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Q5.9:
A rocket with a lift-off mass 20,000 kg is blasted upwards with an initial acceleration of $5.0 m s^{-2}$. Calculate the initial thrust (force) of the blast.

Solution :

Step 1: Identifying Known Variables and Physical Constants

Based on the problem statement, we define the following parameters:

  • Mass of the rocket ($m$) = $20,000 \text{ kg} = 2 \times 10^4 \text{ kg}$
  • Initial upward acceleration ($a$) = $5.0 \text{ m s}^{-2}$
  • Acceleration due to gravity ($g$) = $9.8 \text{ m s}^{-2}$ [Standard approximation for Earth's surface]

Step 2: Defining the Force Equations (Free Body Diagram Analysis)

The rocket experiences two primary vertical forces during the initial blast phase:

  1. The upward Thrust Force ($F_{thrust}$), which is generated by the rocket engines.
  2. The downward Gravitational Force ($F_g$), which is the weight of the rocket ($W = mg$).

According to [Newton’s Second Law of Motion], the net force ($F_{net}$) acting on an object is the product of its mass and its acceleration ($F_{net} = ma$). Because the rocket is accelerating upwards, the Thrust Force must be greater than the Gravitational Force.

The net force equation is expressed as:

$F_{net} = F_{thrust} - F_g$
$ma = F_{thrust} - mg$

Step 3: Algebraic Rearrangement for Thrust Force

To solve for $F_{thrust}$, we isolate the variable on one side of the equation:

$F_{thrust} = ma + mg$
$F_{thrust} = m(a + g)$ [By the Distributive Property of Multiplication]

Step 4: Substitution and Calculation

Substitute the identified variables into the derived equation:

$F_{thrust} = (20,000 \text{ kg}) \times (5.0 \text{ m s}^{-2} + 9.8 \text{ m s}^{-2})$
$F_{thrust} = 20,000 \times 14.8$
$F_{thrust} = 296,000 \text{ N}$

Visual Representation of Force Vectors

$F_{thrust}$ $mg$

Step 5: Analysis of Results

The initial thrust is calculated as $2.96 \times 10^5 \text{ N}$. This magnitude is necessary not only to counteract the weight of the rocket ($196,000 \text{ N}$) but also to provide the required net force to generate an acceleration of $5.0 \text{ m s}^{-2}$.

Final Solution: $2.96 \times 10^5 \text{ N}$


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