Dr Rajni J.

Boharkawaloo, Kangra, India - 176001

Dr Rajni J. photo

Dr Rajni J.

rajni cv

Boharkawaloo, Kangra, India- 176001.

1 Student taught

4.5
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Overview

I have 2 and half year expt to teach m sc physics students in the instructions.

Education

BU Bhopal 2010

Doctor of Philosophy (Ph.D.)

Barkatullah University Bhopal 2010

Barkatullah University Bhopal, ph.d. cetificate

Address

Boharkawaloo, Kangra, India - 176001

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BSc Tuition Overview

BSc Tuition

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

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Answers by Dr Rajni J. (22)

Answered on 24/06/2016 Tuition/BSc Tuition

The rotation of the planet has slightly flattened it out, so it has a larger diameter at the equator than at the poles. The equatorial diameter of Earth is 12,756 km, its polar diameter is 12,713 km, and its average diameter, which is referred to in common usage, is 12,742 km.
Answers 30 Comments
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Answered on 24/06/2016 Tuition/BSc Tuition

A light emitting diode
Answers 17 Comments
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Answered on 24/06/2016 Tuition/BSc Tuition

The isospin of the nucleon and the isospin symmetry (charge independence) of nuclear forces arises from a corresponding symmetry in the quarks from whichnucleons are made. The main fermion (spin 1/2) constituents of the proton and the neutron are the so-called u and d quarks.
Answers 3 Comments
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Answered on 13/06/2016 Tuition/BSc Tuition

Maxima and minima are plural forms of maximum and minimum. However, in interference and diffraction maxima refers to the zones where the intensity of the light is maximum and minima when the intensity is minimum. When if minimum of a wave superimposes on maximum of the other, it results in a destructive... ...more
Maxima and minima are plural forms of maximum and minimum. However, in interference and diffraction maxima refers to the zones where the intensity of the light is maximum and minima when the intensity is minimum. When if minimum of a wave superimposes on maximum of the other, it results in a destructive interference and intensity becomes a minimum of interference fringes, while if maxima of a wave superimposes on maxima of another wave or minimum of a wave superimposes on minimum of another wave, intensity becomes maximum. For maxima path difference x = n? For minima path difference x = (2n+1)?/2 For interference pattern, in double slit experiment maxima will be found at a distance y from the central maximum , y = n?D/d D = distance between slit and screen d = separation of the slits. n = 1, 2, 3 … For minima y = (2n+1)?D/2d In diffraction minima is found by equation asin? = n? a = slit width For maxima the formula is a transcendental equation and not included in your syllabus.
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Dr Rajni J.Directions

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BSc Tuition 4.5

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Class 11 Tuition 4.5

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 11 Tuition

3

Board

State

Taught in School or College

Yes

State Syllabus Subjects taught

Physics

Teaching Experience in detail in Class 11 Tuition

In 2010 some students were came to my house to study state level physics Syllabus.I tought these students of One year . After that i had joined my job.

Class 12 Tuition 4.5

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 12 Tuition

3

Board

State

Taught in School or College

Yes

State Syllabus Subjects taught

Physics

Teaching Experience in detail in Class 12 Tuition

In 2010 some students were came to my house to study state level physics Syllabus.I tought these students of One year . After that i had joined my job.

MSc Tuition 4.5

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in MSc Tuition

3

Subject

Physics

Taught in School or College

Yes

Teaching Experience in detail in MSc Tuition

I have two and half years experience to teach m.sc. physics. Total experience is about 7&1/2 years exp. I was used to teach in Laboratory (practical work). Students project work should be done. Students six month assessment will be done. Class assesment will be done by the students.

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Answers by Dr Rajni J. (22)

Answered on 24/06/2016 Tuition/BSc Tuition

The rotation of the planet has slightly flattened it out, so it has a larger diameter at the equator than at the poles. The equatorial diameter of Earth is 12,756 km, its polar diameter is 12,713 km, and its average diameter, which is referred to in common usage, is 12,742 km.
Answers 30 Comments
Dislike Bookmark

Answered on 24/06/2016 Tuition/BSc Tuition

A light emitting diode
Answers 17 Comments
Dislike Bookmark

Answered on 24/06/2016 Tuition/BSc Tuition

The isospin of the nucleon and the isospin symmetry (charge independence) of nuclear forces arises from a corresponding symmetry in the quarks from whichnucleons are made. The main fermion (spin 1/2) constituents of the proton and the neutron are the so-called u and d quarks.
Answers 3 Comments
Dislike Bookmark

Answered on 13/06/2016 Tuition/BSc Tuition

Maxima and minima are plural forms of maximum and minimum. However, in interference and diffraction maxima refers to the zones where the intensity of the light is maximum and minima when the intensity is minimum. When if minimum of a wave superimposes on maximum of the other, it results in a destructive... ...more
Maxima and minima are plural forms of maximum and minimum. However, in interference and diffraction maxima refers to the zones where the intensity of the light is maximum and minima when the intensity is minimum. When if minimum of a wave superimposes on maximum of the other, it results in a destructive interference and intensity becomes a minimum of interference fringes, while if maxima of a wave superimposes on maxima of another wave or minimum of a wave superimposes on minimum of another wave, intensity becomes maximum. For maxima path difference x = n? For minima path difference x = (2n+1)?/2 For interference pattern, in double slit experiment maxima will be found at a distance y from the central maximum , y = n?D/d D = distance between slit and screen d = separation of the slits. n = 1, 2, 3 … For minima y = (2n+1)?D/2d In diffraction minima is found by equation asin? = n? a = slit width For maxima the formula is a transcendental equation and not included in your syllabus.
Answers 6 Comments
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Dr Rajni J. describes herself as rajni cv. She conducts classes in BSc Tuition, Class 11 Tuition and Class 12 Tuition. Dr Rajni is located in Boharkawaloo, Kangra. Dr Rajni takes Regular Classes- at her Home and Online Classes- via online medium. She has 3 years of teaching experience . Dr Rajni has completed Doctor of Philosophy (Ph.D.) from BU Bhopal in 2010.

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