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Q10:
If the matrix A is both symmetric and skew symmetric, then
Solution :
Step 1: Establishing Definitions
To determine the nature of a matrix $A$ that is simultaneously symmetric and skew-symmetric, we must apply the foundational definitions of these matrix classifications [Per the definitions of square matrices]:
- Symmetric Matrix: A square matrix $A$ is symmetric if $A^T = A$.
- Skew-Symmetric Matrix: A square matrix $A$ is skew-symmetric if $A^T = -A$.
Step 2: Equating the Conditions
Given that the matrix $A$ satisfies both conditions simultaneously, we set the right-hand sides of the two definitions equal to each other:
$A = A^T$ (from the property of symmetric matrices)
$A^T = -A$ (from the property of skew-symmetric matrices)
By the Transitive Property of Equality [By Mathematical Axioms], we substitute $A^T$ in the first equation with $-A$:
$A = -A$
Step 3: Algebraic Manipulation
To solve for $A$, we perform the following algebraic steps:
$A + A = 0$ [Adding $A$ to both sides of the equation]
$2A = O$ [Where $O$ denotes the zero matrix of the same order as $A$]
$A = \frac{1}{2}O$
$A = O$
Step 4: Logical Deduction of the Matrix Elements
If $A = O$, then every element $a_{ij}$ within the matrix $A$ must be zero for all $i, j$. A square matrix where all entries are zero is defined as a Null Matrix or Zero Matrix.
Step 5: Theoretical Conclusion
Any matrix $A$ that is both symmetric and skew-symmetric must necessarily contain only zero elements. If even one element were non-zero (e.g., $a_{ij} = k \neq 0$), then $a_{ij} = k$ would imply $a_{ji} = k$ (symmetric) and $a_{ji} = -k$ (skew-symmetric), forcing $k = -k$, which is only possible if $k=0$ [Per the properties of field characteristics where $char \neq 2$].
Final Solution: A is a zero matrix.
More Questions from Class 12 Mathematics Matrices Miscellaneous Exercise on Chapter 3
- Q1: If A and B are symmetric matrices, prove that AB – BA is a skew symmetric matrix.
- Q2: Show that the matrix B′AB is symmetric or skew symmetric according as A is symmetric or skew symmetric.
- Q3: Find the values of $x, y, z$ if the matrix $A = \begin{bmatrix} 0 & 2y & z \\ x & y & -z \\ x & -y & z \end{bmatrix}$ satisfy the equation $A′A = I$.
- Q4: For what values of $x$ : $\begin{bmatrix} 1 & 2 & 1 \end{bmatrix} \begin{bmatrix} 1 & 2 & 0 \\ 2 & 0 & 1 \\ 1 & 0 & 2 \end{bmatrix} \begin{bmatrix} 0 \\ 2 \\ x \end{bmatrix} = O$?
- Q5: If $A = \begin{bmatrix} 3 & 1 \\ -1 & 2 \end{bmatrix}$, show that $A^2 – 5A + 7I = 0$.
- Q6: Find $x$, if $\begin{bmatrix} x & -5 & -1 \end{bmatrix} \begin{bmatrix} 1 & 0 & 2 \\ 0 & 2 & 1 \\ 2 & 0 & 3 \end{bmatrix} \begin{bmatrix} x \\ 4 \\ 1 \end{bmatrix} = O$
- Q7(a): A manufacturer produces three products $x, y, z$ which he sells in two markets. Annual sales are indicated below: (a) If unit sale prices of $x, y$ and $z$ are ` 2.50, ` 1.50 and ` 1.00, respectively, find the total revenue in each market with the help of matrix algebra.
- Q7(b): A manufacturer produces three products $x, y, z$ which he sells in two markets. Annual sales are indicated below: (b) If the unit costs of the above three commodities are ` 2.00, ` 1.00 and 50 paise respectively. Find the gross profit.
- Q8: Find the matrix $X$ so that $X \begin{bmatrix} 1 & 2 & 3 \\ 4 & 5 & 6 \end{bmatrix} = \begin{bmatrix} -7 & -8 & -9 \\ 2 & 4 & 6 \end{bmatrix}$
- Q9: If $A = \begin{bmatrix} \alpha & \beta \\ \gamma & -\alpha \end{bmatrix}$ is such that $A^2 = I$, then
- Q11: If A is square matrix such that $A^2 = A$, then $(I + A)^3 – 7 A$ is equal to
CBSE Solutions for Class 12 Mathematics Matrices
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