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Q5.8:
The driver of a three-wheeler moving with a speed of 36 km/h sees a child standing in the middle of the road and brings his vehicle to rest in 4.0 s just in time to save the child. What is the average retarding force on the vehicle ? The mass of the three-wheeler is 400 kg and the mass of the driver is 65 kg.

Solution :

Step 1: Identification of Given Variables

First, we convert all given quantities into SI units for consistency [Per International System of Units standards].

  • Initial velocity ($u$): $36 \text{ km/h} = 36 \times \frac{5}{18} \text{ m/s} = 10 \text{ m/s}$
  • Final velocity ($v$): $0 \text{ m/s}$ (since the vehicle comes to rest)
  • Time taken ($t$): $4.0 \text{ s}$
  • Mass of three-wheeler ($m_1$): $400 \text{ kg}$
  • Mass of driver ($m_2$): $65 \text{ kg}$
  • Total mass ($M$): $m_1 + m_2 = 400 + 65 = 465 \text{ kg}$

Step 2: Kinematic Analysis

To find the average retarding force, we must first determine the deceleration ($a$) of the vehicle using the first equation of motion [By Kinematic Equation of Motion]:

$v = u + at$

$0 = 10 + a(4.0)$

$4a = -10$

$a = -2.5 \text{ m/s}^2$

The negative sign indicates a retardation (deceleration) of $2.5 \text{ m/s}^2$.

Step 3: Force Calculation

Using Newton's Second Law of Motion, which states that the force acting on an object is equal to the product of its mass and acceleration ($F = ma$) [Per Newton’s Second Law]:

$F = M \times a$

$F = 465 \text{ kg} \times (-2.5 \text{ m/s}^2)$

$F = -1162.5 \text{ N}$

Step 4: Visualizing the Dynamics

Velocity ($v$) Force ($F = -1162.5 \text{ N}$)

Step 5: Analysis of Results

The retarding force represents the resistive force applied by the brakes against the direction of motion. Since the magnitude is requested, we express the force as a positive retarding value.

Parameter Value
Total Mass $465 \text{ kg}$
Deceleration $2.5 \text{ m/s}^2$
Retarding Force $1162.5 \text{ N}$

Final Solution: The average retarding force acting on the vehicle is 1162.5 N.


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