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Q2(i):

Choose the correct choice in the following and justify : (i) 30th term of the AP: 10, 7, 4, . . . , is

Solution :

Given: An Arithmetic Progression (AP) sequence: $10, 7, 4, \dots$

To Find: The $30^{th}$ term of the given AP.

Step 1: Identify the parameters of the Arithmetic Progression.

An Arithmetic Progression is a sequence of numbers such that the difference between consecutive terms is constant. This constant is known as the common difference ($d$).

The first term ($a$) is the first number in the sequence:
$a = 10$

The common difference ($d$) is calculated by subtracting the first term from the second term:
$d = a_2 - a_1$
$d = 7 - 10$
$d = -3$

Step 2: State the formula for the $n^{th}$ term of an AP.

The general formula to find the $n^{th}$ term ($a_n$) of an Arithmetic Progression is:
$a_n = a + (n - 1)d$
Where:
$a_n$ = the $n^{th}$ term to be found
$a$ = the first term
$n$ = the position of the term
$d$ = the common difference

Step 3: Substitute the known values into the formula.

We are looking for the $30^{th}$ term, so $n = 30$.
Substituting $a = 10$, $d = -3$, and $n = 30$ into the formula:

$a_{30} = 10 + (30 - 1)(-3)$

Step 4: Perform the arithmetic calculations.

First, solve the expression inside the parentheses:
$a_{30} = 10 + (29)(-3)$

Next, perform the multiplication:
$29 \times -3 = -87$

Finally, perform the addition:
$a_{30} = 10 - 87$
$a_{30} = -77$

Justification: By applying the standard formula for the $n^{th}$ term of an arithmetic progression, we have determined that the sequence decreases by $3$ at each step. Starting from $10$, after $29$ steps of decreasing by $3$, the value reaches $-77$.

Final Answer: The 30th term of the AP is -77.


More Questions from Class 10 Mathematics Arithmetic Progression EXERCISE 5.2


CBSE Solutions for Class 10 Mathematics Arithmetic Progression


Chapters in CBSE - Class 10 Mathematics


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