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Q6(c):
Balance the following chemical equations. (c) $NaCl + AgNO_3 \rightarrow AgCl + NaNO_3$

Solution :

Step 1: Analyzing the Unbalanced Equation

The given skeletal chemical equation is:

$NaCl_{(aq)} + AgNO_{3(aq)} \rightarrow AgCl_{(s)} + NaNO_{3(aq)}$

To balance this equation, we must ensure that the number of atoms for each element is equal on both the reactant and product sides [Per the Law of Conservation of Mass, which states that matter is neither created nor destroyed in a chemical reaction].

Step 2: Tabulating Atomic Distribution

Element Reactant Side (LHS) Product Side (RHS)
Sodium ($Na$) 1 1
Chlorine ($Cl$) 1 1
Silver ($Ag$) 1 1
Nitrate group ($NO_3$) 1 1

Step 3: Assessment and Verification

By inspecting the table above, we observe the following:

  • The number of $Na$ atoms is 1 on both sides.
  • The number of $Cl$ atoms is 1 on both sides.
  • The number of $Ag$ atoms is 1 on both sides.
  • The number of $NO_3$ groups is 1 on both sides.

Since the stoichiometry of every element and polyatomic ion is already balanced, the coefficients of all reactants and products are effectively $1$.

Step 4: Visual Representation of the Precipitation Reaction

NaCl + AgNO₃ AgCl (White Ppt) + NaNO₃ Double Displacement Reaction

Step 5: Final Equation Formulation

The equation remains as provided, confirming that the initial representation follows the stoichiometric requirement of balancing [Law of Conservation of Mass].

Final Solution: $1NaCl + 1AgNO_3 \rightarrow 1AgCl + 1NaNO_3$


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