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Q4.23(d):
Explain why a cricketer moves his hands backwards while holding a catch.

Solution :

Theoretical Foundation: The Impulse-Momentum Theorem

To understand the mechanics of catching a fast-moving cricket ball, we must analyze the interaction using Newton’s Second Law of Motion in terms of momentum. The relationship between the force exerted, the time of interaction, and the change in momentum is given by the Impulse-Momentum Theorem:

$\vec{F} \Delta t = \Delta \vec{p}$

Where:

  • $\vec{F}$ is the average force exerted by the hands on the ball.
  • $\Delta t$ is the duration of the contact.
  • $\Delta \vec{p} = m(\vec{v}_f - \vec{v}_i)$ is the change in momentum of the ball.

Step 1: Analyzing the Variables

In a standard cricket catch, the initial velocity $\vec{v}_i$ is high, and the final velocity $\vec{v}_f$ is zero (since the ball comes to rest in the hands). Therefore, the magnitude of the change in momentum $\Delta p = |m(0 - v_i)| = mv_i$ is a constant determined by the speed and mass of the ball [Per the Principle of Conservation of Momentum and fixed initial state].

Step 2: Deriving the Force-Time Relationship

Rearranging the theorem to solve for the force exerted by the hands:

$F = \frac{\Delta p}{\Delta t}$

Since $\Delta p$ is fixed, the force $F$ is inversely proportional to the time interval $\Delta t$ ($F \propto \frac{1}{\Delta t}$).

Step 3: Geometrical Representation of Impulse

Time (t) Force (F) Sudden Stop Gradual Stop

Step 4: Physical Application and Conclusion

When a cricketer pulls their hands backward while catching the ball, they are intentionally increasing the duration of the impact ($\Delta t$).

  • Scenario A (Stationary Hands): $\Delta t$ is very small, leading to a very large impulsive force $F$ exerted by the ball on the hands, causing potential injury.
  • Scenario B (Hands in Motion): By moving the hands in the direction of the ball's velocity, the contact time $\Delta t$ is significantly extended. According to the inverse proportionality established in Step 2, increasing $\Delta t$ decreases the magnitude of the force $F$ required to bring the ball to rest.

Final Solution: The cricketer moves their hands backwards to increase the time ($\Delta t$) taken to bring the ball to rest. By increasing the duration of the impulse, the average retarding force ($\vec{F}$) exerted on the hands is reduced, thereby minimizing the risk of injury and preventing the ball from bouncing out of the hands [Per Newton's Second Law of Motion].


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