin{bmatrix} 3 & 1 \\ -1 & 2 \end{bmatrix}$, show that $A^2 – 5A + 7I = 0$.
- Q6: Find $x$, if $\begin{bmatrix} x & -5 & -1 \end{bmatrix} \begin{bmatrix} 1 & 0 & 2 \\ 0 & 2 & 1 \\ 2 & 0 & 3 \end{bmatrix} \begin{bmatrix} x \\ 4 \\ 1 \end{bmatrix} = O$
- Q7(a): A manufacturer produces three products $x, y, z$ which he sells in two markets. Annual sales are indicated below: (a) If unit sale prices of $x, y$ and $z$ are ` 2.50, ` 1.50 and ` 1.00, respectively, find the total revenue in each market with the help of matrix algebra.
- Q7(b): A manufacturer produces three products $x, y, z$ which he sells in two markets. Annual sales are indicated below: (b) If the unit costs of the above three commodities are ` 2.00, ` 1.00 and 50 paise respectively. Find the gross profit.
- Q8: Find the matrix $X$ so that $X \begin{bmatrix} 1 & 2 & 3 \\ 4 & 5 & 6 \end{bmatrix} = \begin{bmatrix} -7 & -8 & -9 \\ 2 & 4 & 6 \end{bmatrix}$
- Q9: If $A = \begin{bmatrix} \alpha & \beta \\ \gamma & -\alpha \end{bmatrix}$ is such that $A^2 = I$, then
- Q10: If the matrix A is both symmetric and skew symmetric, then
- Q11: If A is square matrix such that $A^2 = A$, then $(I + A)^3 – 7 A$ is equal to
CBSE Solutions for Class 12 Mathematics Matrices
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