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Sumanta Panda Engineering Entrance trainer in Kolkata

Sumanta Panda

locationImg Ghughudanga, Kolkata
3 yrs of Exp
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Tutor

Online Classes
Student's home
Tutor's home
I can teach each and every topics very easily and make it stronger for the students.

Languages Spoken

Hindi

Oriya

Bengali

English

Education

PONDICHERRY UNIVERSITY 2015

Master of Science (M.Sc.)

Address

Ghughudanga, Kolkata, India - 700030

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Teaches

Engineering Entrance Coaching classes

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Engineering Entrance Coaching classes

3

Engineering Entrance Exams

IIT JEE Coaching Classes, GATE Coaching Classes

IITJEE Coaching

IIT JEE Foundation Course, IIT JEE Advanced Coaching, IIT JEE Crash Course, IIT JEE Mains Coaching, IIT JEE Integrated Coaching

Type of class

Regular Classes, Crash Course

IIT-JEE Subjects

Chemistry

Class 9 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

3

Board

ICSE, IGCSE, CBSE, State

Subjects taught

Chemistry, Science

Taught in School or College

No

Class 10 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

3

Board

ICSE, CBSE, State

Subjects taught

Chemistry, Science

Taught in School or College

No

Class 11 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

3

Board

CBSE, ISC/ICSE, State

Subjects taught

Chemistry

Taught in School or College

No

Class 12 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

3

Board

CBSE, ISC/ICSE, State

Subjects taught

Chemistry

Taught in School or College

No

NEET-UG Coaching Classes

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in NEET-UG Coaching Classes

3

NEET Subjects

Chemistry

IIT JAM Coaching

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in IIT JAM Coaching

2

Reviews

No Reviews yet!

Answers by Sumanta Panda

Answered on 10/11/2018 Learn CBSE - Class 11/Chemistry/Chemical Bonding and Molecular Structure +1 CBSE - Class 11/Chemistry

Ask a Question

Post a Lesson

I¡) central atom is Be having 2 valance electron, each Cl atom contribute one electron each . So total 4 electron arround central Be atom ,means 2 electron pair. so these 2 electron pair arrange themselve linearly. there are 2 electron pair and two of them is bond pair. So according to VSEPR theory... ...more

I¡) central atom is Be having  2 valance electron, each Cl atom contribute one electron each . So total 4 electron arround central Be atom ,means 2 electron pair. so these 2 electron pair arrange themselve linearly. there are 2 electron pair and two of them is bond pair. So according to VSEPR theory shape of the molecule is linear

(¡¡)SiCl4 molecule has total (4+4)= 8 electrons. i.e; 4 electron pairs so it is having a tetrahedral arrangement. there is 4 electron pair and all are bond pair .So according to VSEPR theory it is tetrahedral shape.

Answers 4 Comments
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Teaches

Engineering Entrance Coaching classes

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Engineering Entrance Coaching classes

3

Engineering Entrance Exams

IIT JEE Coaching Classes, GATE Coaching Classes

IITJEE Coaching

IIT JEE Foundation Course, IIT JEE Advanced Coaching, IIT JEE Crash Course, IIT JEE Mains Coaching, IIT JEE Integrated Coaching

Type of class

Regular Classes, Crash Course

IIT-JEE Subjects

Chemistry

Class 9 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

3

Board

ICSE, IGCSE, CBSE, State

Subjects taught

Chemistry, Science

Taught in School or College

No

Class 10 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

3

Board

ICSE, CBSE, State

Subjects taught

Chemistry, Science

Taught in School or College

No

Class 11 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

3

Board

CBSE, ISC/ICSE, State

Subjects taught

Chemistry

Taught in School or College

No

Class 12 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

3

Board

CBSE, ISC/ICSE, State

Subjects taught

Chemistry

Taught in School or College

No

NEET-UG Coaching Classes

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in NEET-UG Coaching Classes

3

NEET Subjects

Chemistry

IIT JAM Coaching

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in IIT JAM Coaching

2

No Reviews yet!

Answers by Sumanta Panda

Answered on 10/11/2018 Learn CBSE - Class 11/Chemistry/Chemical Bonding and Molecular Structure +1 CBSE - Class 11/Chemistry

Ask a Question

Post a Lesson

I¡) central atom is Be having 2 valance electron, each Cl atom contribute one electron each . So total 4 electron arround central Be atom ,means 2 electron pair. so these 2 electron pair arrange themselve linearly. there are 2 electron pair and two of them is bond pair. So according to VSEPR theory... ...more

I¡) central atom is Be having  2 valance electron, each Cl atom contribute one electron each . So total 4 electron arround central Be atom ,means 2 electron pair. so these 2 electron pair arrange themselve linearly. there are 2 electron pair and two of them is bond pair. So according to VSEPR theory shape of the molecule is linear

(¡¡)SiCl4 molecule has total (4+4)= 8 electrons. i.e; 4 electron pairs so it is having a tetrahedral arrangement. there is 4 electron pair and all are bond pair .So according to VSEPR theory it is tetrahedral shape.

Answers 4 Comments
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