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Q11(ii):
In how many ways can the letters of the word PERMUTATIONS be arranged if the (ii) vowels are all together,
Solution :
Step 1: Analyzing the Word Composition
The given word is PERMUTATIONS. We perform an exhaustive count of its constituent letters:
- Total letters ($n$) = 12
- Letter frequencies:
- P: 1, E: 1, R: 1, M: 1, U: 1, T: 2, A: 1, I: 1, O: 1, N: 1, S: 1
- Total distinct letters: 11 distinct types, with 'T' repeating twice.
Step 2: Segregating Vowels and Consonants
To arrange the letters such that all vowels are kept together, we identify the specific vowels in the word:
- Vowels: {E, U, A, I, O} (Total = 5)
- Consonants: {P, R, M, T, T, N, S} (Total = 7)
[By the method of grouping, we treat the set of vowels as a single entity or 'super-letter' (V)].
Step 3: Calculating Internal Permutations of the Vowel Group
The 5 vowels {E, U, A, I, O} are all distinct. The number of ways to arrange these 5 vowels internally is given by $5!$ [Per the Multiplication Principle of counting]:
$5! = 5 \times 4 \times 3 \times 2 \times 1 = 120$
Step 4: Arranging the Combined Entities
After grouping the vowels into a single unit (V), we now have the following entities to arrange:
- Consonants: {P, R, M, T, T, N, S} (7 entities)
- Vowel group: {V} (1 entity)
- Total entities to arrange = $7 + 1 = 8$
Among these 8 entities, the letter 'T' appears twice. Therefore, the number of distinct permutations of these 8 entities is calculated as:
$\frac{8!}{2!}$
Calculation: $\frac{40320}{2} = 20160$
Step 5: Final Combinatorial Synthesis
The total number of arrangements is the product of the external arrangements of the entities and the internal arrangements of the vowels [Per the Fundamental Counting Principle]:
$\text{Total} = (\text{Arrangements of entities}) \times (\text{Internal vowel permutations})$
$\text{Total} = 20160 \times 120$
$\text{Total} = 2,419,200$
Visual Representation of the Grouping Method
Final Solution: 2,419,200 ways
More Questions from Class 11 Mathematics Permutations and Combinations EXERCISE 6.3
- Q1: How many 3-digit numbers can be formed by using the digits 1 to 9 if no digit is repeated?
- Q2: How many 4-digit numbers are there with no digit repeated?
- Q3: How many 3-digit even numbers can be made using the digits 1, 2, 3, 4, 6, 7, if no digit is repeated?
- Q4: Find the number of 4-digit numbers that can be formed using the digits 1, 2, 3, 4, 5 if no digit is repeated. How many of these will be even?
- Q5: From a committee of 8 persons, in how many ways can we choose a chairman and a vice chairman assuming one person can not hold more than one position?
- Q6: Find $n$ if ${}^{n–1}P_3 : {}^nP_4 = 1 : 9$.
- Q7(i): Find $r$ if (i) ${}^5P_r = 2 \cdot {}^6P_{r-1}$
- Q7(ii): Find $r$ if (ii) ${}^5P_r = {}^6P_{r-1}$.
- Q8: How many words, with or without meaning, can be formed using all the letters of the word EQUATION, using each letter exactly once?
- Q9(i): How many words, with or without meaning can be made from the letters of the word MONDAY, assuming that no letter is repeated, if. (i) 4 letters are used at a time,
- Q9(ii): How many words, with or without meaning can be made from the letters of the word MONDAY, assuming that no letter is repeated, if. (ii) all letters are used at a time,
- Q9(iii): How many words, with or without meaning can be made from the letters of the word MONDAY, assuming that no letter is repeated, if. (iii) all letters are used but first letter is a vowel?
- Q10: In how many of the distinct permutations of the letters in MISSISSIPPI do the four $I$'s not come together?
- Q11(i): In how many ways can the letters of the word PERMUTATIONS be arranged if the (i) words start with P and end with S,
- Q11(iii): In how many ways can the letters of the word PERMUTATIONS be arranged if the (iii) there are always 4 letters between P and S?
CBSE Solutions for Class 11 Mathematics Permutations and Combinations
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