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Q21:
Integrate the functions in Exercises 1 to 37: 21. $\tan^2(2x-3)$

Solution :

Step 1: Application of Trigonometric Identity

To integrate the function $\int \tan^2(2x-3) \, dx$, we utilize the fundamental trigonometric identity derived from the Pythagorean identity $\sec^2 \theta - \tan^2 \theta = 1$. Rearranging this, we obtain:

$\tan^2 \theta = \sec^2 \theta - 1$

Substituting $\theta = 2x - 3$, the integral becomes:

$\int \tan^2(2x-3) \, dx = \int (\sec^2(2x-3) - 1) \, dx$

Step 2: Decomposition and Integration

By the linearity property of integration [Per the Linearity of Integrals], we can split the expression into two distinct integrals:

$\int \sec^2(2x-3) \, dx - \int 1 \, dx$

Step 3: Evaluating the Integrals

For the first term, we apply the integration formula $\int \sec^2(u) \, du = \tan(u) + C$. Let $u = 2x - 3$. Then, $du = 2 \, dx$, or $dx = \frac{1}{2} \, du$ [By Substitution Rule].

$\int \sec^2(2x-3) \, dx = \frac{1}{2} \tan(2x-3)$

For the second term, we evaluate the integral of a constant:

$\int 1 \, dx = x + C_2$

Step 4: Synthesis of the Final Result

Combining the results from Step 3 and introducing the constant of integration $C$:

$\int \tan^2(2x-3) \, dx = \frac{1}{2} \tan(2x-3) - x + C$

Visual Representation of Function Transformation

x y Graph of tan²(2x-3)

Final Solution: \frac{1}{2} \tan(2x-3) - x + C


More Questions from Class 12 Mathematics Integrals EXERCISE 7.2


CBSE Solutions for Class 12 Mathematics Integrals


Chapters in CBSE - Class 12 Mathematics


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