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Q13:
How many three-digit numbers are divisible by 7?

Solution :

Given:

We are looking for three-digit numbers. The range of three-digit numbers is from $100$ to $999$. We are specifically interested in those numbers that are divisible by $7$.

To Find:

The total count of three-digit numbers divisible by $7$.

Step 1: Identifying the first three-digit number divisible by 7

The smallest three-digit number is $100$. Let us divide $100$ by $7$:
$100 \div 7 = 14$ with a remainder of $2$.
To find the next multiple of $7$, we calculate: $100 + (7 - 2) = 105$.
Thus, the first three-digit number divisible by $7$ is $a = 105$.

Step 2: Identifying the last three-digit number divisible by 7

The largest three-digit number is $999$. Let us divide $999$ by $7$:
$999 \div 7 = 142$ with a remainder of $5$.
To find the largest multiple of $7$ less than or equal to $999$, we subtract the remainder from $999$:
$999 - 5 = 994$.
Thus, the last three-digit number divisible by $7$ is $l = 994$.

Step 3: Formulating the Arithmetic Progression (AP)

The sequence of three-digit numbers divisible by $7$ forms an Arithmetic Progression where:
First term ($a$) = $105$
Common difference ($d$) = $7$
Last term ($a_n$) = $994$

Step 4: Applying the formula for the $n^{th}$ term of an AP

The formula for the $n^{th}$ term of an AP is given by:
$a_n = a + (n - 1)d$
[Where $a_n$ is the last term, $a$ is the first term, $d$ is the common difference, and $n$ is the number of terms.]

Step 5: Solving for $n$

Substitute the known values into the formula:
$994 = 105 + (n - 1)7$
Subtract $105$ from both sides:
$994 - 105 = (n - 1)7$
$889 = (n - 1)7$
Divide both sides by $7$:
$889 / 7 = n - 1$
$127 = n - 1$
Add $1$ to both sides:
$n = 127 + 1$
$n = 128$

Final Answer:

There are 128 three-digit numbers that are divisible by 7.


More Questions from Class 10 Mathematics Arithmetic Progression EXERCISE 5.2


CBSE Solutions for Class 10 Mathematics Arithmetic Progression


Chapters in CBSE - Class 10 Mathematics


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