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Q8:
How many words, with or without meaning, can be formed using all the letters of the word EQUATION, using each letter exactly once?

Solution :

Step 1: Analyzing the Set of Letters

The given word is "EQUATION". To determine the number of permutations, we must first identify the individual components (letters) of the word and check for repetitions.

  • Letters: E, Q, U, A, T, I, O, N
  • Total number of letters ($n$): 8
  • Frequency of letters: Each letter (E, Q, U, A, T, I, O, N) appears exactly once. [Per the Fundamental Counting Principle for distinct objects]

Step 2: Theoretical Foundation

The problem asks for the number of arrangements of $n$ distinct objects taken all at a time. The formula for the number of permutations of $n$ distinct objects is given by $n!$ (n-factorial), where $n! = n \times (n-1) \times (n-2) \times \dots \times 1$. [By the Theorem of Permutations of $n$ distinct objects]

Step 3: Algebraic Calculation

Substituting $n = 8$ into the permutation formula:

Number of arrangements = $8!$

$8! = 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1$

Operation Result
$8 \times 7$ 56
$56 \times 6$ 336
$336 \times 5$ 1680
$1680 \times 4$ 6720
$6720 \times 3$ 20160
$20160 \times 2$ 40320
$40320 \times 1$ 40320

Step 4: Visual Representation of Permutation Slots

8 7 6 5 4 3 2 1 Slots representing the 8 positions for the 8 distinct letters.

Final Solution: The total number of words that can be formed is 40,320.


More Questions from Class 11 Mathematics Permutations and Combinations EXERCISE 6.3


CBSE Solutions for Class 11 Mathematics Permutations and Combinations


Chapters in CBSE - Class 11 Mathematics


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