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Q11(iii):
In how many ways can the letters of the word PERMUTATIONS be arranged if the (iii) there are always 4 letters between P and S?
Solution :
Step 1: Analyis of the Given Word
The word "PERMUTATIONS" consists of $12$ letters. Let us identify the frequency of each letter:
- P: 1, E: 1, R: 1, M: 1, U: 1, T: 2, A: 1, I: 1, O: 1, N: 1, S: 1.
- Total letters ($n$) = 12.
- Repeating letters: 'T' appears 2 times.
Step 2: Defining the Constraint
We are required to arrange the letters such that there are exactly 4 letters between 'P' and 'S'.
Let the positions be represented by indices $1, 2, 3, \dots, 12$. If P is at position $i$, then S must be at position $i+5$ (to allow for 4 letters between them) or vice versa. The possible pairs of positions $(P, S)$ are:
$(1, 6), (2, 7), (3, 8), (4, 9), (5, 10), (6, 11), (7, 12)$.
There are $7$ such pairs. Since P and S can be swapped, there are $7 \times 2 = 14$ ways to place P and S.
Step 3: Calculating Permutations of Remaining Letters
Once P and S are fixed in a chosen pair of positions, there are $12 - 2 = 10$ remaining positions to be filled by the remaining $10$ letters.
The remaining letters are $\{E, R, M, U, T, T, A, I, O, N\}$.
The number of ways to arrange these 10 letters, where 'T' repeats 2 times, is given by the formula for permutations of multisets [Per Fundamental Principle of Counting]:
$$\text{Ways} = \frac{10!}{2!}$$
Calculating the value:
$$\frac{3,628,800}{2} = 1,814,400$$
Step 4: Final Computation
The total number of arrangements is the product of the number of ways to place P and S and the number of ways to arrange the remaining letters.
$$\text{Total Arrangements} = (\text{Ways to place P and S}) \times (\text{Ways to arrange remaining 10 letters})$$
$$\text{Total Arrangements} = 14 \times 1,814,400$$
$$\text{Total Arrangements} = 25,401,600$$
Visual Representation of Position Slots
Final Solution: The total number of ways to arrange the letters such that there are always 4 letters between P and S is 25,401,600.
More Questions from Class 11 Mathematics Permutations and Combinations EXERCISE 6.3
- Q1: How many 3-digit numbers can be formed by using the digits 1 to 9 if no digit is repeated?
- Q2: How many 4-digit numbers are there with no digit repeated?
- Q3: How many 3-digit even numbers can be made using the digits 1, 2, 3, 4, 6, 7, if no digit is repeated?
- Q4: Find the number of 4-digit numbers that can be formed using the digits 1, 2, 3, 4, 5 if no digit is repeated. How many of these will be even?
- Q5: From a committee of 8 persons, in how many ways can we choose a chairman and a vice chairman assuming one person can not hold more than one position?
- Q6: Find $n$ if ${}^{n–1}P_3 : {}^nP_4 = 1 : 9$.
- Q7(i): Find $r$ if (i) ${}^5P_r = 2 \cdot {}^6P_{r-1}$
- Q7(ii): Find $r$ if (ii) ${}^5P_r = {}^6P_{r-1}$.
- Q8: How many words, with or without meaning, can be formed using all the letters of the word EQUATION, using each letter exactly once?
- Q9(i): How many words, with or without meaning can be made from the letters of the word MONDAY, assuming that no letter is repeated, if. (i) 4 letters are used at a time,
- Q9(ii): How many words, with or without meaning can be made from the letters of the word MONDAY, assuming that no letter is repeated, if. (ii) all letters are used at a time,
- Q9(iii): How many words, with or without meaning can be made from the letters of the word MONDAY, assuming that no letter is repeated, if. (iii) all letters are used but first letter is a vowel?
- Q10: In how many of the distinct permutations of the letters in MISSISSIPPI do the four $I$'s not come together?
- Q11(i): In how many ways can the letters of the word PERMUTATIONS be arranged if the (i) words start with P and end with S,
- Q11(ii): In how many ways can the letters of the word PERMUTATIONS be arranged if the (ii) vowels are all together,
CBSE Solutions for Class 11 Mathematics Permutations and Combinations
Chapters in CBSE - Class 11 Mathematics
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