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Q13:
Integrate the functions in Exercises 1 to 37: 13. $\frac{x^2}{(2+3x^3)^3}$

Solution :

Step 1: Problem Definition and Setup

The objective is to evaluate the indefinite integral $I$ given by:

$I = \int \frac{x^2}{(2+3x^3)^3} \, dx$

Step 2: Method of Substitution

To simplify the integrand, we observe the relationship between the numerator and the derivative of the expression within the denominator [Per the Substitution Rule for Integration].

Let $u = 2 + 3x^3$.

Differentiating both sides with respect to $x$:

$\frac{du}{dx} = \frac{d}{dx}(2) + \frac{d}{dx}(3x^3)$

$\frac{du}{dx} = 0 + 9x^2$

$du = 9x^2 \, dx$

Step 3: Algebraic Manipulation

Rearranging the differential to match the terms present in the integrand:

$x^2 \, dx = \frac{1}{9} \, du$

Substituting these values back into the integral $I$:

$I = \int \frac{1}{u^3} \cdot \left( \frac{1}{9} \, du \right)$

$I = \frac{1}{9} \int u^{-3} \, du$

Step 4: Applying the Power Rule for Integration

Using the power rule $\int x^n \, dx = \frac{x^{n+1}}{n+1} + C$, where $n \neq -1$:

$I = \frac{1}{9} \left( \frac{u^{-3+1}}{-3+1} \right) + C$

$I = \frac{1}{9} \left( \frac{u^{-2}}{-2} \right) + C$

$I = -\frac{1}{18} \cdot \frac{1}{u^2} + C$

Step 5: Re-substitution and Simplification

Substitute $u = 2 + 3x^3$ back into the equation:

$I = -\frac{1}{18(2+3x^3)^2} + C$

Visual Representation of the Substitution Variable

Mapping: x → u = 2 + 3x³ u = 2 + 3x³

Final Solution: -\frac{1}{18(2+3x^3)^2} + C


More Questions from Class 12 Mathematics Integrals EXERCISE 7.2


CBSE Solutions for Class 12 Mathematics Integrals


Chapters in CBSE - Class 12 Mathematics


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