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Q7:

The distribution below gives the weights of 30 students of a class. Find the median weight of the students. 

Solution :

Given: A frequency distribution of the weights of 30 students.

Weight (kg)Number of students (f)
40 - 452
45 - 503
50 - 558
55 - 606
60 - 656
65 - 703
70 - 752

To Find: The median weight of the students.

Step 1: Constructing the Cumulative Frequency Table

To find the median, we must first calculate the cumulative frequency ($cf$) for each class interval.

Weight (kg)Frequency ($f$)Cumulative Frequency ($cf$)
40 - 4522
45 - 5032 + 3 = 5
50 - 5585 + 8 = 13
55 - 60613 + 6 = 19
60 - 65619 + 6 = 25
65 - 70325 + 3 = 28
70 - 75228 + 2 = 30
Total$n = 30$-

Step 2: Identifying the Median Class

The total number of observations is $n = 30$.
We calculate $\frac{n}{2} = \frac{30}{2} = 15$.
[The median class is the class interval whose cumulative frequency is greater than or nearest to $\frac{n}{2}$.]
Looking at the table, the cumulative frequency just greater than 15 is 19, which corresponds to the class interval 55 - 60.

Step 3: Applying the Median Formula

The formula for the median is:
$Median = l + \left( \frac{\frac{n}{2} - cf}{f} \right) \times h$
Where:
$l$ (lower limit of median class) = $55$
$n$ (total number of observations) = $30$
$cf$ (cumulative frequency of the class preceding the median class) = $13$
$f$ (frequency of the median class) = $6$
$h$ (class size) = $60 - 55 = 5$

Step 4: Calculating the Result

$Median = 55 + \left( \frac{15 - 13}{6} \right) \times 5$
$Median = 55 + \left( \frac{2}{6} \right) \times 5$
$Median = 55 + \left( \frac{1}{3} \right) \times 5$
$Median = 55 + \frac{5}{3}$
$Median = 55 + 1.666...$
$Median \approx 56.67$

Final Answer: The median weight of the students is 56.67 kg.


More Questions from Class 10 Mathematics Statistics EXERCISE 13.3


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