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Q6:

100 surnames were randomly picked up from a local telephone directory and the frequency distribution of the number of letters in the English alphabets in the surnames was obtained as follows:

Determine the median number of letters in the surnames. Find the mean number of letters in the surnames? Also, find the modal size of the surnames.

Solution :

Given: A frequency distribution of the number of letters in 100 surnames.

Number of lettersNumber of surnames ($f_i$)
1 - 46
4 - 730
7 - 1040
10 - 1316
13 - 164
16 - 194

To Find: The Median, Mean, and Mode of the given data.

Step 1: Calculation of Mean ($\bar{x}$)

We use the Assumed Mean Method. Let the assumed mean $a = 11.5$. The class size $h = 3$.

Class IntervalFrequency ($f_i$)Class Mark ($x_i$)$d_i = x_i - a$$u_i = \frac{x_i - a}{h}$$f_i u_i$
1-462.5-9-3-18
4-7305.5-6-2-60
7-10408.5-3-1-40
10-131611.5000
13-16414.5314
16-19417.5628
Total$\sum f_i = 100$---$\sum f_i u_i = -106$

Formula for Mean: $\bar{x} = a + \left( \frac{\sum f_i u_i}{\sum f_i} \right) \times h$

$\bar{x} = 11.5 + \left( \frac{-106}{100} \right) \times 3 = 11.5 - 3.18 = 8.32$

Step 2: Calculation of Median

Total frequency $N = 100$. So, $N/2 = 50$.

Class IntervalFrequency ($f_i$)Cumulative Frequency ($cf$)
1-466
4-73036
7-104076

The cumulative frequency just greater than 50 is 76, so the median class is $7-10$.

Lower limit ($l$) = 7, $cf$ of preceding class = 36, $f$ of median class = 40, $h = 3$.

Median = $l + \left( \frac{N/2 - cf}{f} \right) \times h = 7 + \left( \frac{50 - 36}{40} \right) \times 3 = 7 + \left( \frac{14}{40} \right) \times 3 = 7 + 1.05 = 8.05$

Step 3: Calculation of Mode

The modal class is the class with the highest frequency, which is $7-10$ ($f_1 = 40$).

$l = 7, f_1 = 40, f_0 = 30, f_2 = 16, h = 3$.

Mode = $l + \left( \frac{f_1 - f_0}{2f_1 - f_0 - f_2} \right) \times h = 7 + \left( \frac{40 - 30}{2(40) - 30 - 16} \right) \times 3$

Mode = $7 + \left( \frac{10}{80 - 46} \right) \times 3 = 7 + \left( \frac{10}{34} \right) \times 3 = 7 + 0.88 = 7.88$

Final Answer: The Mean number of letters is 8.32, the Median is 8.05, and the Mode is 7.88.


More Questions from Class 10 Mathematics Statistics EXERCISE 13.3


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